How do I write a simple code in C for SJF scheduling non preemptive?

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declare array and read jobs time in that. search the array for smallest cpu burst time and find the index and add
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#include stdio.h #include stdlib.h void sort(int,int); int main() { int bt,wt,n,i,sum,x,avg; float p; sum=0; printf("\nenter the number of processes:"); scanf("%d",&n); for(i=0;ibt) { temp=bt; bt=bt; bt=temp; } } } }
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#include stdio.h #include stdlib.h void sort(int[],int); int main() { int bt[10],wt[10],n,i,sum,x,avg; float p[5]; sum=0; printf("\nenter the number of processes:"); scanf("%d",&n); for(i=0;ibt[j+1]) { temp=bt[j]; bt[j]=bt[j+1]; bt[j+1]=temp; } } } } read less
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A simple priority queue will do the job. You can define each node in the queue to hold the task as well as the priority level. Enqueueing will be no different that regular queues and will happen at the rear. Dequeueing however, will not always take place at the front but will rather happen to the...
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A simple priority queue will do the job. You can define each node in the queue to hold the task as well as the priority level. Enqueueing will be no different that regular queues and will happen at the rear. Dequeueing however, will not always take place at the front but will rather happen to the node with least priority level in the queue, regardless of location. Have a look at priority queues, learn what they are and have fun implementing them. I assure you, it’s easy to do and you learn a lot! Round Robin Scheduling Each process is provided a fix time to execute called quantum. Once a process is executed for given time period. Process is preempted and other process executes for given time period. Context switching is used to save states of preempted processes. See below attached image1 for your reference. CODE: #include "stdio.h" main() { int n; printf("Enter the no. of processes: "); scanf("%d",&n); int id[n],bt[n],rt[n],wt[n],tat[n],st[n],ft[n],q,i,time=0,btsum=0; for(i=0;iq) { time+=q; bt[i]-=q; wt[i]=wt[i]+st[i]-ft[i]; ft[i]=time; } else if(bt[i]<=q && bt[i]!=0) { time+=bt[i]; wt[i]=wt[i]+st[i]-ft[i]; bt[i]=0; } } for(i=0;iread less
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