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Q7:
Integrate the functions in Exercises 1 to 23. 7. $\frac{x-1}{\sqrt{x^2-1}}$

Solution :

Step 1: Decomposition of the Integrand

The given integral is $I = \int \frac{x-1}{\sqrt{x^2-1}} dx$. We split the integral into two distinct parts to facilitate different integration techniques [By the linearity property of integration]:

$I = \int \frac{x}{\sqrt{x^2-1}} dx - \int \frac{1}{\sqrt{x^2-1}} dx$

Let $I_1 = \int \frac{x}{\sqrt{x^2-1}} dx$ and $I_2 = \int \frac{1}{\sqrt{x^2-1}} dx$. Thus, $I = I_1 - I_2$.

Step 2: Solving $I_1$ via Substitution

For $I_1 = \int \frac{x}{\sqrt{x^2-1}} dx$, we utilize the method of substitution [By the substitution rule for indefinite integrals]:

  • Let $u = x^2 - 1$.
  • Differentiating with respect to $x$, $du = 2x \, dx$, which implies $x \, dx = \frac{du}{2}$.

$I_1 = \int \frac{1}{\sqrt{u}} \cdot \frac{du}{2} = \frac{1}{2} \int u^{-1/2} du$

Applying the power rule $\int u^n du = \frac{u^{n+1}}{n+1} + C$:

$I_1 = \frac{1}{2} \left( \frac{u^{1/2}}{1/2} \right) = \sqrt{u} + C_1 = \sqrt{x^2-1} + C_1$

Step 3: Solving $I_2$ via Standard Formula

For $I_2 = \int \frac{1}{\sqrt{x^2-1}} dx$, we apply the standard integral formula [Per the table of integrals for algebraic forms]:

$\int \frac{1}{\sqrt{x^2-a^2}} dx = \ln|x + \sqrt{x^2-a^2}| + C$

Given $a = 1$, we have:

$I_2 = \ln|x + \sqrt{x^2-1}| + C_2$

Step 4: Synthesis of the Final Result

Combining the results from Step 2 and Step 3 into our expression from Step 1:

$I = I_1 - I_2 = \sqrt{x^2-1} - \ln|x + \sqrt{x^2-1}| + C$

Integral Breakdown Strategy: 1. Linearity: Split x/sqrt(x²-1) and -1/sqrt(x²-1) 2. Integration: Substitution for I₁, Standard form for I₂ 3. Aggregation: Final expression with constant C

Final Solution: $\sqrt{x^2-1} - \ln|x + \sqrt{x^2-1}| + C$


More Questions from Class 12 Mathematics Integrals EXERCISE 7.4


CBSE Solutions for Class 12 Mathematics Integrals


Chapters in CBSE - Class 12 Mathematics


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