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Q1(i):
Find the transpose of each of the following matrices: (i) $\begin{bmatrix} 5 \\ \frac{1}{2} \\ -1 \end{bmatrix}$

Solution :

Step 1: Theoretical Foundation of Matrix Transposition

The transpose of a matrix, denoted as $A^T$ or $A'$, is an operation that converts rows into columns and columns into rows. For any matrix $A$ of order $m \times n$, its transpose $A^T$ will have the order $n \times m$. Formally, if $A = [a_{ij}]$, then $A^T = [a_{ji}]$, where the element at the $i$-th row and $j$-th column is shifted to the $j$-th row and $i$-th column [By the definition of matrix transpose].

Step 2: Analysis of the Given Matrix

Let the given matrix be $A$. $A = \begin{bmatrix} 5 \\ \frac{1}{2} \\ -1 \end{bmatrix}$

  • Matrix Dimensions: The matrix $A$ consists of 3 rows and 1 column. Therefore, the order is $3 \times 1$.
  • Expected Dimensions of $A^T$: Since the order is $m \times n$, the transpose $A^T$ must have an order of $n \times m$, which is $1 \times 3$.

Step 3: Execution of the Transposition

To compute $A^T$, we take the column vector and rewrite it as a row vector:

$A^T = \begin{bmatrix} 5 & \frac{1}{2} & -1 \end{bmatrix}$

Step 4: Geometric/Structural Representation

Matrix A (3x1): 5 1/2 -1 Matrix Aáµ€ (1x3): 5 1/2 -1

Final Solution: The transpose of the matrix $\begin{bmatrix} 5 \\ \frac{1}{2} \\ -1 \end{bmatrix}$ is $\begin{bmatrix} 5 & \frac{1}{2} & -1 \end{bmatrix}$.


More Questions from Class 12 Mathematics Matrices EXERCISE 3.3


CBSE Solutions for Class 12 Mathematics Matrices


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