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Q1(v):
Find the roots of the following quadratic equations by factorisation: (v) $100x^2 – 20x + 1 = 0$
Solution :
Given: A quadratic equation $100x^2 - 20x + 1 = 0$.
To find: The roots of the given quadratic equation using the method of factorisation.
Step 1: Identify the coefficients of the quadratic equation.
The standard form of a quadratic equation is $ax^2 + bx + c = 0$.
Comparing $100x^2 - 20x + 1 = 0$ with the standard form:
$a = 100$
$b = -20$
$c = 1$
Step 2: Determine the splitting of the middle term.
To factorise by splitting the middle term, we need to find two numbers such that:
1. Their product is equal to $a \times c = 100 \times 1 = 100$.
2. Their sum is equal to $b = -20$.
Let the two numbers be $p$ and $q$.
$p \times q = 100$
$p + q = -20$
Considering the factors of $100$: $(-10) \times (-10) = 100$ and $(-10) + (-10) = -20$.
Thus, the two numbers are $-10$ and $-10$.
Step 3: Rewrite the middle term and factorise by grouping.
Substitute $-20x$ with $-10x - 10x$ in the original equation:
$100x^2 - 10x - 10x + 1 = 0$
Group the terms into two pairs:
$(100x^2 - 10x) - (10x - 1) = 0$
Factor out the greatest common factor from each group:
$10x(10x - 1) - 1(10x - 1) = 0$
Step 4: Extract the common binomial factor.
$(10x - 1)(10x - 1) = 0$
This can be written as:
$(10x - 1)^2 = 0$
Step 5: Solve for $x$.
To find the roots, set the factor equal to zero:
$10x - 1 = 0$
$10x = 1$
$x = \frac{1}{10}$
Since the equation is a perfect square, both roots are identical:
$x = \frac{1}{10}, \frac{1}{10}$
Final Answer: The roots of the quadratic equation $100x^2 - 20x + 1 = 0$ are $\frac{1}{10}$ and $\frac{1}{10}$.
More Questions from Class 10 Mathematics Quadratic Equations EXERCISE 4.2
- Q1(i): Find the roots of the following quadratic equations by factorisation: (i) $x^2 – 3x – 10 = 0$
- Q1(ii): Find the roots of the following quadratic equations by factorisation: (ii) $2x^2 + x – 6 = 0$
- Q1(iii): Find the roots of the following quadratic equations by factorisation: (iii) $\sqrt{2}x^2 + 7x + 5\sqrt{2} = 0$
- Q1(iv): Find the roots of the following quadratic equations by factorisation: (iv) $2x^2 – x + \frac{1}{8} = 0$
- Q2: Solve the problems given below. Represent the following situations mathematically: (i) John and Jivanti together have 45 marbles. Both of them lost 5 marbles each, and the product of the number of marbles they now have is 124. We would like to find out how many marbles they had to start with. (ii) A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of toys produced in a day. On a particular day, the total cost of production was Rs.750. We would like to find out the number of toys produced on that day.
- Q3: Find two numbers whose sum is $27$ and product is $182$.
- Q4: Find two consecutive positive integers, sum of whose squares is $365$.
- Q5: The altitude of a right triangle is $7$ cm less than its base. If the hypotenuse is $13$ cm, find the other two sides.
- Q6: A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was $3$ more than twice the number of articles produced on that day. If the total cost of production on that day was ₹ $90$, find the number of articles produced and the cost of each article.
CBSE Solutions for Class 10 Mathematics Quadratic Equations
Chapters in CBSE - Class 10 Mathematics
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