Will the expression *p = p be disallowed by the compiler?

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Sharath Gajawada

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No, Because, here even though the value of p is accessed twice it is used to modify two different objects p and *p. i.e. let us take the value of p as 5, the address where p is stored at 100 location. now statement *p=p will override the value 200 with 5 i.e. P location is shifted from 100 to 5.
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Thanks for the question Atharva, No because even though the value of p is accessed twice it is used to modify two different objects p and *p. Thanks, Team DishaaPro www.dishaapro.com
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Compiler should disallow or at the least warn you, As no types were mentioned and given you are de-referencing using *p so presuming p is a pointer, For sake of simplicity, presume p is of type int* ie: int *p; then in statement below, lhs is of type int and rhs is of type int*, you shouldn't ...
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Compiler should disallow or at the least warn you, As no types were mentioned and given you are de-referencing using *p so presuming p is a pointer, For sake of simplicity, presume p is of type int* ie: int *p; then in statement below, lhs is of type int and rhs is of type int*, you shouldn't assign int* to an int. *p = p If you really want to do that (hope you understand what you are doing with your memory), then you should force typecast it to (int*), so that compiler doesn't generate a warning. Team SG-Tech.in read less
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