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Let D be the mid point of BC. Coordinates of D ( 3 , 2) [ using mid-point formula ]
Using two point formula of straight line, we can find the equation of the median.
A (5 ,-4 ) and D (3 , 2) [ Formula used here is (y - y1 ) = [(y2 - y1)/(x2 - x1)] • (x - x1) ]
(y-5) = [ ( 2 + 4 )/( 3 - 5 ) ] • (x - 5)
( y - 5 ) =( 6 / -2 ) • ( x - 5 )
( y - 5 ) = -3 ( x - 5 )
y - 5 = -3 x + 15
y + 3x - 20 = 0.
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