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Q5.6:
A reaction, (A + B \rightarrow C + D + q) is found to have a positive entropy change. The reaction will be

Solution :

Step 1: Theoretical Foundation of Spontaneity

The spontaneity of a reaction at constant temperature ($T$) and pressure ($P$) is governed by the change in Gibbs Free Energy ($\Delta G$), defined by the Gibbs-Helmholtz equation:

$$\Delta G = \Delta H - T\Delta S$$

[Per the Second Law of Thermodynamics, a process is spontaneous if $\Delta G < 0$].

Step 2: Analysis of the Given Reaction Variables

The reaction is given as: $A + B \rightarrow C + D + q$.

  • Enthalpy Change ($\Delta H$): The presence of $+ q$ in the product side indicates that energy is released into the surroundings. Therefore, the reaction is exothermic, implying $\Delta H < 0$.
  • Entropy Change ($\Delta S$): The problem explicitly states that the reaction has a positive entropy change, implying $\Delta S > 0$.

Step 3: Evaluating the Gibbs Free Energy Equation

Substitute the signs of the variables into the Gibbs-Helmholtz equation:

$$\Delta G = (\text{negative}) - T(\text{positive})$$

Since the temperature $T$ (in Kelvin) is always positive, the term $-T\Delta S$ will be negative.

$$\Delta G = (\text{negative}) - (\text{positive}) = \text{negative}$$

[By the algebraic summation of negative values, the resultant $\Delta G$ must be negative regardless of the magnitude of $T$].

Step 4: Graphical Representation of Thermodynamic Spontaneity

Temperature (T) ΔG ΔG = ΔH - TΔS Spontaneous at all T

Step 5: Conclusion on Reaction Nature

Because $\Delta H < 0$ and $\Delta S > 0$, the condition $\Delta G < 0$ is satisfied at all temperatures. A reaction where $\Delta G$ is always negative is defined as a spontaneous reaction.

Final Solution: The reaction will be spontaneous at all temperatures.


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