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Q5:
Integrate the functions in Exercises 1 to 22. 5. $x \log 2x$

Solution :

Step 1: Application of Integration by Parts Formula

To evaluate the integral $\int x \log(2x) \, dx$, we utilize the method of Integration by Parts, which states: $\int u \cdot v \, dx = u \int v \, dx - \int \left( \frac{du}{dx} \cdot \int v \, dx \right) dx$ [Integration by Parts Formula]

According to the ILATE rule (Inverse trigonometric, Logarithmic, Algebraic, Trigonometric, Exponential), we assign the functions as follows:

  • Let $u = \log(2x)$ [Logarithmic function chosen as the first function]
  • Let $dv = x \, dx$ [Algebraic function chosen as the second function]

Step 2: Differentiation and Integration of Assigned Parts

Calculate the derivative of $u$ and the integral of $dv$:

  • $\frac{du}{dx} = \frac{d}{dx}(\log(2x)) = \frac{1}{2x} \cdot 2 = \frac{1}{x}$ [Chain Rule of Differentiation]
  • $v = \int x \, dx = \frac{x^2}{2}$ [Power Rule of Integration: $\int x^n dx = \frac{x^{n+1}}{n+1}$]

Step 3: Substitution into the Formula

Substitute these components into the Integration by Parts formula: $\int x \log(2x) \, dx = \left( \log(2x) \cdot \frac{x^2}{2} \right) - \int \left( \frac{1}{x} \cdot \frac{x^2}{2} \right) dx$

Step 4: Algebraic Simplification and Final Integration

Simplify the integrand within the integral sign: $\int x \log(2x) \, dx = \frac{x^2}{2} \log(2x) - \int \frac{x}{2} \, dx$ $\int x \log(2x) \, dx = \frac{x^2}{2} \log(2x) - \frac{1}{2} \int x \, dx$

Perform the final integration: $= \frac{x^2}{2} \log(2x) - \frac{1}{2} \left( \frac{x^2}{2} \right) + C$ [Where $C$ is the constant of integration]

Step 5: Final Expression Consolidation

Combining the terms: $= \frac{x^2}{2} \log(2x) - \frac{x^2}{4} + C$

Graph of f(x) = x log(2x) y

Final Solution: $\frac{x^2}{2} \log(2x) - \frac{x^2}{4} + C$


More Questions from Class 12 Mathematics Integrals EXERCISE 7.6


CBSE Solutions for Class 12 Mathematics Integrals


Chapters in CBSE - Class 12 Mathematics


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