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Class 10 > A solid toy is in the form of a hemisphere surmounted...
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A solid toy is in the form of a hemisphere surmounted by a right circular cone. The height of the cone is 4 cm and diameter of the base is 8 cm. Determine the volume of the toy. If the cube circumscribes the toy, then find the difference of the volumes of the cube and the toy. Also, find the total surface area of the toy.

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surface area=171.3cm² difference in volume=311cm³
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height of cone = 4cm ,radius of cone = 8/2 =4cm .. now volume of toy = volume of cone + volume of hemis phere .so total volume = 2/3 π r3 + 1/3 π r2 h = π r2 ( 2/3 r + 1/3 h ) = 22/7 × 4×4 (2/3 × 4 +1/3×4) = 22/7 × 16 (8/3 +4/3) = 22/7× 16...
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height of cone = 4cm ,radius of cone = 8/2 =4cm .. now volume of toy = volume of cone + volume of hemis phere .so total volume = 2/3π r3+ 1/3π r2h =π r2 ( 2/3 r + 1/3 h ) = 22/7 × 4×4 (2/3× 4 +1/3×4) = 22/7× 16 (8/3 +4/3) = 22/7× 16×4 = 22/7×64 cube cm . Curbed surface area of cone = π r l =π 4 √(h2+r2) =π×4√(16+16) = π4√ 32 =22/7× 16√2 surface area of toy =2π r2 +πrl . = 22/7× 2× 16 + 22/7×16√2 =22/7 ( 32 + 16√2) = 3.14× 54.56= 171.31 cm square' answer Difference of volume of cube and toy = 83 - 22/7× 64 = 512 - 201 = 311 cube cm answer read less
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