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Q2(i):
Evaluate the determinant: (i) $\begin{vmatrix} \cos\theta & -\sin\theta \\ \sin\theta & \cos\theta \end{vmatrix}$

Solution :

Step 1: Theoretical Foundation of a $2 \times 2$ Determinant

For any square matrix of order $2$, defined as $A = \begin{pmatrix} a & b \\ c & d \end{pmatrix}$, the determinant is calculated using the formula:
$\det(A) = |A| = (ad) - (bc)$
[Per the definition of the determinant of a $2 \times 2$ matrix].

Step 2: Assigning Variables from the Given Matrix

Given the determinant $\begin{vmatrix} \cos\theta & -\sin\theta \\ \sin\theta & \cos\theta \end{vmatrix}$, we identify the elements as follows:

  • $a = \cos\theta$
  • $b = -\sin\theta$
  • $c = \sin\theta$
  • $d = \cos\theta$

Step 3: Execution of the Determinant Calculation

Substituting the variables into the formula $(ad - bc)$:

$\Delta = (\cos\theta)(\cos\theta) - (-\sin\theta)(\sin\theta)$

$\Delta = \cos^2\theta - (-\sin^2\theta)$

$\Delta = \cos^2\theta + \sin^2\theta$

Step 4: Simplification via Trigonometric Identity

Applying the fundamental Pythagorean identity of trigonometry:
$\cos^2\theta + \sin^2\theta = 1$
[Per the Fundamental Trigonometric Identity].

Step 5: Visual Representation

cos θ -sin θ sin θ cos θ = cos²θ + sin²θ = 1

Final Solution: 1


More Questions from Class 12 Mathematics Determinants EXERCISE 4.1


CBSE Solutions for Class 12 Mathematics Determinants


Chapters in CBSE - Class 12 Mathematics


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