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Science Tuition classes near me in 255 EB Rd Burewala, Burewala

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Science Tuition classes near me in 255 EB Rd Burewala, Burewala

Select from 11 Online Science Tuition classes

1
Online Classes in Burewala, Punjab
1 yrs of Exp
Classes: Science Tuition classes, Class I-V Tuition

I am a tution teacher. I have communication skills and management skills. My degree is processing. I was giving online home tution—my accomplishment...

2
Online Classes in Burewala, Punjab
1 yrs of Exp
PKR 1988per hour
Classes: Science Tuition classes Class I-V Tuition

Currently, I am employed at Tabinda School, where I teach in the higher section. My professional experience also extends to home tutoring since 2022,...

3
Online Classes in Burewala, Punjab
3 yrs of Exp
Classes: Science Tuition classes, Class 12 Tuition and more.

: I am a teacher... I am giving online home tuition since.2020 ... I have a degree in math computer... My key skills are basic programming and mathematics...

4
Online Classes in Burewala, Punjab
3 yrs of Exp
PKR 1491per hour
Classes: Science Tuition classes BSc Tuition

I can teach every topic very easily and make it stronger for the students.

5
Online Classes in Burewala, Punjab
7 yrs of Exp
Classes: Science Tuition classes, Class 12 Tuition and more.

I am a Urdu teacher in well reputed college in Pakistan. I have done my master in philosophy (M. Phil?) Urdu. I have well command in grammar.

6
Online Classes in Burewala, Punjab
8 yrs of Exp
Classes: Science Tuition classes, Class 12 Tuition and more.

I am a teacher. My teaching experience is about 8 years .I have specialities in biology. I can teach Matric and intermediate classes .I can teach...

7
Online Classes in Burewala, Punjab
4 yrs of Exp
Classes: Science Tuition classes, Class 11 Tuition and more.

I am teaching chemistry since 2019 at matric and intermediate level. By the grace of God my students showed good results every year. I am going to...

8
Online Classes in Burewala, Punjab
1 yrs of Exp
Classes: Science Tuition classes, Class 11 Tuition and more.

I am a teacher .... I am giving home tution since 2019 . I have a degree in bs (horns)physics ...... my skill key are physics . I teach physics very...

9
Online Classes in Burewala, Punjab
3 yrs of Exp
Classes: Science Tuition classes, Class 10 Tuition

I am a teacher .I am giving home /online tusion since 2 years .I am certified in science subject . I HAVE DEGREE IN M.SC. My skills are teaching science...

10
Online Classes in Burewala, Punjab
6 yrs of Exp
PKR 6627per hour
Classes: Science Tuition classes Class 10 Tuition

I am a teacher i am giving and online tuition since 2 year's and one more thing is that teaching is my passion i have 6 years of experience in teaching...

11
Online Classes in Burewala, Punjab
3 yrs of Exp
Classes: Science Tuition classes, Class I-V Tuition

I am a teacher. I am giving online tuition . I have a degree in B.Sc.My key skills re mehandi designing and math expert. thanks

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Key highlights about Science Tuition classes

✅ Free Demo Class : Available
✅ Average price : PKR 1,077/hr
✅ Tutors available : 11
✅ Class format : Online or Offline classes

FAQ

How do I find the best Science Tuition classes near me in 255 EB Rd Burewala, Burewala near me?

You can browse the list of best Science Tuition classes tutors on UrbanPro.com. You can even book a free demo class to decide which Tutor to start classes with.

What is the typical Fee charged for Science Tuition classes near me in 255 EB Rd Burewala, Burewala?

The fee charged varies between online and offline classes. Generally you get the best quality at the lowest cost in the online classes, as the best tutors don’t like to travel to the Student’s location.

Monthly Fee for 1-1 Classes

PKR 3,000 - INR 4,800 for 12 classes per month

Hourly Fee for 1-1 Classes

PKR 250 - INR 400

Monthly Fee for Group Classes

PKR 2,400 - INR 3,840 for 12 classes per month

Hourly Fee for Group Classes

PKR 200 - INR 320

Monthly Fee for Tuition at home

PKR 9,936 - PKR 15,900 for 12 classes per month

Hourly Fee for Tuition at home

PKR 828 - PKR 1,325

Monthly Fee for Online Tuition

PKR 9,936 - PKR 15,900 for 12 classes per month

Hourly Fee for Online Tuition

PKR 828 - PKR 1,325

Does joining Tuition help?

It definitely helps to join Science Tuition classes near me in 255 EB Rd Burewala, Burewala, as you get the desired motivation from a Teacher to learn. If you need personal attention and if your budget allows, select 1-1 Class. If you need peer interaction or have budget constraints, select a Group Class.

What are the Top Searches in Burewala?

Top Searches in Burewala are Tuition,

Science Tuition classes Questions

Why does math have to be so hard and confusing?

Because it become excercise for human mind. As you do exercise your potential increases . As you spend...

Find: (i) 4.8 ÷ 10 (ii) 52.5 ÷ 10 (iii) 0.7 ÷ 10 (iv) 33.1 ÷ 10 (v) 272.23...

We know that when a decimal number is divided by a multiple of 10 only (i.e., 10, 100, 1000, etc.), the...

Mention the hazards of working in the glass bangles industry.

The impoverished workers in the glass bangles industry toil in potentially hazardous working conditions...

How is quantum physics different from quantum chemistry?

Quantum physics deals with the fundamental principles of nature at the smallest scales, focusing on phenomena...

Science Tuition classes Lessons

Key to Success in Mathematics

Following are keys to success in any mathematics exam: 1. Learn how formulas are derived. 2. Types of Interpretations of formulas. 3. Selected Examples...

SQL Server Row Count for all Tables in a Database

ProblemI am a database consultant and one of my tasks involves getting the row counts from all the tables in the source database and comparing it against...

A short concept of Fiscal Deficit in Economics :--

A fiscal deficit occurs when a government's total expenditures exceed the revenue that it generates, excluding money from borrowings. Deficit differs from...

Differentiating 2(x^2) using first principle

Differentiate 2x² using first principle We know from first principle that dy/dx f(x) = lim δx→0 /δx Here f(x) = 2 x² substituting...

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