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Preeti P.

Computer programmer ,maths tutor

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Overview

About myself : I am a software engineer .
I have been teaching from my engineering days .The subjects I excel in are programming and coding languages like C,C++,Java etc .
Apart from this I conduct classes for aptitude tests for interviews ,Maths,Science .


It guides the students in engineering ,bcs,bca and other computer related fields .I assure complete understanding of the subject alongwith the practicals related to every subject .

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English

Education

Pune 2012

Bachelor of Engineering (B.E.)

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Chinchwad East, Pune, India - 411019

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Answers by Preeti P. (2)

Answered on 03/12/2014 Learn Tuition/BTech Tuition

How to create our database in oracle database 10g?

there are two ways ..either you use a gui or though command line .I recommend you to use commandline..Open the command prompt of oracle 10g and put your id password .Then fire your queries like create table table_name etc
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Answered on 03/12/2014 Learn IT Courses/RDBMS

What is difference between 3nf and bcnf?

Please refer wiki for exact definitions. Here is an explaination to your query 3NF Definition A relation is in 3NF if it is in 2NF and no non-prime attribute transitively depends on the primary key. In other words, a relation R is in 3NF if for each functional dependency X ? A in R at least... ...more
Please refer wiki for exact definitions. Here is an explaination to your query 3NF Definition A relation is in 3NF if it is in 2NF and no non-prime attribute transitively depends on the primary key. In other words, a relation R is in 3NF if for each functional dependency X ? A in R at least one of the following conditions are met: X is a key or superkey in R A is a prime attribute in R Example Given the following relation: EMP_DEPT(firstName, employeeNumber, dateOfBirth, address, departmentNumber, departmentName) An employee can only work in one department and each department has many employees. The candidate key is employeeNumber. Consider the following functional dependencies: employeeNumber ? firstName, dateOfBirth, address, departmentNumber departmentNumber ? departmentName Given the definition above it is possible to conclude that the relation EMP_DEPT is not in 3NF because the second functional dependency does not meet any of the 2 conditions of the 3NF: departmentNumber is not a key or superkey in EMP_DEPT departmentName is not a prime attribute in EMP_DEPT BCNF Definition A relation R is in BCNF if it is in 3NF and for each functional dependency X ? A in R, X is a key or superkey in R. In other words, the only difference between 3NF and BCNF is that in BCNF it is not present the second condition of the 3NF. This makes BCNF stricter than 3NF as any relation that is in BCNF will be in 3NF but not necessarily every relation that is in 3NF will be in BCNF. Example Given the following relation: STUDENT_COURSE(studentNumber, socialSecurityNumber, courseNumber) A student can assist to many courses and in a course there can be many students. The candidate keys are: socialSecurityNumber, courseNumber studentNumber, courseNumber Consider the following functional dependencies: studentNumber ? socialSecurityNumber socialSecurityNumber ? studentNumber Given the definitioin above it is possible to conclude that STUDENT_COURSE is not in BCNF as at least studentNumber is not a key or superkey in STUDENT_COURSE.3NF Definition A relation is in 3NF if it is in 2NF and no non-prime attribute transitively depends on the primary key. In other words, a relation R is in 3NF if for each functional dependency X ? A in R at least one of the following conditions are met: X is a key or superkey in R A is a prime attribute in R Example Given the following relation: EMP_DEPT(firstName, employeeNumber, dateOfBirth, address, departmentNumber, departmentName) An employee can only work in one department and each department has many employees. The candidate key is employeeNumber. Consider the following functional dependencies: employeeNumber ? firstName, dateOfBirth, address, departmentNumber departmentNumber ? departmentName Given the definition above it is possible to conclude that the relation EMP_DEPT is not in 3NF because the second functional dependency does not meet any of the 2 conditions of the 3NF: departmentNumber is not a key or superkey in EMP_DEPT departmentName is not a prime attribute in EMP_DEPT BCNF Definition A relation R is in BCNF if it is in 3NF and for each functional dependency X ? A in R, X is a key or superkey in R. In other words, the only difference between 3NF and BCNF is that in BCNF it is not present the second condition of the 3NF. This makes BCNF stricter than 3NF as any relation that is in BCNF will be in 3NF but not necessarily every relation that is in 3NF will be in BCNF. Example Given the following relation: STUDENT_COURSE(studentNumber, socialSecurityNumber, courseNumber) A student can assist to many courses and in a course there can be many students. The candidate keys are: socialSecurityNumber, courseNumber studentNumber, courseNumber Consider the following functional dependencies: studentNumber ? socialSecurityNumber socialSecurityNumber ? studentNumber Given the definitioin above it is possible to conclude that STUDENT_COURSE is not in BCNF as at least studentNumber is not a key or superkey in STUDENT_COURSE.
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Answers by Preeti P. (2)

Answered on 03/12/2014 Learn Tuition/BTech Tuition

How to create our database in oracle database 10g?

there are two ways ..either you use a gui or though command line .I recommend you to use commandline..Open the command prompt of oracle 10g and put your id password .Then fire your queries like create table table_name etc
Answers 49 Comments
Dislike Bookmark

Answered on 03/12/2014 Learn IT Courses/RDBMS

What is difference between 3nf and bcnf?

Please refer wiki for exact definitions. Here is an explaination to your query 3NF Definition A relation is in 3NF if it is in 2NF and no non-prime attribute transitively depends on the primary key. In other words, a relation R is in 3NF if for each functional dependency X ? A in R at least... ...more
Please refer wiki for exact definitions. Here is an explaination to your query 3NF Definition A relation is in 3NF if it is in 2NF and no non-prime attribute transitively depends on the primary key. In other words, a relation R is in 3NF if for each functional dependency X ? A in R at least one of the following conditions are met: X is a key or superkey in R A is a prime attribute in R Example Given the following relation: EMP_DEPT(firstName, employeeNumber, dateOfBirth, address, departmentNumber, departmentName) An employee can only work in one department and each department has many employees. The candidate key is employeeNumber. Consider the following functional dependencies: employeeNumber ? firstName, dateOfBirth, address, departmentNumber departmentNumber ? departmentName Given the definition above it is possible to conclude that the relation EMP_DEPT is not in 3NF because the second functional dependency does not meet any of the 2 conditions of the 3NF: departmentNumber is not a key or superkey in EMP_DEPT departmentName is not a prime attribute in EMP_DEPT BCNF Definition A relation R is in BCNF if it is in 3NF and for each functional dependency X ? A in R, X is a key or superkey in R. In other words, the only difference between 3NF and BCNF is that in BCNF it is not present the second condition of the 3NF. This makes BCNF stricter than 3NF as any relation that is in BCNF will be in 3NF but not necessarily every relation that is in 3NF will be in BCNF. Example Given the following relation: STUDENT_COURSE(studentNumber, socialSecurityNumber, courseNumber) A student can assist to many courses and in a course there can be many students. The candidate keys are: socialSecurityNumber, courseNumber studentNumber, courseNumber Consider the following functional dependencies: studentNumber ? socialSecurityNumber socialSecurityNumber ? studentNumber Given the definitioin above it is possible to conclude that STUDENT_COURSE is not in BCNF as at least studentNumber is not a key or superkey in STUDENT_COURSE.3NF Definition A relation is in 3NF if it is in 2NF and no non-prime attribute transitively depends on the primary key. In other words, a relation R is in 3NF if for each functional dependency X ? A in R at least one of the following conditions are met: X is a key or superkey in R A is a prime attribute in R Example Given the following relation: EMP_DEPT(firstName, employeeNumber, dateOfBirth, address, departmentNumber, departmentName) An employee can only work in one department and each department has many employees. The candidate key is employeeNumber. Consider the following functional dependencies: employeeNumber ? firstName, dateOfBirth, address, departmentNumber departmentNumber ? departmentName Given the definition above it is possible to conclude that the relation EMP_DEPT is not in 3NF because the second functional dependency does not meet any of the 2 conditions of the 3NF: departmentNumber is not a key or superkey in EMP_DEPT departmentName is not a prime attribute in EMP_DEPT BCNF Definition A relation R is in BCNF if it is in 3NF and for each functional dependency X ? A in R, X is a key or superkey in R. In other words, the only difference between 3NF and BCNF is that in BCNF it is not present the second condition of the 3NF. This makes BCNF stricter than 3NF as any relation that is in BCNF will be in 3NF but not necessarily every relation that is in 3NF will be in BCNF. Example Given the following relation: STUDENT_COURSE(studentNumber, socialSecurityNumber, courseNumber) A student can assist to many courses and in a course there can be many students. The candidate keys are: socialSecurityNumber, courseNumber studentNumber, courseNumber Consider the following functional dependencies: studentNumber ? socialSecurityNumber socialSecurityNumber ? studentNumber Given the definitioin above it is possible to conclude that STUDENT_COURSE is not in BCNF as at least studentNumber is not a key or superkey in STUDENT_COURSE.
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Preeti P. describes herself as Computer programmer ,maths tutor. She conducts classes in BCA Tuition, BSc Tuition and BTech Tuition. Preeti is located in Chinchwad East, Pune. Preeti takes at students Home, Regular Classes- at her Home and Online Classes- via online medium. She has 2 years of teaching experience . Preeti has completed Bachelor of Engineering (B.E.) from Pune in 2012. She is well versed in English.

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