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Q15:
Evaluate the definite integrals in Exercises 1 to 20. 15. $\int_{0}^{1} x e^{x^2} dx$

Solution :

Step 1: Setting up the Integral and Identifying the Method

We are tasked with evaluating the definite integral:

$I = \int_{0}^{1} x e^{x^2} dx$

Given the integrand is a composition of functions where the derivative of the exponent ($x^2$) is proportional to the multiplier ($x$), we employ the Method of Substitution [Per the substitution rule for definite integrals].

Step 2: Performing Algebraic Substitution

Let $u = x^2$.

Differentiating both sides with respect to $x$:

$\frac{du}{dx} = 2x \implies du = 2x dx \implies x dx = \frac{1}{2} du$

Step 3: Transforming the Limits of Integration

We must adjust the limits of integration from the variable $x$ to the variable $u$ using the relation $u = x^2$:

  • When $x = 0$, $u = (0)^2 = 0$.
  • When $x = 1$, $u = (1)^2 = 1$.

[By the Fundamental Theorem of Calculus, the transformation of bounds is required when performing change of variables].

Step 4: Substitution and Evaluation

Substituting $u$ and $du$ into the original integral:

$I = \int_{0}^{1} e^u \left( \frac{1}{2} du \right)$

$I = \frac{1}{2} \int_{0}^{1} e^u du$

Evaluating the antiderivative [Per the integration rule $\int e^u du = e^u + C$]:

$I = \frac{1}{2} [e^u]_{0}^{1}$

$I = \frac{1}{2} (e^1 - e^0)$

Step 5: Final Simplification

Since $e^0 = 1$ [By the zero exponent rule in algebra]:

$I = \frac{1}{2} (e - 1)$

Visual Representation of the Area under the Curve

x y 0 1 y = x e^{x^2}

Final Solution: \frac{e-1}{2}


More Questions from Class 12 Mathematics Integrals EXERCISE 7.8


CBSE Solutions for Class 12 Mathematics Integrals


Chapters in CBSE - Class 12 Mathematics


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