How do I solve the equation 3^x+4^x=5^x in C?

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Sharath Kumar Sadar

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#include <stdio.h>#include <math.h>int main(){int x,n, sum1 =0, sum2=0;printf("Enter the upper range value: \n");scanf("%d",&n);if (n>=1){ for(x=1;x<=n;x++) { sum1 = pow(3,x) + pow(4,x); sum2 = pow(5,x); if ((sum1==sum2) && (sum1 >0) &&...
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#include <stdio.h>#include <math.h>int main(){int x,n, sum1 =0, sum2=0;printf("Enter the upper range value: \n");scanf("%d",&n);if (n>=1){ for(x=1;x<=n;x++) { sum1 = pow(3,x) + pow(4,x); sum2 = pow(5,x); if ((sum1==sum2) && (sum1 >0) && (sum2 >0)) printf("The feasible x value is %d, 3^%d+4^%d = %d, 5^%d = %d \n",x,x,x,sum1,x,sum2); } return 0;}elseprintf("Please enter value greater than or equal to 1");} read less
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