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Q11.22(c):
Answer the following questions based on the P – T phase diagram of $CO_2$: (c) Describe qualitatively the changes in a given mass of solid $CO_2$ at 10 atm pressure and temperature –65 °C as it is heated up to room temperature at constant pressure.

Solution :

Initial State and Thermodynamic Coordinates

Given the initial state of the carbon dioxide ($CO_2$) sample:

  • Pressure ($P$): $10\text{ atm}$
  • Temperature ($T$): $-65\text{ °C}$
  • Phase: Solid ($CO_2$ ice/dry ice)
[Per the $P-T$ phase diagram of $CO_2$, the triple point is located at $P = 5.11\text{ atm}$ and $T = -56.6\text{ °C}$]. Since the applied pressure ($10\text{ atm}$) is significantly above the triple point pressure, and the temperature ($-65\text{ °C}$) is well below the sublimation/fusion thresholds, the sample exists in the stable solid phase.

Phase Transition Analysis

As the system is heated at a constant pressure of $10\text{ atm}$, it traverses the following path in the $P-T$ coordinate plane:

  1. Heating the Solid: The temperature increases from $-65\text{ °C}$. The solid $CO_2$ undergoes sensible heating, increasing in internal energy without a phase change until the fusion curve is intersected.
  2. Melting (Solid to Liquid): At $10\text{ atm}$, the melting point of $CO_2$ is approximately $-56\text{ °C}$. Upon reaching this temperature, the solid absorbs latent heat of fusion [Per the First Law of Thermodynamics, $dQ = dU + PdV$]. The phase transition from solid to liquid occurs while the temperature remains constant during the phase change.
  3. Heating the Liquid: Once the mass is entirely in the liquid phase, further heating causes the temperature of the liquid $CO_2$ to rise.
  4. Vaporization (Liquid to Gas): As heating continues toward room temperature ($20\text{ °C}$–$25\text{ °C}$), the system approaches the boiling point. At $10\text{ atm}$, which is lower than the critical pressure of $CO_2$ ($73\text{ atm}$), the liquid will eventually cross the vaporization curve and undergo a phase change into the gaseous state (vapor).

Visual Representation of the Phase Transition Path

T P Solid Liquid Gas 10 atm isobar Start

Summary of Thermodynamic Evolution

The progression of the system can be summarized by the following table:

Phase Temperature Range Mechanism
Solid $-65\text{ °C}$ to $\approx -56\text{ °C}$ Sensible heating of solid
Solid + Liquid $\approx -56\text{ °C}$ Latent heat of fusion
Liquid $-56\text{ °C}$ to $T_{boiling}$ Sensible heating of liquid
Gas $T_{boiling}$ to Room Temp Expansion/Vaporization

Final Solution: The solid $CO_2$ first undergoes sensible heating, then melts into liquid $CO_2$ at approximately $-56\text{ °C}$, and finally, as heating continues toward room temperature at $10\text{ atm}$, the liquid will eventually vaporize into gas.


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