Sonal S.

Maninagar, Ahmedabad, India - 380028

Sonal S. photo

Sonal S.

Learn maths and science in a different way by engineer...

Maninagar, Ahmedabad, India - 380028.

5.0

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Details verified of Sonal S.

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Education

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Overview

I can teach every topic very easily and make it stronger for the students.

Languages Spoken

English Proficient

Hindi Proficient

Education

Instt of technology and management 2008

Bachelor of Engineering (B.E.)

Niit 2005

C language

Jlj financial and management consultant 2007

Java

London city college 2008

Post graduate diploma in business management

Address

Maninagay co-operative society,near Moscow horai, station road, Maninagar

Maninagar, Ahmedabad, India - 380028

Landmark: moscow hotel

Verified Info

Phone Verified

Email Verified

Demo Class

Yes, not charged

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Class 10 Tuition Overview

Class 10 Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

6

Board

CBSE, State, IGCSE, ICSE

CBSE Subjects taught

Social science, Science, Computer Practices, English, Mathematics, Information and Comunication Technology

ICSE Subjects taught

Physics, Chemistry, English Literature, English, Mathematics, Biology, Computer Application

IGCSE Subjects taught

English, Physics, Chemistry, Information Technology, English Literature, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Science, Hindi, English, EVS, Social Science

Reviews

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Answers by Sonal S. (2)

Answered on 02 Aug CBSE/Class 10/Mathematics/UNIT III: Coordinate Geometry/Coordinate geometry/NCERT Solutions/Exercise 7.1

(i) Distance between two points (x1, y1) and (x2, y2) is given as: √{(x2 – x1)2 + (y2 – y1)2} Therefore, the distance between two points (2, 3) and (4, 1) is D = √{(4 – 2)2 + (1 - 3)2} => D = √{22 + (-2)2} => D = √{4 + 4} => D = √8 =>... ...more

(i) Distance between two points (x1, y1) and (x2, y2) is given as:

√{(x2 – x1)2 + (y2 – y1)2}

Therefore, the distance between two points (2, 3) and (4, 1) is

       D = √{(4 – 2)2 + (1 - 3)2}

=> D = √{22 + (-2)2}

=> D = √{4 + 4}

=> D = √8

=> D = 2√2

(ii) Distance between two points (x1, y1) and (x2, y2) is given as:

√{(x2 – x1)2 + (y2 – y1)2}

Therefore, the distance between two points (2, 3) and (4, 1) is

       D = √{(-1 + 5)2 + (3 - 7)2}

=> D = √{42 + (-4)2}

=> D = √{16 + 16}

=> D = √32

=> D = 4√2

(iii) Distance between two points (x1, y1) and (x2, y2) is given as:

√{(x2 – x1)2 + (y2 – y1)2}

Therefore, the distance between two points (2, 3) and (4, 1) is

       D = √{(-a - a)2 + (-b - b)2}

=> D = √{(-2a)2 + (-2b)2}

=> D = √{4a2 + 4b2}

=> D = 2√(a2 + b2)

Answers 3 Comments
Dislike Bookmark

Answered on 02 Aug CBSE/Class 10/Mathematics/UNIT II: Algebra/Polynomials/NCERT Solutions/Exercise 2.1

0,1,3,2,4,3
Answers 21 Comments
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Sonal S.Directions

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Class 10 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

6

Board

CBSE, State, IGCSE, ICSE

CBSE Subjects taught

Social science, Science, Computer Practices, English, Mathematics, Information and Comunication Technology

ICSE Subjects taught

Physics, Chemistry, English Literature, English, Mathematics, Biology, Computer Application

IGCSE Subjects taught

English, Physics, Chemistry, Information Technology, English Literature, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Science, Hindi, English, EVS, Social Science

BTech Tuition 4.3

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in BTech Tuition

6

BTech Computer Science subjects

Java Programming

BTech Branch

BTech Computer Science Engineering

Type of class

Crash Course

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

Yes

Class 11 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

6

Board

State, CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Class 9 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 9 Tuition

6

Board

CBSE, State, IGCSE, ICSE

CBSE Subjects taught

Science, Computer Practices, English, Mathematics, Information and Comunication Technology

ICSE Subjects taught

Physics, Chemistry, English Literature, English, Mathematics, Biology, Computer Application

IGCSE Subjects taught

English, Physics, Chemistry, Information Technology, Biology, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Science, English

Class 8 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 8 Tuition

6

Board

State, ICSE, IGCSE, International Baccalaureate, CBSE

IB Subjects taught

Computers, Science, Physical Education, Mathematics, Hindi, Arts, English

CBSE Subjects taught

English, Social Science, Computers, Science, Hindi, EVS, Mathematics

ICSE Subjects taught

Mathematics, Chemistry, History, EVS, English, Biology, Physics, Geography, Computer Science, Hindi

IGCSE Subjects taught

Science, Hindi, English, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, EVS, Hindi, English, Social science, Science

Class 7 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 7 Tuition

6

Board

State, ICSE, IGCSE, International Baccalaureate, CBSE

IB Subjects taught

Computers, Science, Physical Education, Mathematics, Hindi, Arts, English

CBSE Subjects taught

English, Social Science, Computers, Science, Hindi, EVS, Mathematics

ICSE Subjects taught

Mathematics, Chemistry, History, EVS, English, Biology, Physics, Geography, Computer Science, Hindi

IGCSE Subjects taught

Science, Hindi, English, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, EVS, Hindi, English, Social science, Science

Class 6 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 6 Tuition

6

Board

State, ICSE, IGCSE, International Baccalaureate, CBSE

IB Subjects taught

Computers, Science, Physical Education, Mathematics, Hindi, English

CBSE Subjects taught

English, Social Science, Computers, Science, Hindi, EVS, Mathematics

ICSE Subjects taught

Mathematics, Chemistry, History, EVS, English, Biology, Physics, Geography, Computer Science, Hindi

IGCSE Subjects taught

Science, Hindi, English, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, EVS, Hindi, English, Social science, Science

C++ Language Classes 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in C++ Language Classes

6

Proficiency level taught

Advanced C++

C Language Classes 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in C Language Classes

6

Python Training classes 4.3

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Python Training classes

6

Course Duration provided

1-3 months

Seeker background catered to

Individual

Certification provided

No

Python applications taught

Regular Expressions with Python

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No Reviews yet! Be the first one to Review

Answers by Sonal S. (2)

Answered on 02 Aug CBSE/Class 10/Mathematics/UNIT III: Coordinate Geometry/Coordinate geometry/NCERT Solutions/Exercise 7.1

(i) Distance between two points (x1, y1) and (x2, y2) is given as: √{(x2 – x1)2 + (y2 – y1)2} Therefore, the distance between two points (2, 3) and (4, 1) is D = √{(4 – 2)2 + (1 - 3)2} => D = √{22 + (-2)2} => D = √{4 + 4} => D = √8 =>... ...more

(i) Distance between two points (x1, y1) and (x2, y2) is given as:

√{(x2 – x1)2 + (y2 – y1)2}

Therefore, the distance between two points (2, 3) and (4, 1) is

       D = √{(4 – 2)2 + (1 - 3)2}

=> D = √{22 + (-2)2}

=> D = √{4 + 4}

=> D = √8

=> D = 2√2

(ii) Distance between two points (x1, y1) and (x2, y2) is given as:

√{(x2 – x1)2 + (y2 – y1)2}

Therefore, the distance between two points (2, 3) and (4, 1) is

       D = √{(-1 + 5)2 + (3 - 7)2}

=> D = √{42 + (-4)2}

=> D = √{16 + 16}

=> D = √32

=> D = 4√2

(iii) Distance between two points (x1, y1) and (x2, y2) is given as:

√{(x2 – x1)2 + (y2 – y1)2}

Therefore, the distance between two points (2, 3) and (4, 1) is

       D = √{(-a - a)2 + (-b - b)2}

=> D = √{(-2a)2 + (-2b)2}

=> D = √{4a2 + 4b2}

=> D = 2√(a2 + b2)

Answers 3 Comments
Dislike Bookmark

Answered on 02 Aug CBSE/Class 10/Mathematics/UNIT II: Algebra/Polynomials/NCERT Solutions/Exercise 2.1

0,1,3,2,4,3
Answers 21 Comments
Dislike Bookmark

Sonal S. describes herself as Learn maths and science in a different way by engineer having y years of experience...... She conducts classes in BTech Tuition, C Language and C++ Language. Sonal is located in Maninagar, Ahmedabad. Sonal takes at students Home and Regular Classes- at her Home. She has 6 years of teaching experience . Sonal has completed Bachelor of Engineering (B.E.) from Instt of technology and management in 2008. She is well versed in English and Hindi.

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