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Q12.6:
Estimate the total number of air molecules (inclusive of oxygen, nitrogen, water vapour and other constituents) in a room of capacity (25.0 \text{ m}^{3}) at a temperature of (27 °\text{C}) and 1 atm pressure.
Solution :
Step 1: Given Variables and Initial Setup
To estimate the total number of air molecules, we utilize the Ideal Gas Equation. The state variables are provided as follows:
- Volume ($V$) = $25.0 \text{ m}^3$
- Temperature ($T$) = $27 \text{ °C} = 27 + 273.15 = 300.15 \text{ K} \approx 300 \text{ K}$ [Per the thermodynamic conversion to Kelvin]
- Pressure ($P$) = $1 \text{ atm} = 1.013 \times 10^5 \text{ Pa}$ [Standard atmospheric pressure definition]
- Boltzmann Constant ($k_B$) = $1.38 \times 10^{-23} \text{ J/K}$ [Physical constant]
Step 2: Selecting the Governing Equation
The Ideal Gas Law in terms of the number of molecules ($N$) is expressed as: $$PV = Nk_BT$$ where $P$ is pressure, $V$ is volume, $N$ is the number of molecules, $k_B$ is the Boltzmann constant, and $T$ is the absolute temperature. [Reference: Kinetic Theory of Gases, Ideal Gas Equation derivation]
Step 3: Algebraic Manipulation
To solve for $N$, we rearrange the equation: $$N = \frac{PV}{k_BT}$$
Step 4: Numerical Calculation
Substitute the given values into the rearranged equation:
$$N = \frac{(1.013 \times 10^5 \text{ Pa}) \times (25.0 \text{ m}^3)}{(1.38 \times 10^{-23} \text{ J/K}) \times (300 \text{ K})}$$
Perform the calculation in the denominator: $$(1.38 \times 10^{-23}) \times 300 = 4.14 \times 10^{-21} \text{ J}$$
Perform the calculation in the numerator: $$(1.013 \times 10^5) \times 25.0 = 25.325 \times 10^5 = 2.5325 \times 10^6 \text{ J}$$
Complete the division: $$N = \frac{2.5325 \times 10^6}{4.14 \times 10^{-21}} \approx 0.6117 \times 10^{27}$$ $$N \approx 6.12 \times 10^{26} \text{ molecules}$$
Visual Representation of Kinetic Distribution
Step 5: Analysis of Results
The calculated value represents the total ensemble of gas molecules within the enclosed volume. The result is independent of the chemical composition (Oxygen, Nitrogen, etc.) because, per Avogadro’s Hypothesis and the Kinetic Theory of Gases, all gases behave identically under the assumption of ideal gas behavior at these standard conditions. [Justification: Kinetic theory assumes negligible molecular volume and elastic collisions, which holds true for air at room temperature and pressure.]
Final Solution: The total number of air molecules in the room is approximately $6.12 \times 10^{26}$.
More Questions from Class 11 Physics Kinetic Theory EXERCISES
- Q12.1: Estimate the fraction of molecular volume to the actual volume occupied by oxygen gas at STP. Take the diameter of an oxygen molecule to be 3 Å.
- Q12.10: Estimate the mean free path and collision frequency of a nitrogen molecule in a cylinder containing nitrogen at 2.0 atm and temperature (17 °\text{C}). Take the radius of a nitrogen molecule to be roughly 1.0 Å. Compare the collision time with the time the molecule moves freely between two successive collisions (Molecular mass of (N_{2}) = 28.0 u).
- Q12.2: Molar volume is the volume occupied by 1 mol of any (ideal) gas at standard temperature and pressure (STP : 1 atmospheric pressure, (0 °\text{C})). Show that it is 22.4 litres.
- Q12.3 (a): Figure 12.8 shows plot of (\frac{PV}{T}) versus (P) for (1.00 \times 10^{-3}) kg of oxygen gas at two different temperatures. (a) What does the dotted plot signify?
- Q12.3 (b): Figure 12.8 shows plot of (\frac{PV}{T}) versus (P) for (1.00 \times 10^{-3}) kg of oxygen gas at two different temperatures. (b) Which is true: (T_{1} > T_{2}) or (T_{1} < T_{2})?
- Q12.3 (c): Figure 12.8 shows plot of (\frac{PV}{T}) versus (P) for (1.00 \times 10^{-3}) kg of oxygen gas at two different temperatures. (c) What is the value of (\frac{PV}{T}) where the curves meet on the y-axis?
- Q12.3 (d): Figure 12.8 shows plot of (\frac{PV}{T}) versus (P) for (1.00 \times 10^{-3}) kg of oxygen gas at two different temperatures. (d) If we obtained similar plots for (1.00 \times 10^{-3}) kg of hydrogen, would we get the same value of (\frac{PV}{T}) at the point where the curves meet on the y-axis? If not, what mass of hydrogen yields the same value of (\frac{PV}{T}) (for low pressure high temperature region of the plot) ? (Molecular mass of (H_{2}) = 2.02 u, of (O_{2}) = 32.0 u, (R) = 8.31 J (\text{mol}^{-1}) (\text{K}^{-1}).)
- Q12.4: An oxygen cylinder of volume 30 litre has an initial gauge pressure of 15 atm and a temperature of (27 °\text{C}). After some oxygen is withdrawn from the cylinder, the gauge pressure drops to 11 atm and its temperature drops to (17 °\text{C}). Estimate the mass of oxygen taken out of the cylinder ((R) = 8.31 J (\text{mol}^{-1}) (\text{K}^{-1}), molecular mass of (O_{2}) = 32 u).
- Q12.5: An air bubble of volume (1.0 \text{ cm}^{3}) rises from the bottom of a lake 40 m deep at a temperature of (12 °\text{C}). To what volume does it grow when it reaches the surface, which is at a temperature of (35 °\text{C}) ?
- Q12.7 (i): Estimate the average thermal energy of a helium atom at (i) room temperature ((27 °\text{C})),
- Q12.7 (ii): Estimate the average thermal energy of a helium atom at (ii) the temperature on the surface of the Sun (6000 K),
- Q12.7 (iii): Estimate the average thermal energy of a helium atom at (iii) the temperature of 10 million kelvin (the typical core temperature in the case of a star).
- Q12.8: Three vessels of equal capacity have gases at the same temperature and pressure. The first vessel contains neon (monatomic), the second contains chlorine (diatomic), and the third contains uranium hexafluoride (polyatomic). Do the vessels contain equal number of respective molecules ? Is the root mean square speed of molecules the same in the three cases? If not, in which case is (v_{rms}) the largest ?
- Q12.9: At what temperature is the root mean square speed of an atom in an argon gas cylinder equal to the rms speed of a helium gas atom at (– 20 °\text{C}) ? (atomic mass of Ar = 39.9 u, of He = 4.0 u).
- Q13.1: Estimate the fraction of molecular volume to the actual volume occupied by oxygen gas at STP. Take the diameter of an oxygen molecule to be 3 Å.
- Q13.10: Estimate the mean free path and collision frequency of a nitrogen molecule in a cylinder containing nitrogen at 2.0 atm and temperature 17 0C. Take the radius of a nitrogen molecule to be roughly 1.0 Å. Compare the collision time with the time the molecule moves freely between two successive collisions (Molecular mass of $N_2$ = 28.0 u).
- Q13.2: Molar volume is the volume occupied by 1 mol of any (ideal) gas at standard temperature and pressure (STP : 1 atmospheric pressure, 0 °C). Show that it is 22.4 litres.
- Q13.3(a): Figure 13.8 shows plot of $frac{PV}{T}$ versus $P$ for $1.00 \times 10^{-3}$ kg of oxygen gas at two different temperatures. (a) What does the dotted plot signify?
- Q13.3(b): Figure 13.8 shows plot of $frac{PV}{T}$ versus $P$ for $1.00 \times 10^{-3}$ kg of oxygen gas at two different temperatures. (b) Which is true: $T_1 > T_2$ or $T_1 < T_2$?
- Q13.3(c): Figure 13.8 shows plot of $frac{PV}{T}$ versus $P$ for $1.00 \times 10^{-3}$ kg of oxygen gas at two different temperatures. (c) What is the value of $frac{PV}{T}$ where the curves meet on the y-axis?
- Q13.3(d): Figure 13.8 shows plot of $frac{PV}{T}$ versus $P$ for $1.00 \times 10^{-3}$ kg of oxygen gas at two different temperatures. (d) If we obtained similar plots for $1.00 \times 10^{-3}$ kg of hydrogen, would we get the same value of $frac{PV}{T}$ at the point where the curves meet on the y-axis? If not, what mass of hydrogen yields the same value of $frac{PV}{T}$ (for low pressure high temperature region of the plot) ? (Molecular mass of $H_2$ = 2.02 u, of $O_2$ = 32.0 u, $R = 8.31$ J $mol^{-1} K^{-1}$.)
- Q13.4: An oxygen cylinder of volume 30 litres has an initial gauge pressure of 15 atm and a temperature of 27 °C. After some oxygen is withdrawn from the cylinder, the gauge pressure drops to 11 atm and its temperature drops to 17 °C. Estimate the mass of oxygen taken out of the cylinder ($R = 8.31$ J $mol^{-1} K^{-1}$, molecular mass of $O_2$ = 32 u).
- Q13.5: An air bubble of volume 1.0 $cm^3$ rises from the bottom of a lake 40 m deep at a temperature of 12 °C. To what volume does it grow when it reaches the surface, which is at a temperature of 35 °C ?
- Q13.6: Estimate the total number of air molecules (inclusive of oxygen, nitrogen, water vapour and other constituents) in a room of capacity 25.0 $m^3$ at a temperature of 27 °C and 1 atm pressure.
- Q13.7(i): Estimate the average thermal energy of a helium atom at (i) room temperature (27 °C),
- Q13.7(ii): Estimate the average thermal energy of a helium atom at (ii) the temperature on the surface of the Sun (6000 K),
- Q13.7(iii): Estimate the average thermal energy of a helium atom at (iii) the temperature of 10 million kelvin (the typical core temperature in the case of a star).
- Q13.8: Three vessels of equal capacity have gases at the same temperature and pressure. The first vessel contains neon (monatomic), the second contains chlorine (diatomic), and the third contains uranium hexafluoride (polyatomic). Do the vessels contain equal number of respective molecules ? Is the root mean square speed of molecules the same in the three cases? If not, in which case is $v_{rms}$ the largest ?
- Q13.9: At what temperature is the root mean square speed of an atom in an argon gas cylinder equal to the rms speed of a helium gas atom at – 20 °C ? (atomic mass of $Ar$ = 39.9 u, of $He$ = 4.0 u).
CBSE Solutions for Class 11 Physics Kinetic Theory
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