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Q5(ii):
Construct a $3 \times 4$ matrix, whose elements are given by: (ii) $a_{ij} = 2i-j$

Solution :

Step 1: Matrix Definition and Structural Setup

A $3 \times 4$ matrix $A$ consists of $3$ rows and $4$ columns. The general form of the matrix is represented as:

$A = \begin{bmatrix} a_{11} & a_{12} & a_{13} & a_{14} \\ a_{21} & a_{22} & a_{23} & a_{24} \\ a_{31} & a_{32} & a_{33} & a_{34} \end{bmatrix}$

Each element $a_{ij}$ is defined by the rule $a_{ij} = 2i - j$, where $i$ denotes the row index ($i \in \{1, 2, 3\}$) and $j$ denotes the column index ($j \in \{1, 2, 3, 4\}$).

Step 2: Calculating Individual Elements

We evaluate each element systematically by substituting the indices into the given formula $a_{ij} = 2i - j$:

Row ($i$) $j=1$ $j=2$ $j=3$ $j=4$
$i=1$ $2(1)-1 = 1$ $2(1)-2 = 0$ $2(1)-3 = -1$ $2(1)-4 = -2$
$i=2$ $2(2)-1 = 3$ $2(2)-2 = 2$ $2(2)-3 = 1$ $2(2)-4 = 0$
$i=3$ $2(3)-1 = 5$ $2(3)-2 = 4$ $2(3)-3 = 3$ $2(3)-4 = 2$

Step 3: Matrix Assembly

Substituting the calculated values into the general matrix structure:

$A = \begin{bmatrix} 1 & 0 & -1 & -2 \\ 3 & 2 & 1 & 0 \\ 5 & 4 & 3 & 2 \end{bmatrix}$

Visualization of Index Mapping

1 0 -1 -2 3 2 1 0 5 4 3 2 Formula: aᵢⱼ = 2i - j

Final Solution: The constructed matrix is $A = \begin{bmatrix} 1 & 0 & -1 & -2 \\ 3 & 2 & 1 & 0 \\ 5 & 4 & 3 & 2 \end{bmatrix}$


More Questions from Class 12 Mathematics Matrices EXERCISE 3.1


CBSE Solutions for Class 12 Mathematics Matrices


Chapters in CBSE - Class 12 Mathematics


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