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C Language > Learn C Language > how the right shift operator works on a numerical value??...
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how the right shift operator works on a numerical value?? eg:- 8>>3=?

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One-to-One Computer & Programming Coaching | 14+ Years of Excellence

Binary of 8 is "1000" and here by this command 3 bits of "1000" will be shifted to right. Hence Binary will be "0001" so your expressions answer will be "0001" i.e. 1
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Enthusiastic Learner and Teacher

8 in binary is 1000 You're shifting it by 3 times After first shift 0100 After second shift 0010 After Third shift 0001 So you'll be left with 8>>3=1 To make it simple, every time you shift right your number gets divided by 2 and every time you shift left your number gets multiplied by 2.
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first convert numerical value to binary value then arrange into bits and shift 3 bit on right then convert binary value to decimal value.
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C++, Data Structures, Software Engineering working professional.

This is bitwise operator, forget about the numeric value, You will have to think in terms of sequence of bits, Just write down these two numbers in bits, and start moving the bits,
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Expert Technical Trainer with 15 years of work experience

The decimal value need to converted to equivalent binary values and then shift right operation is performed
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After converting the numerical value into binary value right shift operator starts its working.
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Computer and Photography Instructor

its a Shift operator and its shifted 3 times in right onwards. all in bit wise. (1000)2 in binary form. after shifting 3 position on rightwords the value is (0001)2 in Decimal value is 1
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MCA

This operator shifts the first operand the specified number of bits to the right. Excess bits shifted off to the right are discarded. Copies of the leftmost bit are shifted in from the left
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Master of Computer Applications (M.C.A)

In C right shift works like this .... it divides the 8 by the 2 power of 3...
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Computer Wizard

It's right shift bitwise operator 1) data shifted by specificed number of position to right. 2)when data shifted right ,leading zero's are filled with zero .and it's binary operator ( means it require two argument s)
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