UrbanPro

Location Set your Location

Login Ask & Answer Success Stories Paid Courses Free Classes Tuition & Classes Fees Write a Review All Categories Help Center
Post your Learning Need Signup as a Tutor
✕

Popular Cities

Bangalore

Hyderabad

Delhi

Mumbai

Chennai

Pune

Kolkata

Gurgaon

Ahmedabad

Jaipur

Noida

✕
true
Ritika M. IGCSE Tuition Classes trainer in Bangalore

Ritika M.

Trained teacher, passionate about simplifying Chemistry

Indiranagar, Bangalore, India - 560038.

Contact
Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Ritika M.✕

Identity

Education

Know how UrbanPro verifies Tutor details

Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

I am currently pursuing my B.Ed. to enable myself to be better equipped as a teacher. I have a master's degree in chemistry and a bachelor's degree in physics, chemistry and mathematics. I also have research experience.
I am passionate about teaching and my aim is to develop a love for the subject. I believe that a good foundation and proper understanding of fundamental concepts can make any subject interesting, especially with chemistry which is often hated.
I can teach Chemistry for CBSE, ICSE and State boards.
I am patient with students and will go down to their level to address the issues that are hindering their progress.

Languages Spoken

English Mother Tongue (Native)

Kannada Basic

Tamil Basic

Education

New Horizon College of Education Pursuing

Bachelor of Education (B.Ed.)

Christ university 2015

Bachelor of Science (B.Sc.)

St Joseph's College of Arts and Science 2017

Master of Science (M.Sc.)

Address

Indiranagar, Bangalore, India - 560038

Verified Info

ID Verified

Phone Verified

Email Verified

Report this Profile

✕
x

Is this listing inaccurate or duplicate? Any other problem?

Please tell us about the problem and we will fix it.

Please describe the problem that you see in this page.

Type the letters as shown below *

Please enter the letters as show below

Teaches

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

3

Board

ICSE, IGCSE

Preferred class strength

Group Classes, One on one/ Private Tutions

ICSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Experience in School or College

Teaching at an international school for grades 9 to 12.

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

ICSE, IGCSE

Preferred class strength

Group Classes, One on one/ Private Tutions

ICSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Taught in School or College

Yes

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

AS/A levels, ISC/ICSE

Preferred class strength

Group Classes, One on one/ Private Tutions

ISC/ICSE Subjects taught

Chemistry

Taught in School or College

Yes

AS/A Level Subject

Chemistry

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

ICSE and IGCSE

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 3 years.

Contact

Answers by Ritika M. (4)

Answered on 24/09/2019 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/Intext Exercise 8.4

A racing car has a uniform acceleration of 4 m s−2. What distance will it cover in 10 s after start? ...more

Given data, Initial velocity, u= 0m/s (body is starting from rest) Time, t = 10s Acceleration, a = 4ms-2 Distance covered, S, S= ut + 1/2 at2 = 0 x 10 + 1/2 ( 4x10x10) = 2x10x10 = 200m. Thus, the distance travelled is 200m ...more

Given data,

Initial velocity, u= 0m/s (body is starting from rest)

Time, t = 10s

Acceleration, a = 4ms-2

Distance covered, S,

S= ut + 1/2 at2

= 0 x 10 + 1/2 ( 4x10x10)

= 2x10x10

= 200m.

Thus, the distance travelled is 200m
Answers 5 Comments
Dislike Bookmark

Answered on 24/09/2019 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/Intext Exercise 8.1

An object has moved through a distance. Can it have zero displacement? If yes, support your answer with an example?

Yes, if an object has moved through a distance, it can have zero displacement. This is true if the initial position of the body and final position of the body are the same. Consider a man moving from point A to point B , covering a distance of 10m. If he returns to point A , the distance travelled... ...more

Yes, if an object has moved through a distance, it can have zero displacement.

This is true if the initial position of the body and final position of the body are the same.

Consider a man moving from point A to point B , covering a distance of 10m.

If he returns to point A , the distance travelled by him will be 2x10m but his displacement is zero as there is no possiblity of the shortest path as the final and initial positions are the same.

Answers 3 Comments
Dislike Bookmark

Answered on 24/09/2019 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/Intext Exercise 8.4

What can you say about the motion of an object whose distance−time graph is a straight line... ...more

If the distance- time graph is a straight line parallel to the time axis, the body is in a state of rest.
Answers 5 Comments
Dislike Bookmark

Answered on 24/09/2019 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/Intext Exercise 8.4

A bus starting from rest moves with a uniform acceleration of 0.1 m s−2 for 2 minutes. Find (a)... ...more

A bus starting from rest moves with a uniform acceleration of 0.1 m s−2 for 2 minutes. Find (a) the speed acquired, (b) the distance travelled.

Given data Initial velocity, u = 0 m/s Acceleration , a= 0.1m/S2 Time, t = 2min= 120s Speed acquired, v= u +at = 0+ 0.1x120 = 12m/s. The speed acquired is 12m/s Distance travelled, S= ut + 1/2at2 = 0 + 1/2 ( 0.1x120x120) = 0.1x120x60 = 720m The distance travelled is 720m. ...more

Given data

Initial velocity, u = 0 m/s

Acceleration , a= 0.1m/S2

Time, t = 2min= 120s

Speed acquired,

v= u +at

= 0+ 0.1x120

= 12m/s.

The speed acquired is 12m/s

Distance travelled, 

S= ut + 1/2at2

= 0 + 1/2 ( 0.1x120x120)

= 0.1x120x60

=  720m

 

The distance travelled is 720m.

 

Answers 5 Comments
Dislike Bookmark

Contact

Teaches

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

3

Board

ICSE, IGCSE

Preferred class strength

Group Classes, One on one/ Private Tutions

ICSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Experience in School or College

Teaching at an international school for grades 9 to 12.

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

ICSE, IGCSE

Preferred class strength

Group Classes, One on one/ Private Tutions

ICSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Taught in School or College

Yes

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

AS/A levels, ISC/ICSE

Preferred class strength

Group Classes, One on one/ Private Tutions

ISC/ICSE Subjects taught

Chemistry

Taught in School or College

Yes

AS/A Level Subject

Chemistry

No Reviews yet!

Answers by Ritika M. (4)

Answered on 24/09/2019 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/Intext Exercise 8.4

A racing car has a uniform acceleration of 4 m s−2. What distance will it cover in 10 s after start? ...more

Given data, Initial velocity, u= 0m/s (body is starting from rest) Time, t = 10s Acceleration, a = 4ms-2 Distance covered, S, S= ut + 1/2 at2 = 0 x 10 + 1/2 ( 4x10x10) = 2x10x10 = 200m. Thus, the distance travelled is 200m ...more

Given data,

Initial velocity, u= 0m/s (body is starting from rest)

Time, t = 10s

Acceleration, a = 4ms-2

Distance covered, S,

S= ut + 1/2 at2

= 0 x 10 + 1/2 ( 4x10x10)

= 2x10x10

= 200m.

Thus, the distance travelled is 200m
Answers 5 Comments
Dislike Bookmark

Answered on 24/09/2019 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/Intext Exercise 8.1

An object has moved through a distance. Can it have zero displacement? If yes, support your answer with an example?

Yes, if an object has moved through a distance, it can have zero displacement. This is true if the initial position of the body and final position of the body are the same. Consider a man moving from point A to point B , covering a distance of 10m. If he returns to point A , the distance travelled... ...more

Yes, if an object has moved through a distance, it can have zero displacement.

This is true if the initial position of the body and final position of the body are the same.

Consider a man moving from point A to point B , covering a distance of 10m.

If he returns to point A , the distance travelled by him will be 2x10m but his displacement is zero as there is no possiblity of the shortest path as the final and initial positions are the same.

Answers 3 Comments
Dislike Bookmark

Answered on 24/09/2019 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/Intext Exercise 8.4

What can you say about the motion of an object whose distance−time graph is a straight line... ...more

If the distance- time graph is a straight line parallel to the time axis, the body is in a state of rest.
Answers 5 Comments
Dislike Bookmark

Answered on 24/09/2019 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/Intext Exercise 8.4

A bus starting from rest moves with a uniform acceleration of 0.1 m s−2 for 2 minutes. Find (a)... ...more

A bus starting from rest moves with a uniform acceleration of 0.1 m s−2 for 2 minutes. Find (a) the speed acquired, (b) the distance travelled.

Given data Initial velocity, u = 0 m/s Acceleration , a= 0.1m/S2 Time, t = 2min= 120s Speed acquired, v= u +at = 0+ 0.1x120 = 12m/s. The speed acquired is 12m/s Distance travelled, S= ut + 1/2at2 = 0 + 1/2 ( 0.1x120x120) = 0.1x120x60 = 720m The distance travelled is 720m. ...more

Given data

Initial velocity, u = 0 m/s

Acceleration , a= 0.1m/S2

Time, t = 2min= 120s

Speed acquired,

v= u +at

= 0+ 0.1x120

= 12m/s.

The speed acquired is 12m/s

Distance travelled, 

S= ut + 1/2at2

= 0 + 1/2 ( 0.1x120x120)

= 0.1x120x60

=  720m

 

The distance travelled is 720m.

 

Answers 5 Comments
Dislike Bookmark

Contact

Ritika M. describes herself as Trained teacher, passionate about simplifying Chemistry. She conducts classes in Class 10 Tuition, Class 11 Tuition and Class 9 Tuition. Ritika is located in Indiranagar, Bangalore. Ritika takes Online Classes- via online medium. She has 3 years of teaching experience . Ritika is pursuing Bachelor of Education (B.Ed.) from New Horizon College of Education. Ritika has completed Bachelor of Science (B.Sc.) from Christ university in 2015 and Master of Science (M.Sc.) from St Joseph's College of Arts and Science in 2017. She is well versed in Kannada, Tamil and English.

X

Share this Profile

Recommended Profiles

Afzal K.

Afzal K. photo Indiranagar, Bangalore

Shivani

Shivani photo Indiranagar, Bangalore

Arjun Namala

Arjun Namala photo Indiranagar, Bangalore

Chimakurthy Ganesh

Chimakurthy Ganesh photo Indiranagar, Bangalore

Keerthana G.

Keerthana G. photo Indiranagar, Bangalore

Lakshmi N.

Lakshmi N. photo Indiranagar, Bangalore

Also have a look at

Learn More

NCERT Solutions for Class 9 CBSE Class 10 Syllabus NCERT Class 10 Solutions NCERT Solutions For Class 11 NCERT Solutions for Class 9 Maths NCERT Solutions for Class 9 Science Chapter 1 - Matter In Our Surroundings Chapter 2 - Is Matter Around Us Pure? Chapter 3 - Atoms and Molecules Chapter 4 - Structure of the Atom

Reply to 's review

Enter your reply*

1500/1500

Please enter your reply

Your reply should contain a minimum of 10 characters

Your reply has been successfully submitted.

✕

Certified

The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.

✕

Different batches available for this Course

Book a Free Demo

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more

ThinkVidya Learning Pvt Ltd © 2010-2024All Rights Reserved