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Q7:
In each of the following, give also the justification of the construction:
Draw a circle with the help of a bangle. Take a point outside the circle. Construct the pair of tangents from this point to the circle.
Solution :
Given: A circle drawn using a bangle (the center $O$ of which is unknown) and a point $P$ located outside the circle.
To Find: Construct a pair of tangents from point $P$ to the circle and provide the geometric justification for the construction.
Visual Representation:
Step 1: Finding the Center of the Circle
Since the circle is drawn with a bangle, the center $O$ is unknown. To find it:
1. Draw two non-parallel chords $AB$ and $CD$ in the circle.
2. Construct the perpendicular bisectors of $AB$ and $CD$.
3. The point where these two perpendicular bisectors intersect is the center $O$ of the circle. [Justification: The perpendicular bisector of any chord passes through the center of the circle.]
Step 2: Construction of Tangents
1. Join the point $P$ to the center $O$ with a line segment $OP$.
2. Construct the perpendicular bisector of $OP$. Let the midpoint of $OP$ be $M$.
3. With $M$ as the center and $MO$ (or $MP$) as the radius, draw a circle. This circle will intersect the original circle at two points, say $Q$ and $R$.
4. Join $PQ$ and $PR$. These are the required tangents.
Step 3: Justification
To justify that $PQ$ and $PR$ are tangents, we must prove that $\angle OQP = 90^\circ$ and $\angle ORP = 90^\circ$.
1. Join $OQ$.
2. In the circle with diameter $OP$, $\angle OQP$ is an angle in a semicircle. [Theorem: An angle inscribed in a semicircle is a right angle.]
3. Therefore, $\angle OQP = 90^\circ$.
4. Since $OQ$ is a radius of the original circle, $PQ$ must be a tangent to the circle at $Q$. [Theorem: A line perpendicular to the radius at its point of contact is a tangent to the circle.]
5. By the same logic, joining $OR$ proves $\angle ORP = 90^\circ$, confirming $PR$ is also a tangent.
Final Answer: The construction is completed by locating the center $O$, bisecting $OP$, and drawing an auxiliary circle to find the points of tangency $Q$ and $R$. The lines $PQ$ and $PR$ are the required tangents.
More Questions from Class 10 Mathematics Constructions EXERCISE 11.2
- Q1: In each of the following, give also the justification of the construction: Draw a circle of radius 6 cm. From a point 10 cm away from its centre, construct the pair of tangents to the circle and measure their lengths.
- Q2: In each of the following, give also the justification of the construction: Construct a tangent to a circle of radius 4 cm from a point on the concentric circle of radius 6 cm and measure its length. Also verify the measurement by actual calculation.
- Q3: In each of the following, give also the justification of the construction: Draw a circle of radius 3 cm. Take two points $P$ and $Q$ on one of its extended diameter each at a distance of 7 cm from its centre. Draw tangents to the circle from these two points $P$ and $Q$.
- Q4: In each of the following, give also the justification of the construction: Draw a pair of tangents to a circle of radius 5 cm which are inclined to each other at an angle of $60^{\circ}$.
- Q5: In each of the following, give also the justification of the construction: Draw a line segment $AB$ of length 8 cm. Taking $A$ as centre, draw a circle of radius 4 cm and taking $B$ as centre, draw another circle of radius 3 cm. Construct tangents to each circle from the centre of the other circle.
- Q6: In each of the following, give also the justification of the construction: Let ABC be a right triangle in which $AB = 6$ cm, $BC = 8$ cm and $\angle B = 90^{\circ}$. $BD$ is the perpendicular from $B$ on $AC$. The circle through $B$, $C$, $D$ is drawn. Construct the tangents from $A$ to this circle.
CBSE Solutions for Class 10 Mathematics Constructions
Chapters in CBSE - Class 10 Mathematics
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