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Quest Academy, Opp. HMT Ground, 80 Feet Road R T Nagar, Bangalore, India- 560032.

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Quest Academy is the first of its kind institute with a focus on preparing students for JEE (Main + Advanced), and Medical entrance examinations. The institute adopts a scientific and comprehensive approach for selecting a batch of self-motivated, talented and capable students, enhancing their capabilities through continuous guidance and evaluation of their potential, and developing exhaustive and well researched content w.r.t. examinations.

THE QUEST ACADEMY METHODOLOGY

At QUEST ACADEMY, we believe that a successful classroom is one in which the student's zeal to learn is matched by the teacher's passion to teach. We lay emphasis on selecting the right set of students and providing them with coaching and personalized mentoring to help them meet their goals.

BEST OF THE BRAINS

To connect the best of the brains around is a tradition at Quest Academy now. To explore their sheer talent & to make our students gain from their time accumulated experience is something that can be considered our foremost & intense desire. Quest Academy takes immense pride on continuing to its glorious tradition of collecting the gems to create new ones.

THE QUEST ACADEMY METHODOLOGY

At QUEST ACADEMY, we believe that a successful classroom is one in which the student's zeal to learn is matched by the teacher's passion to teach. We lay emphasis on selecting the right set of students and providing them with coaching and personalized mentoring to help them meet their goals.

BEST OF THE BRAINS

To connect the best of the brains around is a tradition at Quest Academy now. To explore their sheer talent & to make our students gain from their time accumulated experience is something that can be considered our foremost & intense desire. Quest Academy takes immense pride on continuing to its glorious tradition of collecting the gems to create new ones.

Quest Academy, Opp. HMT Ground, 80 Feet Road

Near RT Nagar Police Station, RT Nagar

R T Nagar, Bangalore, India- 560032.

Engineering Entrance Coaching classes

Engineering Entrance Exams

IIT JEE Coaching Classes, BITSAT Coaching Classes

Type of class

Crash Course, Regular Classes

Class Location

At the Institute

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4.9 from 10 reviews

4.9/510

M

- by Mufassira Rahman

attended Engineering Entrance Coaching

posted on 23 Jul, 2017

"I would say Quest academy is one of the best institute you will find for all those young aspiring engineers and doctors to be, to strengthen your fundamentals and thoroughly understanding and enjoying the learning of science..Teachers here are as much as dedicated for every student as you are for your career. It was indeed privilege to be their student. Anyone looking for knowledge oriented and effective couching in right approach I would say you Quest Academy!! They provide complete study material, regular test and most importantly they also give individual attention to students motivating and helping with good strategies to crack competitive exams. The level of dedication of every teacher is amazing. Always present for any doubts and understanding of subjects. The environment in academy has healthy competition for enhancement of every student to excel in competitive exams. "

K

- by Kaushal

attended CET Coaching

posted on 23 Jun, 2017

"Its an awesome institute that gives you proper guidance and complete knowledge to crack 1. Jee mains 2. Jee advanced 3. KCET It will also help you get good marks in boards. "

C

- by Chaitya shah

attended CET Coaching

posted on 30 Apr, 2017

"It is pretty good. I have been a part of quest academy for like 1 year. The coaching over there is just amazing. Teachers over there come down to our level and starting teaching and go level by level, so that one can understand topics easily. The daily tests keep us engaged in studies. The more we practice the more we get ourselves perfect. The teachers are very helpful. It was a great experience. "

A

- by Aishwarya Nair

attended Medical Entrance Coaching

posted on 29 Apr, 2017

"One to one attention is something every student expects and that is fulfilled here. The faculty is amazing and available all the time for any doubt clearances. A perfect academy for entrance oriented as well as board exam orientation preparations. "

Have you attended the class of Quest Academy? Write a Review

"Sir, I just want you to suggest me a book that can help me in revising my 11th and 12th standard syllabus of PCM." in Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching, Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Crash Course

CENGAGE Publications for PCM

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"What is F=Ma?" in Tuition/Class IX-X Tuition

Newton's second law of motion describes the relationship between an object's mass and the amount of force needed to accelerate it. Newton's second law is often stated as F=ma, which means the force (F) acting on an object is equal to the mass (m) of an object times its acceleration (a)

0

| 0

"What is value Tan360?" in Tuition/Class XI-XII Tuition (PUC)

Value of Tan(360 degree) = 0.0000

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"A 900 pF battery is charged by 100 V battery. How much electrostatic energy is stored by the capacitor ?" in Tuition/Class XI-XII Tuition (PUC)

The charge on the capacitor is Q = CV = 900 × 1012 F × 100 V = 9 × 108 C The energy stored in the capacitor = (1/2) CV2 = (1/2) QV = (1/2) × 9 × 108 C × 100 V = 4.5 × 10% J

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"An athlete completes one round a circular track of diameter 200 m in 40 seconds. What will be the distance covered and the displacement at the end of 2 minute and 20 seconds." in Tuition/Class IX-X Tuition

Here we have, Diameter = 200 m, therefore, radius = 200m/2 = 100 m Time of one rotation = 40s Time after 2m20s = 2 x 60s + 20s = 140s Distance after 140 s = ? Displacement after 140s =? Motion Ex1 Motion Ex2 (a) Distance after 140s We know that,distance=velocity ×time ?distance=15.7m/s ×140 s = 2198 m (b) Displacement after 2 m 20 s i.e. in 140 s Since,rotatin in 40 s=1 Motion Ex3 Therefore, in 3.5 rotations athlete will be just at the opposite side of the circular track, i.e. at a distance equal to the diameter of the circular track which is equal to 200 m. Therefore, Distance covered in 2 m 20 s = 2198 m And, displacement after 2 m 20 s = 200m 2. Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph’s average speeds and velocities in jogging (a) from A to B and (b) from A to C? Answer:- Motion Ex4 Here we have, Distance from point A to B = 300 m Time taken = 2 minute 30 second = 2 x 60 + 30 s = 150 s Distance from point B to C = 100 m Time taken = 1 minute = 60 s (a) Average speed and velocity from point A to B Motion Ex5 (b) Average speed and velocity from B to C Motion Ex6 Therefore,average velocity=1.66 m/s west

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Quest Academy address

x Engineering Entrance Coaching classes

Engineering Entrance Exams

IIT JEE Coaching Classes, BITSAT Coaching Classes

Type of class

Crash Course, Regular Classes

Class Location

At the Institute

Class XI-XII Tuition (PUC)

Board

State, CBSE

CBSE Subjects taught

Mathematics, Biology, Physics, Chemistry

State Syllabus Subjects taught

Biology, Physics, Chemistry, Mathematics

Class Location

At the Institute

Medical Entrance Coaching classes

Teaches for following exams

AIPMT Coaching, AIIMS Coaching

Type of class

Crash Course, Regular Classes

Class Location

At the Institute

Class IX-X Tuition

Board

CBSE

CBSE Subjects taught

Science, Mathematics, English

ICSE Subjects taught

State Syllabus Subjects taught

Class Location

At the Institute

CET Coaching classes

Subjects

Chemistry, Biology, Mathematics, Physics

Class type catered to

Regular Classes, Integrated coaching classes, Crash course

Class Location

At the Institute

"Sir, I just want you to suggest me a book that can help me in revising my 11th and 12th standard syllabus of PCM." in Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching, Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Crash Course

CENGAGE Publications for PCM

0

| 0

"What is F=Ma?" in Tuition/Class IX-X Tuition

Newton's second law of motion describes the relationship between an object's mass and the amount of force needed to accelerate it. Newton's second law is often stated as F=ma, which means the force (F) acting on an object is equal to the mass (m) of an object times its acceleration (a)

0

| 0

"What is value Tan360?" in Tuition/Class XI-XII Tuition (PUC)

Value of Tan(360 degree) = 0.0000

0

| 0

"A 900 pF battery is charged by 100 V battery. How much electrostatic energy is stored by the capacitor ?" in Tuition/Class XI-XII Tuition (PUC)

The charge on the capacitor is Q = CV = 900 × 1012 F × 100 V = 9 × 108 C The energy stored in the capacitor = (1/2) CV2 = (1/2) QV = (1/2) × 9 × 108 C × 100 V = 4.5 × 10% J

1

| 0

"An athlete completes one round a circular track of diameter 200 m in 40 seconds. What will be the distance covered and the displacement at the end of 2 minute and 20 seconds." in Tuition/Class IX-X Tuition

Here we have, Diameter = 200 m, therefore, radius = 200m/2 = 100 m Time of one rotation = 40s Time after 2m20s = 2 x 60s + 20s = 140s Distance after 140 s = ? Displacement after 140s =? Motion Ex1 Motion Ex2 (a) Distance after 140s We know that,distance=velocity ×time ?distance=15.7m/s ×140 s = 2198 m (b) Displacement after 2 m 20 s i.e. in 140 s Since,rotatin in 40 s=1 Motion Ex3 Therefore, in 3.5 rotations athlete will be just at the opposite side of the circular track, i.e. at a distance equal to the diameter of the circular track which is equal to 200 m. Therefore, Distance covered in 2 m 20 s = 2198 m And, displacement after 2 m 20 s = 200m 2. Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph’s average speeds and velocities in jogging (a) from A to B and (b) from A to C? Answer:- Motion Ex4 Here we have, Distance from point A to B = 300 m Time taken = 2 minute 30 second = 2 x 60 + 30 s = 150 s Distance from point B to C = 100 m Time taken = 1 minute = 60 s (a) Average speed and velocity from point A to B Motion Ex5 (b) Average speed and velocity from B to C Motion Ex6 Therefore,average velocity=1.66 m/s west

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