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Q18:
Find the integrals of the functions in Exercises 1 to 22: 18. $\frac{\cos 2x + 2\sin^2 x}{\cos^2 x}$

Solution :

Step 1: Application of Trigonometric Identities

The integrand is given by:

$I = \int \frac{\cos 2x + 2\sin^2 x}{\cos^2 x} \, dx$

To simplify the numerator, apply the double-angle identity for cosine: $\cos 2x = 1 - 2\sin^2 x$ [Per the trigonometric identity $\cos 2\theta = 1 - 2\sin^2 \theta$].

Substituting this into the integral expression:

$I = \int \frac{(1 - 2\sin^2 x) + 2\sin^2 x}{\cos^2 x} \, dx$

Step 2: Algebraic Simplification

Observe the cancellation of the $2\sin^2 x$ terms in the numerator:

$I = \int \frac{1}{\cos^2 x} \, dx$

Utilizing the reciprocal trigonometric identity, $\frac{1}{\cos^2 x} = \sec^2 x$ [By definition of the secant function], the integral simplifies to:

$I = \int \sec^2 x \, dx$

Step 3: Integration and Final Result

Applying the standard integral formula for the square of the secant function [Per the Fundamental Theorem of Calculus/Table of Integrals]:

$\int \sec^2 x \, dx = \tan x + C$

where $C$ represents the constant of integration.

Visual Representation of the Integrand Function

y = 1 f(x) = sec²(x)

Final Solution: $\tan x + C$


More Questions from Class 12 Mathematics Integrals EXERCISE 7.3


CBSE Solutions for Class 12 Mathematics Integrals


Chapters in CBSE - Class 12 Mathematics


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