Babu Varghese

Btm Layout 2nd Stage, Bangalore, India - 560076

Babu Varghese photo

Babu Varghese

Tutor

Btm Layout 2nd Stage, Bangalore, India - 560076.

3 Students taught

5.0

UrbanPro Rating

Details verified of Babu Varghese

Identity

Education

Know how UrbanPro verifies Tutor details

Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

I am M Sc Computer Science Degree holder from Cochin University of Science and Technology with 18+ years in IT industry, worked with DRDO and reputed MNCs such as Tektronix and Hewlett-Packard.
Worked with Educational Initiatives to develop Maths content of their flagship product, ASSET across grades 2 to 10. Currently working with funtoot, leading the content development for Maths and Science for grades 2 to 9.
Familiar with content structure and coverage for all grades 2 to 12 across curriculum boards, CBSE, ICSE, State boards, IGCSE and IB.
I have taught students Maths 9th, 10th IGCSE and CBSE boards. Currently teaching 11th Maths for IB board, 11th Physics for CBSE and ICSE boards.
I am passionate about learning through teaching.

Languages Spoken

Malayalam

Hindi

English

Education

Calicut University 1988

Bachelor of Science (B.Sc.)

Cochin University of Science and Technology 1991

Master of Science (M.Sc.)

Address

Btm Layout 2nd Stage, Bangalore, India - 560076

Verified Info

ID Verified

Education Verified

Phone Verified

Email Verified

Facebook Verified

Demo Class

Yes, not charged

Report this Profile

Is this listing inaccurate or duplicate? Any other problem?

Please tell us about the problem and we will fix it.

Please describe the problem that you see in this page.

Type the letters as shown below *

Please enter the letters as show below

Class 12 Tuition Overview

Class 12 Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 12 Tuition

5

Board

International Baccalaureate, ISC/ICSE, CBSE, State, IGCSE

IB Subjects taught

Physics, Mathematics

ISC/ICSE Subjects taught

Mathematics, Physics

CBSE Subjects taught

Physics, Mathematics

IGCSE Subjects taught

Mathematics, Physics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Physics

Teaching Experience in detail in Class 12 Tuition

GOOD

Reviews

this is test message this is test message this is test message this is test message this is test message this is test message this is test message

No Reviews yet! Be the first one to Review

Answers by Babu Varghese (9)

Answered on 12/02/2018 CBSE/Class 9/Science Tuition/Class IX-X Tuition

Here is a convenient formula that helps us find an answer to this question. v^2 = u^2 + 2aS, where "v" is the final velocity, "u" is the initial velocity, "a" is the acceleration, "S" is the distance travelled. In this case, v = 0, a = -g (acceleration due to gravity), S = h (height). Thus we get, u^2... ...more

Here is a convenient formula that helps us find an answer to this question. v^2 = u^2 + 2aS, where "v" is the final velocity, "u" is the initial velocity, "a" is the acceleration, "S" is the distance travelled. In this case, v = 0, a = -g (acceleration due to gravity), S = h (height). Thus we get, u^2 = 2gh, knowing "u', h can be calculated. Note that the calculation of height is independent of the mass of the object. The height depends on the velocity with which the object is projected upwards. Thus both objects reach the same height.

Answers 6 Comments
Dislike Bookmark

Answered on 12/02/2018 CBSE/Class 9/Science Tuition/Class IX-X Tuition

Out of the four physical quantities associated with the motion of an object viz, Force, Velocity, Acceleration... ...more
Out of the four physical quantities associated with the motion of an object viz, Force, Velocity, Acceleration and momentum which one remains constant for all bodies large or small, undergoing free fall?

Freefall is when the body falls freely under the gravity and we assume, resistance due to the air is negligible. The acceleration on the body is constant and Force on the body is "mg", where "m" is the mass of the body and "g" is the acceleration due to gravity. Since "m" is constant for the given... ...more
Freefall is when the body falls freely under the gravity and we assume, resistance due to the air is negligible. The acceleration on the body is constant and Force on the body is "mg", where "m" is the mass of the body and "g" is the acceleration due to gravity. Since "m" is constant for the given body, the force is also constant. Momentum and acceleration are of course will not be constant when the net force acting on the body is not zero as in the case of free fall.
Answers 2 Comments
Dislike Bookmark

Answered on 12/02/2018 CBSE/Class 9/Science Tuition/Class IX-X Tuition

When the state of matter (solid -> liquid, liquid-> vapour, vapour -> liquid, liquid -> solid) does not change all of a sudden as the soon its transition temperature is reached. So what happens to a block of ice kept at room temperature (say at 27-degree Celsius ). The molecules in the liquid... ...more

When the state of matter (solid -> liquid, liquid-> vapour, vapour -> liquid, liquid -> solid) does not change all of a sudden as the soon its transition temperature is reached. So what happens to a block of ice kept at room temperature (say at 27-degree Celsius ). The molecules in the liquid state of matter will have a higher internal energy as compared when the matter is in the solid state. The melting point is the temperature at which the solid transitioned into liquid. The heat supplied is fully utilised to convert the solid into the liquid state at the melting point of the solid. Thus its temperature does not rise.

Answers 4 Comments
Dislike Bookmark

Answered on 12/02/2018 CBSE/Class 9/Science Tuition/Class IX-X Tuition

Why Newton's first law of Motion is known as the law of inertia?

Any object that has a mass also have inertia. The inertia of a body is its resistance to change its state, whether it is the state of rest or the state of motion. Newton's 1st law describes the behaviour of a body to continue its state of rest or state of the motion unless acted upon by an external... ...more
Any object that has a mass also have inertia. The inertia of a body is its resistance to change its state, whether it is the state of rest or the state of motion. Newton's 1st law describes the behaviour of a body to continue its state of rest or state of the motion unless acted upon by an external force. It is clear that newtons first law describes the inertia of the object, therefore it is also known as the law of inertia.
Answers 2 Comments
Dislike Bookmark

Answered on 12/02/2018 CBSE/Class 9/Science Tuition/Class IX-X Tuition

Uniform circular motion describes an object moves along a circular path at constant speed. The velocity of the object any point on the circular path is directed along the tangent. Therefore its velocity change continuously (though its speed is constant). The change in velocity is possible only when... ...more
Uniform circular motion describes an object moves along a circular path at constant speed. The velocity of the object any point on the circular path is directed along the tangent. Therefore its velocity change continuously (though its speed is constant). The change in velocity is possible only when there is the force acting on the object making it move along the curved path. This force is directed towards the centre of the circular path, along which the object moves. This force is referred as centripetal force. A stone tied to the string and swung in circles is an example of uniform circular motion, provided its speed is kept constant. A car going along a curve is another example.
Answers 7 Comments
Dislike Bookmark

Babu VargheseDirections

x
Class 12 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 12 Tuition

5

Board

International Baccalaureate, ISC/ICSE, CBSE, State, IGCSE

IB Subjects taught

Physics, Mathematics

ISC/ICSE Subjects taught

Mathematics, Physics

CBSE Subjects taught

Physics, Mathematics

IGCSE Subjects taught

Mathematics, Physics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Physics

Teaching Experience in detail in Class 12 Tuition

GOOD

Class 11 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

5

Board

International Baccalaureate, ISC/ICSE, CBSE, State, IGCSE

IB Subjects taught

Physics, Mathematics

ISC/ICSE Subjects taught

Mathematics, Physics

CBSE Subjects taught

Physics, Mathematics

IGCSE Subjects taught

Mathematics, Physics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Physics

Teaching Experience in detail in Class 11 Tuition

I stay in BTM 2nd Stage, would like to assist you to learn the subject. At grade 10 I teach Maths and Physics. At 11 and 12 levels, I teach Physics (Tuitions). I have an experience of 7+ years in teaching, creating and publishing questions and videos. I teach across curriculum boards, State Syllabus, ICSE, CBSE, IGCSE (Cambridge), IB (10+1, 10+2) I have in all, 25+ years working experience, as a Scientist in DRDO, Engineer in MNCs (Tektronix, Hughes, HP etc). In past 7 years, I am working in education, 2 years in the content team in Educational Initiatives (creators of - ASSET/Mindspark) and currently content head in funtoot (Another company leads in Maths/Science contents). My teaching style is thoroughly concept based making the classes engaging and interesting to the student, letting them the question the assumptions and learn through dialogues. The classes can be conducted face-to-face or on-line.

Class 10 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

7

Board

IGCSE, CBSE

CBSE Subjects taught

Mathematics, Science

IGCSE Subjects taught

Mathematics, Physics

Taught in School or College

No

Teaching Experience in detail in Class 10 Tuition

GOOD

Class 9 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 9 Tuition

7

Board

IGCSE, CBSE

CBSE Subjects taught

Mathematics, Science

IGCSE Subjects taught

Mathematics, Physics

Taught in School or College

No

Teaching Experience in detail in Class 9 Tuition

This is in response to your requirement for tuitions for grade 9 Maths, in Urban Pro. I stay in BTM 2nd Stage, would like to assist you to learn the subject. At grade 10 I teach Maths and Physics. At 11 and 12 levels, I teach Physics (Tuitions). I have an experience of 7+ years in teaching, creating and publishing questions and videos. I teach across curriculum boards, State Syllabus, ICSE, CBSE, IGCSE (Cambridge), IB (10+1, 10+2) I have in all, 25+ years working experience, as a Scientist in DRDO, Engineer in MNCs (Tektronix, Hughes, HP etc). In past 7 years, I am working in education, 2 years in the content team in Educational Initiatives (creators of - ASSET/Mindspark) and currently content head in funtoot (Another company leads in Maths/Science contents). My teaching style is thoroughly concept based making the classes engaging and interesting to the student, letting them the question the assumptions and learn through dialogues. The classes can be conducted face-to-face or on-line.

this is test message this is test message this is test message this is test message this is test message this is test message this is test message

No Reviews yet! Be the first one to Review

Answers by Babu Varghese (9)

Answered on 12/02/2018 CBSE/Class 9/Science Tuition/Class IX-X Tuition

Here is a convenient formula that helps us find an answer to this question. v^2 = u^2 + 2aS, where "v" is the final velocity, "u" is the initial velocity, "a" is the acceleration, "S" is the distance travelled. In this case, v = 0, a = -g (acceleration due to gravity), S = h (height). Thus we get, u^2... ...more

Here is a convenient formula that helps us find an answer to this question. v^2 = u^2 + 2aS, where "v" is the final velocity, "u" is the initial velocity, "a" is the acceleration, "S" is the distance travelled. In this case, v = 0, a = -g (acceleration due to gravity), S = h (height). Thus we get, u^2 = 2gh, knowing "u', h can be calculated. Note that the calculation of height is independent of the mass of the object. The height depends on the velocity with which the object is projected upwards. Thus both objects reach the same height.

Answers 6 Comments
Dislike Bookmark

Answered on 12/02/2018 CBSE/Class 9/Science Tuition/Class IX-X Tuition

Out of the four physical quantities associated with the motion of an object viz, Force, Velocity, Acceleration... ...more
Out of the four physical quantities associated with the motion of an object viz, Force, Velocity, Acceleration and momentum which one remains constant for all bodies large or small, undergoing free fall?

Freefall is when the body falls freely under the gravity and we assume, resistance due to the air is negligible. The acceleration on the body is constant and Force on the body is "mg", where "m" is the mass of the body and "g" is the acceleration due to gravity. Since "m" is constant for the given... ...more
Freefall is when the body falls freely under the gravity and we assume, resistance due to the air is negligible. The acceleration on the body is constant and Force on the body is "mg", where "m" is the mass of the body and "g" is the acceleration due to gravity. Since "m" is constant for the given body, the force is also constant. Momentum and acceleration are of course will not be constant when the net force acting on the body is not zero as in the case of free fall.
Answers 2 Comments
Dislike Bookmark

Answered on 12/02/2018 CBSE/Class 9/Science Tuition/Class IX-X Tuition

When the state of matter (solid -> liquid, liquid-> vapour, vapour -> liquid, liquid -> solid) does not change all of a sudden as the soon its transition temperature is reached. So what happens to a block of ice kept at room temperature (say at 27-degree Celsius ). The molecules in the liquid... ...more

When the state of matter (solid -> liquid, liquid-> vapour, vapour -> liquid, liquid -> solid) does not change all of a sudden as the soon its transition temperature is reached. So what happens to a block of ice kept at room temperature (say at 27-degree Celsius ). The molecules in the liquid state of matter will have a higher internal energy as compared when the matter is in the solid state. The melting point is the temperature at which the solid transitioned into liquid. The heat supplied is fully utilised to convert the solid into the liquid state at the melting point of the solid. Thus its temperature does not rise.

Answers 4 Comments
Dislike Bookmark

Answered on 12/02/2018 CBSE/Class 9/Science Tuition/Class IX-X Tuition

Why Newton's first law of Motion is known as the law of inertia?

Any object that has a mass also have inertia. The inertia of a body is its resistance to change its state, whether it is the state of rest or the state of motion. Newton's 1st law describes the behaviour of a body to continue its state of rest or state of the motion unless acted upon by an external... ...more
Any object that has a mass also have inertia. The inertia of a body is its resistance to change its state, whether it is the state of rest or the state of motion. Newton's 1st law describes the behaviour of a body to continue its state of rest or state of the motion unless acted upon by an external force. It is clear that newtons first law describes the inertia of the object, therefore it is also known as the law of inertia.
Answers 2 Comments
Dislike Bookmark

Answered on 12/02/2018 CBSE/Class 9/Science Tuition/Class IX-X Tuition

Uniform circular motion describes an object moves along a circular path at constant speed. The velocity of the object any point on the circular path is directed along the tangent. Therefore its velocity change continuously (though its speed is constant). The change in velocity is possible only when... ...more
Uniform circular motion describes an object moves along a circular path at constant speed. The velocity of the object any point on the circular path is directed along the tangent. Therefore its velocity change continuously (though its speed is constant). The change in velocity is possible only when there is the force acting on the object making it move along the curved path. This force is directed towards the centre of the circular path, along which the object moves. This force is referred as centripetal force. A stone tied to the string and swung in circles is an example of uniform circular motion, provided its speed is kept constant. A car going along a curve is another example.
Answers 7 Comments
Dislike Bookmark

Enquire

Load More

Babu Varghese describes himself as Tutor. He conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Babu is located in Btm Layout 2nd Stage, Bangalore. Babu takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 20 years of teaching experience . Babu has completed Bachelor of Science (B.Sc.) from Calicut University in 1988 and Master of Science (M.Sc.) from Cochin University of Science and Technology in 1991. HeĀ is well versed in Malayalam, Hindi and English.

X

Post your Learning Need

Let us shortlist and give the best tutors and institutes.

or

Send Enquiry to Babu Varghese

Let Babu Varghese know you are interested in their class

Reply to 's review

Enter your reply*

1500/1500

Please enter your reply

Your reply should contain a minimum of 10 characters

Your reply has been successfully submitted.

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 25 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 6.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more