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Q1:
Let $A = \{1, 2, 3,...,14\}$. Define a relation $R$ from $A$ to $A$ by $R = \{(x, y) : 3x – y = 0, \text{where } x, y \in A\}$. Write down its domain, codomain and range.
Solution :
Step 1: Identifying the Set and Relation Condition
Given the set $A = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14\}$. The relation $R$ is defined on $A$ as $R = \{(x, y) : 3x - y = 0, \text{ where } x, y \in A\}$.
The condition $3x - y = 0$ can be rewritten as $y = 3x$. This establishes that for every element $x \in A$, the corresponding image $y$ must be three times the value of $x$, provided $y$ is also an element of set $A$ [Per the definition of a relation from set $A$ to set $A$].
Step 2: Tabulating Ordered Pairs $(x, y)$
We test each value of $x \in A$ to determine if $y = 3x$ results in an element within $A$:
| $x$ | $y = 3x$ | Valid $(x, y) \in R$? |
|---|---|---|
| $1$ | $3$ | Yes, $(1, 3)$ |
| $2$ | $6$ | Yes, $(2, 6)$ |
| $3$ | $9$ | Yes, $(3, 9)$ |
| $4$ | $12$ | Yes, $(4, 12)$ |
| $5$ | $15$ | No, $15 \notin A$ |
For all $x \geq 5$, $y \geq 15$, which exceeds the upper bound of set $A$. Thus, the relation in Roster form is: $R = \{(1, 3), (2, 6), (3, 9), (4, 12)\}$.
Step 3: Defining Domain, Codomain, and Range
- Domain: The set of all first components of the ordered pairs in $R$. [Per the definition of Domain in set theory].
Domain = $\{1, 2, 3, 4\}$ - Codomain: The target set $A$ from which the images are drawn. [Per the definition of a relation $R: A \to A$].
Codomain = $\{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14\}$ - Range: The set of all second components of the ordered pairs in $R$. [Per the definition of Range in set theory].
Range = $\{3, 6, 9, 12\}$
Step 4: Visualization of the Relation
Final Solution: Domain = {1, 2, 3, 4}; Codomain = {1, 2, 3, ..., 14}; Range = {3, 6, 9, 12}
More Questions from Class 11 Mathematics Relations and Functions EXERCISE 2.2
- Q2: Define a relation $R$ on the set $\mathbb{N}$ of natural numbers by $R = \{(x, y) : y = x + 5, x \text{ is a natural number less than } 4; x, y \in \mathbb{N}\}$. Depict this relationship using roster form. Write down the domain and the range.
- Q3: $A = \{1, 2, 3, 5\}$ and $B = \{4, 6, 9\}$. Define a relation $R$ from $A$ to $B$ by $R = \{(x, y): \text{the difference between } x \text{ and } y \text{ is odd}; x \in A, y \in B\}$. Write $R$ in roster form.
- Q4(i): The Fig2.7 shows a relationship between the sets $P$ and $Q$. Write this relation (i) in set-builder form. What is its domain and range?
- Q4(ii): The Fig2.7 shows a relationship between the sets $P$ and $Q$. Write this relation (ii) roster form. What is its domain and range?
- Q5(i): Let $A = \{1, 2, 3, 4, 6\}$. Let $R$ be the relation on $A$ defined by $\{(a, b): a, b \in A, b \text{ is exactly divisible by } a\}$. (i) Write $R$ in roster form.
- Q5(ii): Let $A = \{1, 2, 3, 4, 6\}$. Let $R$ be the relation on $A$ defined by $\{(a, b): a, b \in A, b \text{ is exactly divisible by } a\}$. (ii) Find the domain of $R$.
- Q5(iii): Let $A = \{1, 2, 3, 4, 6\}$. Let $R$ be the relation on $A$ defined by $\{(a, b): a, b \in A, b \text{ is exactly divisible by } a\}$. (iii) Find the range of $R$.
- Q6: Determine the domain and range of the relation $R$ defined by $R = \{(x, x + 5) : x \in \{0, 1, 2, 3, 4, 5\}\}$.
- Q7: Write the relation $R = \{(x, x^3) : x \text{ is a prime number less than } 10\}$ in roster form.
- Q8: Let $A = \{x, y, z\}$ and $B = \{1, 2\}$. Find the number of relations from $A$ to $B$.
- Q9: Let $R$ be the relation on $\mathbb{Z}$ defined by $R = \{(a,b): a, b \in \mathbb{Z}, a – b \text{ is an integer}\}$. Find the domain and range of $R$.
CBSE Solutions for Class 11 Mathematics Relations and Functions
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