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Q3(i):
Form the pair of linear equations for the following problems and find their solution by substitution method. (i) The difference between two numbers is 26 and one number is three times the other. Find them.

Solution :

Given:

1. The difference between two numbers is $26$.

2. One number is three times the other number.

To Find:

The two numbers.

Step 1: Defining the Variables

Let the larger number be $x$.

Let the smaller number be $y$.

Step 2: Formulating the Linear Equations

Based on the given conditions, we can form the following system of linear equations:

Equation (1): $x - y = 26$ [Since the difference between the two numbers is 26]

Equation (2): $x = 3y$ [Since one number is three times the other]

Step 3: Applying the Substitution Method

The substitution method involves substituting the value of one variable from one equation into the other equation.

We already have $x$ expressed in terms of $y$ in Equation (2): $x = 3y$.

Substitute $x = 3y$ into Equation (1):

$(3y) - y = 26$

Step 4: Solving for $y$

Simplify the expression:

$2y = 26$

Divide both sides by $2$:

$y = \frac{26}{2}$

$y = 13$

Step 5: Solving for $x$

Now, substitute the value of $y = 13$ back into Equation (2) to find $x$:

$x = 3y$

$x = 3(13)$

$x = 39$

Step 6: Verification

Check the results against the original conditions:

Difference: $39 - 13 = 26$ (Condition 1 satisfied)

Ratio: $39 = 3 \times 13$ (Condition 2 satisfied)

Final Answer: The two numbers are 39 and 13.


More Questions from Class 10 Mathematics Pair of linear equations in two variable EXERCISE 3.2


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