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Q15:
The total cost $C(x)$ in Rupees associated with the production of $x$ units of an item is given by $C(x) = 0.007x^3 – 0.003x^2 + 15x + 4000$. Find the marginal cost when $17$ units are produced.

Solution :

Step 1: Theoretical Definition of Marginal Cost

The marginal cost ($MC$) represents the instantaneous rate of change of the total cost function $C(x)$ with respect to the number of units $x$ produced. Mathematically, it is defined as the first derivative of the total cost function [Per the definition of derivative as the rate of change]:

$MC = \frac{d}{dx}[C(x)]$

Step 2: Differentiating the Cost Function

Given the total cost function: $C(x) = 0.007x^3 - 0.003x^2 + 15x + 4000$.

Applying the Power Rule $\frac{d}{dx}(ax^n) = anx^{n-1}$ to each term individually [Per the linearity property of differentiation]:

$\frac{d}{dx}(0.007x^3) = 0.007 \cdot 3x^2 = 0.021x^2$

$\frac{d}{dx}(-0.003x^2) = -0.003 \cdot 2x = -0.006x$

$\frac{d}{dx}(15x) = 15 \cdot 1 = 15$

$\frac{d}{dx}(4000) = 0$ [Since the derivative of a constant is zero]

Thus, $MC(x) = 0.021x^2 - 0.006x + 15$.

Step 3: Calculating Marginal Cost for $x = 17$

Substitute $x = 17$ into the expression for $MC(x)$:

$MC(17) = 0.021(17)^2 - 0.006(17) + 15$

$MC(17) = 0.021(289) - 0.102 + 15$

$MC(17) = 6.069 - 0.102 + 15$

$MC(17) = 5.967 + 15$

$MC(17) = 20.967$

Step 4: Visualizing the Marginal Cost Trend

Units (x) MC(x) MC(17) ≈ 20.97

Final Solution: The marginal cost when 17 units are produced is Rupees 20.967.


More Questions from Class 12 Mathematics Application of Derivatives EXERCISE 6.1


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