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Q4(c)(i):
A card is selected from a pack of 52 cards. (c) Calculate the probability that the card is (i) an ace

Solution :

Step 1: Identifying the Sample Space

In a standard deck of cards, the total number of distinct outcomes ($n(S)$) is defined by the total number of cards in the pack.

$n(S) = 52$ [Definition of a standard deck probability space].

Step 2: Defining the Event and Favorable Outcomes

Let $E$ be the event of drawing an 'Ace'. A standard deck contains four suits (Hearts, Diamonds, Clubs, and Spades), and each suit contains exactly one Ace.

$n(E) = 4$ [By the structure of standard 52-card decks].

Step 3: Calculating Probability

The probability $P(E)$ of an event occurring is defined by the ratio of favorable outcomes to the total sample space:

$P(E) = \frac{n(E)}{n(S)}$ [Laplace's Definition of Classical Probability].

Substituting the values:

$P(E) = \frac{4}{52}$

Step 4: Simplifying the Fraction

To reduce the fraction, find the greatest common divisor (GCD) of 4 and 52, which is 4:

$P(E) = \frac{4 \div 4}{52 \div 4} = \frac{1}{13}$

Visualization of the Card Distribution

Deck Size (Total): 52 Aces in Deck: 4 Probability Calculation: P(Ace) = 4/52 = 1/13 A

Final Solution: The probability of selecting an Ace from a deck of 52 cards is $\frac{1}{13}$.


More Questions from Class 11 Mathematics Probability EXERCISE 14.2


CBSE Solutions for Class 11 Mathematics Probability


Chapters in CBSE - Class 11 Mathematics


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