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Varghese Babu Class 12 Tuition trainer in Bangalore

Varghese Babu

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experience 11 yrs of Exp
students 3 students
locationImg Btm Layout 2nd Stage, Bangalore
rsIcon 450 per hour
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Varghese Babu - Teacher - Mathematics and Physics (Grades 9 through 12)

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With over ten years of experience in the field, I have developed a deep understanding and passion for teaching. After completing my post-graduation, I realised that teaching was not just a profession for me but a true calling.
I find immense joy and fulfilment in helping students grasp complex concepts and develop a strong foundation in these subjects.I aim to ignite their curiosity and instil a lifelong love for learning. My expertise lies in teaching Mathematics and Physics to students from classes ninth to twelfth.
Throughout my career, I have taught in various settings, including offline and online platforms, and provided home tuition. I believe in adapting to the unique needs of each student and providing them with a comfortable learning environment. By creating a personalised lesson plan tailored to their requirements, I aim to optimise their learning experience. I strive to make the learning process engaging and interactive during my classes. I utilise visual aids, including PowerPoint presentations, to enhance comprehension and facilitate a deeper understanding of the topics. This multimedia approach helps students to connect theoretical concepts with real-life examples, making the learning experience more relatable and enjoyable.
In addition to the course curriculum, I have developed my question material to supplement students' learning. By practising with these materials, students can gain confidence in their problem-solving skills and improve their overall performance. My teaching philosophy revolves around creating a stimulating learning environment where students can thrive academically.

Languages Spoken

Malayalam

Hindi

English

Education

Calicut University 1988

Bachelor of Science (B.Sc.)

Cochin University of Science and Technology 1991

Master of Science (M.Sc.)

Address

Btm Layout 2nd Stage, Bangalore, India - 560076

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Teaches

Class 12 Tuition
1 Student

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

11

Board

NIOS, ISC/ICSE, CBSE, International Baccalaureate, State

Preferred class strength

One on one/ Private Tutions

Subjects taught

Physics

Taught in School or College

No

Teaching Experience in detail in Class 12 Tuition

Good.

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

11

Board

ISC/ICSE, CBSE, International Baccalaureate, State

Preferred class strength

One on one/ Private Tutions

Subjects taught

Physics

Taught in School or College

No

Teaching Experience in detail in Class 11 Tuition

I stay in BTM 2nd Stage and would like to assist you in learning the subject. At grade 10, I teach Maths and Physics. At 11 and 12 levels, I teach Physics (Tuitions). I have 7+ years of experience in teaching, creating, and publishing questions and videos. I teach across curriculum boards: State Syllabus, ICSE, CBSE, IGCSE (Cambridge), and IB (10+1, 10+2). I have a total of 25+ years of working experience as a Scientist in DRDO and as an Engineer in MNCs (Tektronix, Hughes, HP, etc.). In the past 7 years, I have been working in education: 2 years in the content team at Educational Initiatives (creators of ASSET/Mindspark) and currently as a Content Head at Funtoot (a leading company in Maths/Science content). My teaching style is thoroughly concept-based, making the classes engaging and interesting for the student, allowing them to question assumptions and learn through dialogue. The classes can be conducted face-to-face or online.

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

11

Board

CBSE, ICSE, IGCSE, State, International Baccalaureate, NIOS

Preferred class strength

One on one/ Private Tutions, Group Classes

Experience in School or College

Have been teaching Mathematics for 9 and 10 for the last 6 years. Have taught the subject under various boards such as CBSE, ICSE, State Syllabuses.

Subjects taught

Mathematics

Taught in School or College

Yes

Teaching Experience in detail in Class 10 Tuition

A lot of students struggle with concepts and numerical skills. Lack of practice make them fall behind. I take care of students who are can learn under care. These students are generally shy asking questions in the class. I support both student centric and teacher centric teaching so that classes outcome is ensured for different type of learners

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

11

Board

CBSE, ICSE, IGCSE, NIOS, International Baccalaureate

Preferred class strength

One on one/ Private Tutions, Group Classes

Subjects taught

Mathematics, Science

Taught in School or College

No

Teaching Experience in detail in Class 9 Tuition

This is in response to your requirement for tuitions for grade 9 Maths on UrbanPro. I stay in BTM 2nd Stage and would like to assist you in learning the subject. At grade 10, I teach Maths and Physics. At 11th and 12th levels, I teach Physics. I have an experience of 7+ years in teaching, creating and publishing questions and videos. I teach across curriculum boards: State Syllabus, ICSE, CBSE, IGCSE (Cambridge), and IB (10+1, 10+2). I have, in all, 25+ years of working experience as a Scientist in DRDO and as an Engineer in MNCs (Tektronix, Hughes, HP, etc.). In the past 7 years, I have been working in education, including 2 years in the content team at Educational Initiatives (creators of ASSET/Mindspark) and currently as content head at funtoot (a company that leads in Maths/Science content). My teaching style is thoroughly concept-based, making the classes engaging and interesting to the student, letting them question assumptions and learn through dialogue. The classes can be conducted face-to-face or online.

Reviews

No Reviews yet!

Answers by Varghese Babu

Answered on 12/02/2018 Learn CBSE - Class 9/Science +1 Tuition/Class IX-X Tuition

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Here is a convenient formula that helps us find an answer to this question. v^2 = u^2 + 2aS, where "v" is the final velocity, "u" is the initial velocity, "a" is the acceleration, "S" is the distance travelled. In this case, v = 0, a = -g (acceleration due to gravity), S = h (height). Thus we get, u^2... ...more

Here is a convenient formula that helps us find an answer to this question. v^2 = u^2 + 2aS, where "v" is the final velocity, "u" is the initial velocity, "a" is the acceleration, "S" is the distance travelled. In this case, v = 0, a = -g (acceleration due to gravity), S = h (height). Thus we get, u^2 = 2gh, knowing "u', h can be calculated. Note that the calculation of height is independent of the mass of the object. The height depends on the velocity with which the object is projected upwards. Thus both objects reach the same height.

Answer Answers 6 Comments Comments
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Answered on 12/02/2018 Learn CBSE - Class 9/Science +1 Tuition/Class IX-X Tuition

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Freefall is when the body falls freely under the gravity and we assume, resistance due to the air is negligible. The acceleration on the body is constant and Force on the body is "mg", where "m" is the mass of the body and "g" is the acceleration due to gravity. Since "m" is constant for the given... ...more
Freefall is when the body falls freely under the gravity and we assume, resistance due to the air is negligible. The acceleration on the body is constant and Force on the body is "mg", where "m" is the mass of the body and "g" is the acceleration due to gravity. Since "m" is constant for the given body, the force is also constant. Momentum and acceleration are of course will not be constant when the net force acting on the body is not zero as in the case of free fall.
Answer Answers 2 Comments Comments
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Answered on 12/02/2018 Learn CBSE - Class 9/Science +1 Tuition/Class IX-X Tuition

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When the state of matter (solid -> liquid, liquid-> vapour, vapour -> liquid, liquid -> solid) does not change all of a sudden as the soon its transition temperature is reached. So what happens to a block of ice kept at room temperature (say at 27-degree Celsius ). The molecules in the liquid... ...more

When the state of matter (solid -> liquid, liquid-> vapour, vapour -> liquid, liquid -> solid) does not change all of a sudden as the soon its transition temperature is reached. So what happens to a block of ice kept at room temperature (say at 27-degree Celsius ). The molecules in the liquid state of matter will have a higher internal energy as compared when the matter is in the solid state. The melting point is the temperature at which the solid transitioned into liquid. The heat supplied is fully utilised to convert the solid into the liquid state at the melting point of the solid. Thus its temperature does not rise.

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Answered on 12/02/2018 Learn CBSE - Class 9/Science +1 Tuition/Class IX-X Tuition

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Any object that has a mass also have inertia. The inertia of a body is its resistance to change its state, whether it is the state of rest or the state of motion. Newton's 1st law describes the behaviour of a body to continue its state of rest or state of the motion unless acted upon by an external... ...more
Any object that has a mass also have inertia. The inertia of a body is its resistance to change its state, whether it is the state of rest or the state of motion. Newton's 1st law describes the behaviour of a body to continue its state of rest or state of the motion unless acted upon by an external force. It is clear that newtons first law describes the inertia of the object, therefore it is also known as the law of inertia.
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Answered on 12/02/2018 Learn CBSE - Class 9/Science +1 Tuition/Class IX-X Tuition

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Uniform circular motion describes an object moves along a circular path at constant speed. The velocity of the object any point on the circular path is directed along the tangent. Therefore its velocity change continuously (though its speed is constant). The change in velocity is possible only when... ...more
Uniform circular motion describes an object moves along a circular path at constant speed. The velocity of the object any point on the circular path is directed along the tangent. Therefore its velocity change continuously (though its speed is constant). The change in velocity is possible only when there is the force acting on the object making it move along the curved path. This force is directed towards the centre of the circular path, along which the object moves. This force is referred as centripetal force. A stone tied to the string and swung in circles is an example of uniform circular motion, provided its speed is kept constant. A car going along a curve is another example.
Answer Answers 8 Comments Comments
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Teaches

Class 12 Tuition
1 Student

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

11

Board

NIOS, ISC/ICSE, CBSE, International Baccalaureate, State

Preferred class strength

One on one/ Private Tutions

Subjects taught

Physics

Taught in School or College

No

Teaching Experience in detail in Class 12 Tuition

Good.

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

11

Board

ISC/ICSE, CBSE, International Baccalaureate, State

Preferred class strength

One on one/ Private Tutions

Subjects taught

Physics

Taught in School or College

No

Teaching Experience in detail in Class 11 Tuition

I stay in BTM 2nd Stage and would like to assist you in learning the subject. At grade 10, I teach Maths and Physics. At 11 and 12 levels, I teach Physics (Tuitions). I have 7+ years of experience in teaching, creating, and publishing questions and videos. I teach across curriculum boards: State Syllabus, ICSE, CBSE, IGCSE (Cambridge), and IB (10+1, 10+2). I have a total of 25+ years of working experience as a Scientist in DRDO and as an Engineer in MNCs (Tektronix, Hughes, HP, etc.). In the past 7 years, I have been working in education: 2 years in the content team at Educational Initiatives (creators of ASSET/Mindspark) and currently as a Content Head at Funtoot (a leading company in Maths/Science content). My teaching style is thoroughly concept-based, making the classes engaging and interesting for the student, allowing them to question assumptions and learn through dialogue. The classes can be conducted face-to-face or online.

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

11

Board

CBSE, ICSE, IGCSE, State, International Baccalaureate, NIOS

Preferred class strength

One on one/ Private Tutions, Group Classes

Experience in School or College

Have been teaching Mathematics for 9 and 10 for the last 6 years. Have taught the subject under various boards such as CBSE, ICSE, State Syllabuses.

Subjects taught

Mathematics

Taught in School or College

Yes

Teaching Experience in detail in Class 10 Tuition

A lot of students struggle with concepts and numerical skills. Lack of practice make them fall behind. I take care of students who are can learn under care. These students are generally shy asking questions in the class. I support both student centric and teacher centric teaching so that classes outcome is ensured for different type of learners

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

11

Board

CBSE, ICSE, IGCSE, NIOS, International Baccalaureate

Preferred class strength

One on one/ Private Tutions, Group Classes

Subjects taught

Mathematics, Science

Taught in School or College

No

Teaching Experience in detail in Class 9 Tuition

This is in response to your requirement for tuitions for grade 9 Maths on UrbanPro. I stay in BTM 2nd Stage and would like to assist you in learning the subject. At grade 10, I teach Maths and Physics. At 11th and 12th levels, I teach Physics. I have an experience of 7+ years in teaching, creating and publishing questions and videos. I teach across curriculum boards: State Syllabus, ICSE, CBSE, IGCSE (Cambridge), and IB (10+1, 10+2). I have, in all, 25+ years of working experience as a Scientist in DRDO and as an Engineer in MNCs (Tektronix, Hughes, HP, etc.). In the past 7 years, I have been working in education, including 2 years in the content team at Educational Initiatives (creators of ASSET/Mindspark) and currently as content head at funtoot (a company that leads in Maths/Science content). My teaching style is thoroughly concept-based, making the classes engaging and interesting to the student, letting them question assumptions and learn through dialogue. The classes can be conducted face-to-face or online.

No Reviews yet!

Answers by Varghese Babu

Answered on 12/02/2018 Learn CBSE - Class 9/Science +1 Tuition/Class IX-X Tuition

Ask a Question Ask a Question

Post a Lesson Post a Lesson

Here is a convenient formula that helps us find an answer to this question. v^2 = u^2 + 2aS, where "v" is the final velocity, "u" is the initial velocity, "a" is the acceleration, "S" is the distance travelled. In this case, v = 0, a = -g (acceleration due to gravity), S = h (height). Thus we get, u^2... ...more

Here is a convenient formula that helps us find an answer to this question. v^2 = u^2 + 2aS, where "v" is the final velocity, "u" is the initial velocity, "a" is the acceleration, "S" is the distance travelled. In this case, v = 0, a = -g (acceleration due to gravity), S = h (height). Thus we get, u^2 = 2gh, knowing "u', h can be calculated. Note that the calculation of height is independent of the mass of the object. The height depends on the velocity with which the object is projected upwards. Thus both objects reach the same height.

Answer Answers 6 Comments Comments
Dislike Bookmark

Answered on 12/02/2018 Learn CBSE - Class 9/Science +1 Tuition/Class IX-X Tuition

Ask a Question Ask a Question

Post a Lesson Post a Lesson

Freefall is when the body falls freely under the gravity and we assume, resistance due to the air is negligible. The acceleration on the body is constant and Force on the body is "mg", where "m" is the mass of the body and "g" is the acceleration due to gravity. Since "m" is constant for the given... ...more
Freefall is when the body falls freely under the gravity and we assume, resistance due to the air is negligible. The acceleration on the body is constant and Force on the body is "mg", where "m" is the mass of the body and "g" is the acceleration due to gravity. Since "m" is constant for the given body, the force is also constant. Momentum and acceleration are of course will not be constant when the net force acting on the body is not zero as in the case of free fall.
Answer Answers 2 Comments Comments
Dislike Bookmark

Answered on 12/02/2018 Learn CBSE - Class 9/Science +1 Tuition/Class IX-X Tuition

Ask a Question Ask a Question

Post a Lesson Post a Lesson

When the state of matter (solid -> liquid, liquid-> vapour, vapour -> liquid, liquid -> solid) does not change all of a sudden as the soon its transition temperature is reached. So what happens to a block of ice kept at room temperature (say at 27-degree Celsius ). The molecules in the liquid... ...more

When the state of matter (solid -> liquid, liquid-> vapour, vapour -> liquid, liquid -> solid) does not change all of a sudden as the soon its transition temperature is reached. So what happens to a block of ice kept at room temperature (say at 27-degree Celsius ). The molecules in the liquid state of matter will have a higher internal energy as compared when the matter is in the solid state. The melting point is the temperature at which the solid transitioned into liquid. The heat supplied is fully utilised to convert the solid into the liquid state at the melting point of the solid. Thus its temperature does not rise.

Answer Answers 4 Comments Comments
Dislike Bookmark

Answered on 12/02/2018 Learn CBSE - Class 9/Science +1 Tuition/Class IX-X Tuition

Ask a Question Ask a Question

Post a Lesson Post a Lesson

Any object that has a mass also have inertia. The inertia of a body is its resistance to change its state, whether it is the state of rest or the state of motion. Newton's 1st law describes the behaviour of a body to continue its state of rest or state of the motion unless acted upon by an external... ...more
Any object that has a mass also have inertia. The inertia of a body is its resistance to change its state, whether it is the state of rest or the state of motion. Newton's 1st law describes the behaviour of a body to continue its state of rest or state of the motion unless acted upon by an external force. It is clear that newtons first law describes the inertia of the object, therefore it is also known as the law of inertia.
Answer Answers 2 Comments Comments
Dislike Bookmark

Answered on 12/02/2018 Learn CBSE - Class 9/Science +1 Tuition/Class IX-X Tuition

Ask a Question Ask a Question

Post a Lesson Post a Lesson

Uniform circular motion describes an object moves along a circular path at constant speed. The velocity of the object any point on the circular path is directed along the tangent. Therefore its velocity change continuously (though its speed is constant). The change in velocity is possible only when... ...more
Uniform circular motion describes an object moves along a circular path at constant speed. The velocity of the object any point on the circular path is directed along the tangent. Therefore its velocity change continuously (though its speed is constant). The change in velocity is possible only when there is the force acting on the object making it move along the curved path. This force is directed towards the centre of the circular path, along which the object moves. This force is referred as centripetal force. A stone tied to the string and swung in circles is an example of uniform circular motion, provided its speed is kept constant. A car going along a curve is another example.
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