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How do I print a list of descending numbers in C in a square shape?

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int n,i,j; n = d*d; for(i=0;i
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it will take two loops, firstly decide the dimension of the square i.e 3*3 or 4*4 etc if it is 3*3 then the number will start from 9 and if it is 4*4 then the number will start from 16 then 15 etc. Which means you can take the dimension from the user and run the first loop up till that dimension after... read more
it will take two loops, firstly decide the dimension of the square i.e 3*3 or 4*4 etc if it is 3*3 then the number will start from 9 and if it is 4*4 then the number will start from 16 then 15 etc. Which means you can take the dimension from the user and run the first loop up till that dimension after that in the next loop print the number up till that dimension, which means your inner loop will also run the number of time the dimension is given. e.g. int outer,inner,dimension,value; now take dimension value from user then value = dimension * dimension ; after that run two loop. or you can do in inside one loop also. take the dimension value = dimension * dimension; value2 = dimension * (dimension + 1); then take one more variable count =0; then for(outer = 0;outer < value2 ; outer++){ count++; if(count == 3){ change the line; continue; count =0; }else{ print(the value) value --; and change the line; } } fine any doubt let me know if I am wrong also. read less
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read elements in array and sort them . then depending on no of elements , use the method to print like a matrix
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