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Q5(ii):
Find the range of each of the following functions. (ii) $f(x) = x^2 + 2$, $x$ is a real number.

Solution :

Step 1: Identifying the Domain and Function Definition

Given the function $f(x) = x^2 + 2$, where $x \in \mathbb{R}$ (the set of all real numbers). The domain is defined as the set of all possible input values for $x$, which is $(-\infty, \infty)$.

Step 2: Analyzing the Square Property of Real Numbers

By the definition of real numbers, the square of any real number is always non-negative [Axiom of non-negativity in ordered fields]:

For all $x \in \mathbb{R}$, $x^2 \geq 0$.

Step 3: Transforming the Inequality to Match the Function

To determine the range, we must transform $x^2$ into $x^2 + 2$ by applying the Addition Property of Inequalities [Property of Ordered Fields]:

Add $2$ to both sides of the inequality $x^2 \geq 0$:

$x^2 + 2 \geq 0 + 2$

$x^2 + 2 \geq 2$

Step 4: Establishing the Range

Since $f(x) = x^2 + 2$, we conclude that $f(x) \geq 2$. The range is the set of all output values $y$ such that $y = f(x)$. Therefore, the range of the function is the interval $[2, \infty)$.

x f(x) 2 (0, 2)

Final Solution: The range of the function $f(x) = x^2 + 2$ is $[2, \infty)$.


More Questions from Class 11 Mathematics Relations and Functions EXERCISE 2.3


CBSE Solutions for Class 11 Mathematics Relations and Functions


Chapters in CBSE - Class 11 Mathematics


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