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Maninagar, Ahmedabad 
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Tutor's home You are amazing at what you do! Your passion and dedication is beyond words! Thank you for getting me through this hard quick semester.Thank you so much once again!
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Hindi Proficient
UNIVERSITY RAJASTHAN 2008
Bachelor of Engineering (B.E.)
Niit 2005
C language
Jlj financial and management consultant 2007
Java
London city college 2008
Post graduate diploma in business management
Near, Gopal Tower, Maninagar Railway Station Rd, Maninagar
Maninagar, Ahmedabad, India - 380028
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2 Students Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
6
Board
CBSE, State
Subjects taught
Mathematics, Science
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
6
Board
CBSE, State
Subjects taught
Mathematics, Science
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
6
Board
State, CBSE
Subjects taught
Science, Mathematics
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
6
Board
CBSE
Subjects taught
Mathematics
Taught in School or College
Yes
4.8 out of 5 28 reviews
Patel Riya
Class 9 Tuition
"You are amazing at what you do! Your passion and dedication is beyond words! Thank you for getting me through this hard quick semester.Thank you so much once again! "
Reply by Sonal
Thanks for feedback
Harsh
Class 9 Tuition
"Mam teaches us very well,she explain us each topic in detail and also clear the base of every topic. I like her method of teaching. "
Reply by Sonal
Thanks for feedback
Rahi Patel
Class 7 Tuition
"I like the teaching way. it was so smart. I am enjoying studying with sonal mam and her teaching way is brilliant. "
Reply by Sonal
Thanks for feedback
Atharv
Class 7 Tuition
"The best explanation is given. Even though I am a weak student now I feel that I am improving and getting better day by day."
Reply by Sonal
Thanks for feedback
Have you attended any class with Sonal?
Answered on 12/03/2020
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Like 2 
Answers 328 
Comments Answered on 12/03/2020 Learn IT Courses/Business Objects Enterprise XI
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Like 1 Answers 53 Comments Answered on 02/08/2019 Learn CBSE - Class 10/Mathematics/Coordinate geometry/NCERT Solutions/Exercise 7.1
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(i) Distance between two points (x1, y1) and (x2, y2) is given as:
√{(x2 – x1)2 + (y2 – y1)2}
Therefore, the distance between two points (2, 3) and (4, 1) is
D = √{(4 – 2)2 + (1 - 3)2}
=> D = √{22 + (-2)2}
=> D = √{4 + 4}
=> D = √8
=> D = 2√2
(ii) Distance between two points (x1, y1) and (x2, y2) is given as:
√{(x2 – x1)2 + (y2 – y1)2}
Therefore, the distance between two points (2, 3) and (4, 1) is
D = √{(-1 + 5)2 + (3 - 7)2}
=> D = √{42 + (-4)2}
=> D = √{16 + 16}
=> D = √32
=> D = 4√2
(iii) Distance between two points (x1, y1) and (x2, y2) is given as:
√{(x2 – x1)2 + (y2 – y1)2}
Therefore, the distance between two points (2, 3) and (4, 1) is
D = √{(-a - a)2 + (-b - b)2}
=> D = √{(-2a)2 + (-2b)2}
=> D = √{4a2 + 4b2}
=> D = 2√(a2 + b2)
Like 2 Answers 3 Comments Answered on 02/08/2019 Learn CBSE - Class 10/Mathematics/Polynomials/NCERT Solutions/Exercise 2.1
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Like 1 Answers 21 Comments Ask a Question
Also have a look at
2 Students Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
6
Board
CBSE, State
Subjects taught
Mathematics, Science
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
6
Board
CBSE, State
Subjects taught
Mathematics, Science
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
6
Board
State, CBSE
Subjects taught
Science, Mathematics
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
6
Board
CBSE
Subjects taught
Mathematics
Taught in School or College
Yes
Answered on 12/03/2020
Ask a Question
Post a Lesson
Like 2 Answers 328 Comments Answered on 12/03/2020 Learn IT Courses/Business Objects Enterprise XI
Ask a Question
Post a Lesson
Like 1 Answers 53 Comments Answered on 02/08/2019 Learn CBSE - Class 10/Mathematics/Coordinate geometry/NCERT Solutions/Exercise 7.1
Ask a Question
Post a Lesson
(i) Distance between two points (x1, y1) and (x2, y2) is given as:
√{(x2 – x1)2 + (y2 – y1)2}
Therefore, the distance between two points (2, 3) and (4, 1) is
D = √{(4 – 2)2 + (1 - 3)2}
=> D = √{22 + (-2)2}
=> D = √{4 + 4}
=> D = √8
=> D = 2√2
(ii) Distance between two points (x1, y1) and (x2, y2) is given as:
√{(x2 – x1)2 + (y2 – y1)2}
Therefore, the distance between two points (2, 3) and (4, 1) is
D = √{(-1 + 5)2 + (3 - 7)2}
=> D = √{42 + (-4)2}
=> D = √{16 + 16}
=> D = √32
=> D = 4√2
(iii) Distance between two points (x1, y1) and (x2, y2) is given as:
√{(x2 – x1)2 + (y2 – y1)2}
Therefore, the distance between two points (2, 3) and (4, 1) is
D = √{(-a - a)2 + (-b - b)2}
=> D = √{(-2a)2 + (-2b)2}
=> D = √{4a2 + 4b2}
=> D = 2√(a2 + b2)
Like 2 Answers 3 Comments Answered on 02/08/2019 Learn CBSE - Class 10/Mathematics/Polynomials/NCERT Solutions/Exercise 2.1
Ask a Question
Post a Lesson
Like 1 Answers 21 Comments Ask a Question
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Ahmedabad
