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Q20:
Integrate the functions in Exercises 1 to 22.
20. $\frac{(x-3)e^x}{(x-1)^3}$
Solution :
Step 1: Manipulating the Integrand
Given the integral: $I = \int \frac{(x-3)e^x}{(x-1)^3} \, dx$.
To simplify the integrand, we express the numerator $(x-3)$ in terms of $(x-1)$ to facilitate partial fraction decomposition relative to the denominator $(x-1)^3$.
Rewrite $(x-3)$ as $(x-1) - 2$.
Substituting this into the integral:
$I = \int \frac{((x-1) - 2)e^x}{(x-1)^3} \, dx$$I = \int \left( \frac{x-1}{(x-1)^3} - \frac{2}{(x-1)^3} \right) e^x \, dx$
$I = \int \left( \frac{1}{(x-1)^2} - \frac{2}{(x-1)^3} \right) e^x \, dx$ [By Algebraic Simplification]
Step 2: Applying the Integration Formula
We utilize the standard integration identity: $\int e^x [f(x) + f'(x)] \, dx = e^x f(x) + C$.
Let $f(x) = \frac{1}{(x-1)^2}$.
Differentiating $f(x)$ with respect to $x$ using the Power Rule and Chain Rule:
$f'(x) = \frac{d}{dx} (x-1)^{-2}$$f'(x) = -2(x-1)^{-3} \cdot \frac{d}{dx}(x-1)$ [Per the Chain Rule]
$f'(x) = \frac{-2}{(x-1)^3}$
Step 3: Verification of the Identity
Our integrand is now in the form $e^x [f(x) + f'(x)]$, where:
- $f(x) = \frac{1}{(x-1)^2}$
- $f'(x) = -\frac{2}{(x-1)^3}$
Substituting these back into the integral expression:
$I = \int e^x \left[ \frac{1}{(x-1)^2} + \left( -\frac{2}{(x-1)^3} \right) \right] \, dx$Step 4: Final Integration
Applying the formula $\int e^x [f(x) + f'(x)] \, dx = e^x f(x) + C$:
$I = e^x \cdot \left( \frac{1}{(x-1)^2} \right) + C$Final Solution: $\frac{e^x}{(x-1)^2} + C$
More Questions from Class 12 Mathematics Integrals EXERCISE 7.6
- Q1: Integrate the functions in Exercises 1 to 22. 1. $x \sin x$
- Q2: Integrate the functions in Exercises 1 to 22. 2. $x \sin 3x$
- Q3: Integrate the functions in Exercises 1 to 22. 3. $x^2 e^x$
- Q4: Integrate the functions in Exercises 1 to 22. 4. $x \log x$
- Q5: Integrate the functions in Exercises 1 to 22. 5. $x \log 2x$
- Q6: Integrate the functions in Exercises 1 to 22. 6. $x^2 \log x$
- Q7: Integrate the functions in Exercises 1 to 22. 7. $x \sin^{-1} x$
- Q8: Integrate the functions in Exercises 1 to 22. 8. $x \tan^{-1} x$
- Q9: Integrate the functions in Exercises 1 to 22. 9. $x \cos^{-1} x$
- Q10: Integrate the functions in Exercises 1 to 22. 10. $(\sin^{-1} x)^2$
- Q11: Integrate the functions in Exercises 1 to 22. 11. $\frac{x \cos^{-1} x}{\sqrt{1-x^2}}$
- Q12: Integrate the functions in Exercises 1 to 22. 12. $x \sec^2 x$
- Q13: Integrate the functions in Exercises 1 to 22. 13. $\tan^{-1} x$
- Q14: Integrate the functions in Exercises 1 to 22. 14. $x (\log x)^2$
- Q15: Integrate the functions in Exercises 1 to 22. 15. $(x^2+1) \log x$
- Q16: Integrate the functions in Exercises 1 to 22. 16. $e^x(\sin x + \cos x)$
- Q17: Integrate the functions in Exercises 1 to 22. 17. $\frac{x e^x}{(1+x)^2}$
- Q18: Integrate the functions in Exercises 1 to 22. 18. $e^x (\frac{1+\sin x}{1+\cos x})$
- Q19: Integrate the functions in Exercises 1 to 22. 19. $e^x (\frac{1}{x} - \frac{1}{x^2})$
- Q21: Integrate the functions in Exercises 1 to 22. 21. $e^{2x} \sin x$
- Q22: Integrate the functions in Exercises 1 to 22. 22. $\sin^{-1} (\frac{2x}{1+x^2})$
- Q23: Choose the correct answer in Exercises 23 and 24. 23. $\int x^2 e^{x^3} dx$ equals
- Q24: Choose the correct answer in Exercises 23 and 24. 24. $\int e^x \sec x (1 + \tan x) dx$ equals
CBSE Solutions for Class 12 Mathematics Integrals
- Integrals Class 12 EXERCISE 7.1
- Integrals Class 12 EXERCISE 7.10
- Integrals Class 12 EXERCISE 7.2
- Integrals Class 12 EXERCISE 7.3
- Integrals Class 12 EXERCISE 7.4
- Integrals Class 12 EXERCISE 7.5
- Integrals Class 12 EXERCISE 7.7
- Integrals Class 12 EXERCISE 7.8
- Integrals Class 12 EXERCISE 7.9
- Integrals Class 12 Miscellaneous Exercise on Chapter 7
Chapters in CBSE - Class 12 Mathematics
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Other Subjects in CBSE - Class 12
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