How to write a C program to print the series 1,9,17, 33,49,73,97?

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Rajan Maheshwari

iOS Trainer and Developer, C++, Advanced C++, C, Core Java Trainer

The series is like adding 8 * x for two numbers and then incrementing x by 1 so that 8 is doubled. 1, (1+8*1) 9, (9+8*1) 17, (17+ 8 * 2) 33, (33 + 8 * 2) 49 and so on. So it will be like: int main() { // Series to print: 1,9,17, 33,49,73,97..... int multiplier = 8; int...
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The series is like adding 8 * x for two numbers and then incrementing x by 1 so that 8 is doubled. 1, (1+8*1) 9, (9+8*1) 17, (17+ 8 * 2) 33, (33 + 8 * 2) 49 and so on. So it will be like: int main() { // Series to print: 1,9,17, 33,49,73,97..... int multiplier = 8; int reset = 0; int seriesNumber = 1; int limit = 0; printf("Print the limit of series = "); scanf("%d",&limit); printf("%d",seriesNumber); for(int i=1;i= 2) { multiplier += 8; reset = 1; } else { reset++; } seriesNumber += multiplier; printf(", %d",seriesNumber); } return 0; } I am sure the code can be improved too. Output is attached. read less
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1, (1+8*1) 9, (9+8*1) 17, (17+ 8 * 2) 33, (33 + 8 * 2) 49 and so on.
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#include "stdio.h" int main(void) { int i=0,j=1, sum=1; while(sum lessthan 200){ i++; printf("%d\n",sum); sum = sum + (8*j); if(i == 2){ i=0; j=j+1; } } return 0; } Please use lessthan symbol in loop condition as this input does not accepts html tag symbols.
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