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The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.

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CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.2

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Mathematics ( Quantitative Aptitude) Trainer

Let the Base be = x cm then Altitude = (x-7) cm Since it is a right triangle, we can apply the Pythagorean theorem. x(x-12)+5(x-12)=0 (x-12)(x+5)=0 x=12 or x=-5 Since x is base which cannot be negative Hence x (base) = 12 cm and Altitude = 12-7 = 5 cm read more

Let the Base be = x cm

then Altitude = (x-7) cm

Since it is a right triangle, we can apply the Pythagorean theorem.

x(x-12)+5(x-12)=0

(x-12)(x+5)=0

x=12  or  x=-5

Since x is base which cannot be negative

Hence x (base) = 12 cm

and  Altitude = 12-7 = 5 cm

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5 Years Teaching Experience (Maths, Science, English)

Base is 12cm and altitude is 5cm. Use Pythagorus theorem.
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Tutor

Let, base be x. and altitude be (x - 7) a/q x2 + (x - 7)2 = (13)2, x2 + x2 - 14x + 49 - 169=0 x2 - 7x - 60= 0, x2 - 12x + 5x - 60 = 0 (x - 12)(x + 5)=0 x = 12 other two sides are 12 cm and 5cm.
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Passionate Teacher High patience and good listener.

X2 + (X-7)2 = 132 So the 2sides are 12cm and 5cm.
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5 Years Teaching Experience (Maths, Science, English)

Base side is 12cm and altitude is 5cm.
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Use pythagorus theorem, (base)2+(altitude)2= (hypotenuse)2 ans is base=12cm and altitude=5cm
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Engineering college, Assistant Professor, teaches Mathematics & Physics for more than 17 years

Base = x, altitude= x-7.. So, x2+(x-7)2= 169 Base = 12cm, altitude= 5cm ( Using Pythogorus theorem for right angled triangle)
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