default_background

Find the best tutors and institutes for Class 10 Tuition

Find Best Class 10 Tuition

Please select a Category.

Please select a Locality.

No matching category found.

No matching Locality found.

Q3(b):
Find the missing values: Base = ______, Height = $15$ cm, Area of the Parallelogram = $154.5$ cm$^2$.

Solution :

Given Variables & Initial Setup

We are tasked with determining the missing base dimension of a parallelogram given its height and total area. The known parameters are defined as follows:

  • Height ($h$): $15 \text{ cm}$
  • Area ($A$): $154.5 \text{ cm}^2$
  • Base ($b$): Unknown

Theoretical Foundation

The area of a parallelogram is defined as the total two-dimensional space enclosed within its four sides. Geometrically, a parallelogram can be rearranged into a rectangle of the same base and height. Therefore, the governing formula for the area of a parallelogram is:

$A = b \times h$

[Per the geometric postulate of area equivalence under translation, the area of a parallelogram is strictly the product of its base and the corresponding perpendicular height].

Step 1: Algebraic Substitution

Substitute the given numerical values into the standard area formula:

$154.5 = b \times 15$

Step 2: Isolation of the Variable

To solve for the unknown base ($b$), we must isolate it on one side of the equation. We achieve this by dividing both sides of the equation by the height ($15$).

$b = \frac{154.5}{15}$

[Applying the Division Property of Equality, which states that dividing both sides of an equation by the same non-zero number preserves the equality].

Step 3: Arithmetic Computation & Decimal Manipulation

To perform the division with precision, we can eliminate the decimal in the numerator by multiplying both the numerator and the denominator by $10$:

$b = \frac{154.5 \times 10}{15 \times 10}$

$b = \frac{1545}{150}$

Now, simplify the fraction by dividing both terms by their common factors. First, divide by $5$:

$\frac{1545 \div 5}{150 \div 5} = \frac{309}{30}$

Next, divide by $3$:

$\frac{309 \div 3}{30 \div 3} = \frac{103}{10}$

Converting the simplified fraction back into a decimal yields:

$b = 10.3 \text{ cm}$

Geometric Visualization

Below is a scaled, mathematically accurate representation of the parallelogram, demonstrating the relationship between the base, the perpendicular height, and the enclosed area.

Base (b) = 10.3 cm h = 15 cm Area = 154.5 cm²

Final Verification

To ensure absolute accuracy, we substitute the calculated base back into the original area formula:

$A = 10.3 \text{ cm} \times 15 \text{ cm}$

$A = 154.5 \text{ cm}^2$

The calculated area matches the given area perfectly, confirming the validity of the derived base.

Final Solution: The missing value for the Base is $10.3 \text{ cm}$.


More Questions from Class 9 Mathematics Coordinate Geometry EXERCISE 9.1


CBSE Solutions for Class 9 Mathematics Coordinate Geometry


Chapters in CBSE - Class 9 Mathematics


Top Tutors who teach Coordinate Geometry

Ramakrishna Koutha Class 10 Tuition trainer in Mount Olive
(17)
Top Tutor
locationImg Flanders, Mount Olive
experience 5 yrs of Exp students 2 students
greenClock 22 hrs of classes completed
rsIcon 100 per hour
Experience Software engineer and volunteer teacher in math , science and computer science.
Online Classes Online Classes

I have volunteer teacher for evidyaloka ..I thought higg school students math and science

Skills: Mathematics , Physics and more

(76)
Top Tutor
locationImg Jayanagar, Bangalore
experience 18 yrs of Exp students 28 students
greenClock 2317 hrs of classes completed
rsIcon 500 per hour
Experienced Tutor - Maths and Hindustani Vocals
Online Classes Online Classes

Private teacher. Classes will be taken for science also but only for Physics and Chemistry. I have been teaching for Class 10 for the past 15 years. Focus will be given to each student regarding their difficult concepts. Previous year question papers will be discussed, along with practice worksheets that will be given for each chapter. Coaching will be given to score good marks in respective board exams by giving them tricks to manage the timings

Arya

Wonderful teacher with enormous knowledge about the subject with a smile every time while teaching...

Skills: Mathematics
Also teaches: Class 6 Tuition, Class 8 Tuition and more

(19)
Top Tutor
locationImg Bhestan, Surat
experience 2 yrs of Exp students 5 students
greenClock 355 hrs of classes completed
rsIcon 600 per hour
4+ Yrs Exp | M.Sc. Maths | B.Tech Chem Eng | DRDO Research | Mentored 500+ Students Online & Offline
Online Classes Online Classes
regularClasses Tutor's home

I have motivated many 10th std student who scored more than 85% I love teaching and I can make you understand what actually studies is!!! It's all about practise and applications

Dhiraj Patel

I highly recommend Shivam Sir for Class 10 Mathematics and Science. He taught my brother, and the improvement in his understanding and confidence was remarkable. Before joining his classes, my brother found several concepts difficult, but Shivam Sir explained every topic in a very simple, practical, and easy-to-understand manner. He always ensured that every concept was clear before moving on to the next chapter. His teaching style is interactive and student-friendly. He patiently answers every doubt, gives plenty of practice questions, conducts regular tests, and provides useful tips for board exams. He also shares short tricks, revision strategies, and focuses on strengthening concepts rather than just memorizing answers.

Skills: English , Mathematics and more
Also teaches: Class 12 Tuition, Class 9 Tuition and more

(44)
Top Tutor
locationImg SCB Nagar, Kothagudem
experience 20 yrs of Exp students 31 students
greenClock 2094 hrs of classes completed
rsIcon 450 per hour
Mathematics Facilitator 22 Years experience
Online Classes Online Classes

22 Years Experience in Schools IN ICSE/CBSE/IGCSE IN DIFFERENT STATE BOARDS

Abhinav Sidhardha

Sir is very friendly teacher he will support us more he is the best teacher of the year his teaching skills are really good.

Skills: Mathematics , Science and more
Also teaches: Math Olympiad, Class 8 Tuition and more

(12)
Top Tutor
locationImg Patel Nagar, Gurgaon
experience 13 yrs of Exp
rsIcon 300 per hour
Computer cum all subject teacher
Online Classes Online Classes
homeTutions Student's Home
regularClasses Tutor's home
Skills: Computer/Laptop repair , English and more
Also teaches: Class 7 Tuition, Computer and more

Find more Tutor for Coordinate Geometry in your City


Other Subjects in CBSE - Class 9

Worksheet Icon

Download free CBSE - Class 9 Mathematics Coordinate Geometry EXERCISE 9.1 worksheets

Download Now

Find Best Class 10 Tuition ?

Find Now »