UrbanPro
Login Ask & Answer Success Stories Paid Courses Free Classes Tuition & Classes Fees Write a Review Help Center
Post your Learning Need Signup as a Tutor
✕

Popular Cities

Bangalore

Hyderabad

Delhi

Mumbai

Chennai

Pune

Kolkata

Gurgaon

Ahmedabad

Jaipur

Noida

✕
true

Class 11 Tuition > Class 11 Tuition in Chandigarh > Class 11 Tuition in Engg College > Amarjeet Singh

Amarjeet Singh Class 11 Tuition trainer in Chandigarh/>

Amarjeet Singh

locationImg Engg College, Chandigarh
2 yrs of Exp
Book a Free Demo
Book a Free Demo

Details verified of Amarjeet Singh✕

Identity

Education

Know how UrbanPro verifies Tutor details

Identity is verified based on matching the details uploaded by the Tutor with government databases.

Online Classes
Student's home
My experience of working with UNIPROFS has been phenomenal.since first day I feel really happy to help the young minds. As teaching has been something really close to my heart,from the time I really understand #ateacher.
I am pursuing B.Tech in mechanical engineering from the very renowned institute punjab engineering college chandigarh.
i have qualified jee mains and advance with all india rank of 36,000 and 12,600 respectively.
while my preparation i have understood the pros&cons and gained the invaluable experience.

Languages Spoken

Hindi Mother Tongue (Native)

English Basic

Education

PEC university of technology Pursuing

Bachelor of Technology (B.Tech.)

Address

Engg College, Chandigarh, India - 160012

Verified Info

Phone Verified

Email Verified

Report this Profile

✕
x

Is this listing inaccurate or duplicate? Any other problem?

Please tell us about the problem and we will fix it.

Please describe the problem that you see in this page.

Type the letters as shown below *

Please enter the letters as show below

Teaches

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

CBSE, State

Experience in School or College

i have taught students in coaching institutes for preparation of various competetive exams in the last 2 years.

Subjects taught

Mathematics, Chemistry

Taught in School or College

Yes

Reviews

No Reviews yet!

Answers by Amarjeet Singh

Answered on 08/06/2020

Ask a Question

Post a Lesson

<p>5(X^2+Y^2+Z^2)=4(XY+YZ+ZX) then find X:Y:Z</p>

Solving the above equation: Sum of squares will be zero only if each individual number is zero; Therefore we have: 2x=y, 2y=z, 2z=x x:y:z = x/x :y/x :z/x. = 1:2:1/2 therefore x:y:z = 2:4:1 ...more

Solving the above equation:

Sum of squares will be zero only if each individual number is zero;

Therefore we have: 2x=y, 2y=z, 2z=x

x:y:z = x/x :y/x :z/x.

        = 1:2:1/2

 therefore x:y:z = 2:4:1

Answers 353 Comments
Dislike Bookmark
x

Ask a Question

Please enter your Question

Please select a Tag

Book a Demo

Recomended Profiles

Find Qualified Tutors on UrbanPro for School Tuitions in all subjects

Left
Gopal Lal Jat photo

Gopal Lal...

New Tutor

Chandigarh
Aahan Kumar photo

Aahan Kumar...

New Tutor

Chandigarh
Pooja P. photo

Pooja P....

New Tutor

Chandigarh
Naveen Kumar photo

Naveen Kumar...

New Tutor

Chandigarh
Shivam Mishra photo

Shivam Mishra...

New Tutor

Chandigarh
Tanisha M. photo

Tanisha M....

New Tutor

Chandigarh
Jeevan J. photo

Jeevan J....

New Tutor

Chandigarh
Rahul Kumar photo

Rahul Kumar...

New Tutor

Chandigarh
Shubham Dalia photo

Shubham Dalia...

New Tutor

Chandigarh
Yuvraj photo

Yuvraj

New Tutor

Chandigarh
Right
Find Now

Also have a look at

Learn More

Teaches

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

CBSE, State

Experience in School or College

i have taught students in coaching institutes for preparation of various competetive exams in the last 2 years.

Subjects taught

Mathematics, Chemistry

Taught in School or College

Yes

No Reviews yet!

Answers by Amarjeet Singh

Answered on 08/06/2020

Ask a Question

Post a Lesson

<p>5(X^2+Y^2+Z^2)=4(XY+YZ+ZX) then find X:Y:Z</p>

Solving the above equation: Sum of squares will be zero only if each individual number is zero; Therefore we have: 2x=y, 2y=z, 2z=x x:y:z = x/x :y/x :z/x. = 1:2:1/2 therefore x:y:z = 2:4:1 ...more

Solving the above equation:

Sum of squares will be zero only if each individual number is zero;

Therefore we have: 2x=y, 2y=z, 2z=x

x:y:z = x/x :y/x :z/x.

        = 1:2:1/2

 therefore x:y:z = 2:4:1

Answers 353 Comments
Dislike Bookmark
x

Ask a Question

Please enter your Question

Please select a Tag

Book a Demo

  • Want to learn from Amarjeet Singh?

  • Book a Demo
X

Reply to 's review

Enter your reply*

1500/1500

Please enter your reply

Your reply should contain a minimum of 10 characters

Your reply has been successfully submitted.

✕

Certified

The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.

✕

Different batches available for this Course

Book a Free Demo

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more

ThinkVidya Learning Pvt Ltd © 2010-2026 All Rights Reserved