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Q21:
Find the integrals of the functions in Exercises 1 to 22: 21. $\sin^{-1}(\cos x)$

Solution :

Step 1: Simplifying the Integrand

The given integral is $I = \int \sin^{-1}(\cos x) \, dx$. We utilize the trigonometric identity $\cos x = \sin\left(\frac{\pi}{2} - x\right)$ to resolve the inverse trigonometric function. [By the property of complementary angles in trigonometry].

Substituting this identity into the expression:

$I = \int \sin^{-1}\left(\sin\left(\frac{\pi}{2} - x\right)\right) \, dx$

Since the principal value branch of $\sin^{-1}(x)$ is $\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$, the expression simplifies as follows [Per the definition of the composition of inverse trigonometric functions]:

$I = \int \left(\frac{\pi}{2} - x\right) \, dx$

Step 2: Integration via Linearity Property

The integral of a sum/difference is the sum/difference of the integrals. Applying the linearity property of indefinite integrals [Per the fundamental theorem of calculus]:

$I = \int \frac{\pi}{2} \, dx - \int x \, dx$

Step 3: Executing the Integration

We apply the constant integration rule $\int a \, dx = ax + C$ and the power rule for integration $\int x^n \, dx = \frac{x^{n+1}}{n+1} + C$:

  • Integral of constant $\frac{\pi}{2}$ is $\frac{\pi}{2}x$.
  • Integral of $x^1$ is $\frac{x^{1+1}}{1+1} = \frac{x^2}{2}$.

$I = \frac{\pi}{2}x - \frac{x^2}{2} + C$

Visual Representation of the Linear Simplification

x y f(x) = π/2 - x

Step 4: Final Consolidation

Combining the terms obtained in Step 3, we arrive at the final antiderivative. $C$ represents the constant of integration, which is required for all indefinite integrals [By the definition of the antiderivative family].

Final Solution: $\frac{\pi x}{2} - \frac{x^2}{2} + C$


More Questions from Class 12 Mathematics Integrals EXERCISE 7.3


CBSE Solutions for Class 12 Mathematics Integrals


Chapters in CBSE - Class 12 Mathematics


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