How do I write a C program to print the total number of a single-digit prime number using a loop?

We can solve it in two ways 1st Way: ''''''''''''''' It's easy, prime number means it should not be divisible by any number itself and 1. The basic logic dictates that we divide and check each number by numbers of half the value of the number we are checking. confused? here's an example. if we are checking number n (say) for prime, then we run the loop from 2 to n/2! since here we are only checking for single digits , our n has values from 1 to 9. Below is the Code: //assuming all variables declared and all header files included for ( int i = 1; i<=9;i++){ flag = 0; //to check for divisibility for ( int j= 2; j<=i/2;j++){ if (i%j==0){ flag++; // value changes if divisible } } if ( flag==0){ // check for change of value printf("%d",i); } } 2nd Way: ''''''''''''''' for(int i=2; i<=9; i++) { int count=0; for(int j=2;j<=sqrt(i);j++) { if(i%j==0) { count++; break; } } if(count==0) cout<read less