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Q1(iv):
Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. (iv) $4u^2 + 8u$

Solution :

Given: A quadratic polynomial $p(u) = 4u^2 + 8u$.

To Find: The zeroes of the polynomial and verify the relationship between the zeroes and the coefficients of the polynomial.

Step 1: Finding the zeroes of the polynomial

To find the zeroes of the polynomial $p(u)$, we set $p(u) = 0$.

$4u^2 + 8u = 0$

We factor out the greatest common factor, which is $4u$:

$4u(u + 2) = 0$ [Using the distributive property of multiplication over addition]

For the product to be zero, either $4u = 0$ or $u + 2 = 0$ [Zero Product Property].

Case 1: $4u = 0 \implies u = 0$

Case 2: $u + 2 = 0 \implies u = -2$

Thus, the zeroes of the polynomial are $\alpha = 0$ and $\beta = -2$.

Step 2: Identifying coefficients

Comparing the given polynomial $4u^2 + 8u$ with the standard form $au^2 + bu + c$, we have:

$a = 4$

$b = 8$

$c = 0$

Step 3: Verifying the relationship between zeroes and coefficients

The relationships to verify are:

1. Sum of zeroes ($\alpha + \beta$) = $-\frac{b}{a}$

2. Product of zeroes ($\alpha \cdot \beta$) = $\frac{c}{a}$

Verification of Sum of Zeroes:

Sum of zeroes = $\alpha + \beta = 0 + (-2) = -2$

$-\frac{b}{a} = -\frac{8}{4} = -2$

Since $-2 = -2$, the relationship $\alpha + \beta = -\frac{b}{a}$ is verified.

Verification of Product of Zeroes:

Product of zeroes = $\alpha \cdot \beta = 0 \cdot (-2) = 0$

$\frac{c}{a} = \frac{0}{4} = 0$

Since $0 = 0$, the relationship $\alpha \cdot \beta = \frac{c}{a}$ is verified.

Final Answer: The zeroes of the polynomial $4u^2 + 8u$ are $0$ and $-2$. The relationship between the zeroes and coefficients is verified as the sum of zeroes is $-2$ and the product of zeroes is $0$.


More Questions from Class 10 Mathematics Polynomials EXERCISE 2.2


CBSE Solutions for Class 10 Mathematics Polynomials


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