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Q4:
Express the complex number $3(7 + i7) + i(7 + i7)$ in the form $a + ib$.

Solution :

Step 1: Application of Distributive Property

To simplify the complex expression $3(7 + i7) + i(7 + i7)$, we must first distribute the scalar and imaginary multipliers across the terms within the parentheses [Per the Distributive Property of Multiplication over Addition: $a(b + c) = ab + ac$].

$3(7 + i7) = (3 \times 7) + (3 \times i7) = 21 + 21i$
$i(7 + i7) = (i \times 7) + (i \times i7) = 7i + 7i^2$

Step 2: Substitution and Simplification of Powers of $i$

We recall the fundamental property of the imaginary unit, where $i^2 = -1$ [Per the definition of the Imaginary Unit in the Complex Number System].

Substituting $i^2 = -1$ into the second expanded expression:

$7i + 7(-1) = 7i - 7 = -7 + 7i$

Step 3: Combining the Terms

Now, we sum the results from Step 1 and Step 2 to achieve the form $a + ib$:

Expression $= (21 + 21i) + (-7 + 7i)$

Group the real parts and the imaginary parts separately [Per the Associative and Commutative properties of complex addition]:

$= (21 - 7) + (21i + 7i)$
$= 14 + 28i$

Visual Representation of the Complex Vector

Re Im (14, 28i)

Analytical Summary Table

Operation Resulting Expression
Initial Distribution $21 + 21i + 7i + 7i^2$
Substitute $i^2 = -1$ $21 + 21i + 7i - 7$
Combine Real Components $21 - 7 = 14$
Combine Imaginary Components $21i + 7i = 28i$

Final Solution: $14 + 28i$


More Questions from Class 11 Mathematics Complex Numbers EXERCISE 4.1


CBSE Solutions for Class 11 Mathematics Complex Numbers


Chapters in CBSE - Class 11 Mathematics


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