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Q1(ii):
$A$ and $B$ are two events such that $P(A) \neq 0$. Find $P(B|A)$, if (ii) $A \cap B = \phi$

Solution :

Step 1: Identifying the Conditional Probability Formula

The conditional probability of an event $B$ occurring given that event $A$ has already occurred is defined by the multiplication rule of probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

[Per the definition of conditional probability for any two events $A$ and $B$ where $P(A) \neq 0$]

Step 2: Analyzing the Given Condition

The problem states that $A \cap B = \phi$, where $\phi$ denotes the empty set (or null event). In probability theory, the probability of an impossible or empty event is defined as:

$P(A \cap B) = P(\phi) = 0$

[By the Axiom of Probability, the measure of the empty set in the sample space $S$ is zero]

Step 3: Calculating $P(B|A)$

Substitute the value obtained in Step 2 into the formula established in Step 1:

$P(B|A) = \frac{0}{P(A)}$

Since the problem provides the constraint $P(A) \neq 0$, the expression is well-defined and evaluates as follows:

$P(B|A) = 0$

Visual Representation of Mutually Exclusive Events

Sample Space (S) A B A ∩ B = φ (Mutually Exclusive)

Final Solution: $P(B|A) = 0$


More Questions from Class 12 Mathematics Probability Miscellaneous Exercise on Chapter 13


CBSE Solutions for Class 12 Mathematics Probability


Chapters in CBSE - Class 12 Mathematics


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