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Q2.26:
It is claimed that two cesium clocks, if allowed to run for 100 years, free from any disturbance, may differ by only about 0.02 s. What does this imply for the accuracy of the standard cesium clock in measuring a time-interval of 1 s ?

Solution :

Step 1: Identifying the Given Parameters

To determine the accuracy of a cesium clock, we must first define the total elapsed time ($T$) and the total uncertainty (drift) accumulated over that duration ($\Delta T$).

  • Total time duration ($T$): $100 \text{ years}$
  • Maximum uncertainty in $100 \text{ years}$ ($\Delta T$): $0.02 \text{ s}$

Step 2: Converting Units to SI Base Units

To perform a consistent calculation, we convert the total time ($T$) into seconds ($s$).

  • $1 \text{ year} = 365.25 \text{ days}$ (accounting for leap years)
  • $1 \text{ day} = 24 \text{ hours} \times 60 \text{ minutes} \times 60 \text{ seconds} = 86,400 \text{ s}$
  • $T = 100 \text{ years} \times 365.25 \text{ days/year} \times 86,400 \text{ s/day}$
  • $T = 3.1536 \times 10^9 \text{ s}$ [Per the standard conversion constants for time]

Step 3: Calculating Relative Accuracy

The accuracy of a measurement device is defined by its relative error or fractional uncertainty. The relative accuracy for the total duration $T$ is given by:

$\text{Relative Accuracy} = \frac{\Delta T}{T}$

Substituting the values:

$\text{Relative Accuracy} = \frac{0.02 \text{ s}}{3.1536 \times 10^9 \text{ s}}$

$\text{Relative Accuracy} \approx 6.34 \times 10^{-12}$ [By applying the ratio of error to the total measured magnitude]

Step 4: Interpreting Accuracy for a 1-second Interval

The accuracy found in Step 3 represents the drift per second. If a clock has an accuracy of $\delta t$ for a time interval of $1 \text{ s}$, it implies that for any $1 \text{ s}$ measurement, the potential error is approximately $6 \times 10^{-12} \text{ s}$.

Visual Representation of Fractional Error

t = 0 t = 1 s Uncertainty interval (Δt ≈ 6 × 10⁻¹² s)

Summary Analysis

The calculation demonstrates that the cesium clock is exceptionally precise. An accuracy of $10^{-12}$ implies that the device is reliable to within 1 part in roughly 150 billion. This confirms that the standard cesium clock provides a highly stable timekeeping reference, as the deviation is negligible over standard experimental time scales.

Final Solution: The accuracy of the standard cesium clock in measuring a time interval of 1 s is approximately $6 \times 10^{-12} \text{ s}$.


More Questions from Class 11 Physics Units and Measurements Additional Exercises


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