How do I take an input of 10^9 in C?

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Predefined function pow() which is in maths.h is the best for it. But it can be also be done using a loops. The inside definition of pow() function is same as we do using loops :) Method 1(using pow()): Its one of the easiest way to do. void main() { int num,pow,p=1; printf(“Enter the...
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Predefined function pow() which is in maths.h is the best for it. But it can be also be done using a loops. The inside definition of pow() function is same as we do using loops :) Method 1(using pow()): Its one of the easiest way to do. void main() { int num,pow,p=1; printf(“Enter the number: ”); scanf(“%d”,&num); printf(“Enter it’s power: “); scanf(“%d”,&pow); p=pow(num,pow) printf("Result is %d",p); getch(); } Method 2(using for loop) : void main() { int num,pow,i,p=1; printf(“Enter the number: ”); scanf(“%d”,&num); printf(“Enter it’s power: “); scanf(“%d”,&pow); for(i=0;iread less
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See.. for n<=10^9. Use "int". As its range is from -2^31 to +2^31. Around ~10^9. But in case of n~10^18. "int" wont work. So use "long long int". And range can further be increased for 0 read more
See.. for n<=10^9. Use "int". As its range is from -2^31 to +2^31. Around ~10^9. But in case of n~10^18. "int" wont work. So use "long long int". And range can further be increased for 0read less
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Take power and base as input using power predefined function
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