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Akash Timmapuram BTech Tuition trainer in Nizamabad

Akash Timmapuram

IT professional Trainer with 1 year of experience in IT industry

Bheemgal, Nizamabad, India - 503307.

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Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

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Education

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Overview

Im a bachelor of technology student graduated from iiit Kottayam Kerala and volleyball captain.With knowledge in cse, I have started tutoring online during leisure time.

Languages Spoken

Telugu Mother Tongue (Native)

English Proficient

Hindi Basic

Education

indian institute of information technology 2019

Bachelor of Technology (B.Tech.)

Address

Bheemgal, Nizamabad, India - 503307

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Teaches

BTech Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

1

BTech Computer Science subjects

Big Data Analytics, Data Structures and Algorithms, Database Management Systems, Java Programming, Linux Programming, Machine Learning, Design and Analysis of Algorithms

BTech Branch

BTech Computer Science Engineering

Type of class

Crash Course

Class strength catered to

One on one/ Private Tutions

Taught in School or College

Yes

Reviews

No Reviews yet!

FAQs

1. Which BTech branches do you tutor for?

BTech Computer Science Engineering

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach BTech Tuition Class.

4. Do you provide a demo class?

No, I don't provide a demo class.

5. How many years of experience do you have?

I have been teaching for 1 year.

Contact

Answers by Akash Timmapuram (2)

Answered on 25/05/2020 Learn Tuition

5(X^2+Y^2+Z^2)=4(XY+YZ+ZX) then find X:Y:Z

5x^2 + 5y^2 + 5z^2 = 4xy+4yx+4zx 2(x^2+y^2 -2xy) + 2(y^2+z^2 - 2yz) +2(z^2+x^2 -2zx) + x^2+y^2 +z^2 = 0 => 2(x-y)^2 + 2(y-z)^2 + 2(z-x)^2 + x^2 + y^2 + z^2 = 0 Since LHS terms are squares (i.e) positive LHS cannot add to equal RHS that is 0. hence all the terms of LHS are 0.∴ x-y = 0 , y-z... ...more

5x^2 + 5y^2 + 5z^2 = 4xy+4yx+4zx

2(x^2+y^2 -2xy) + 2(y^2+z^2 - 2yz)  +2(z^2+x^2 -2zx) + x^2+y^2 +z^2 = 0 => 2(x-y)^2 + 2(y-z)^2 + 2(z-x)^2 + x^2 + y^2 + z^2 = 0

Since LHS terms are squares (i.e) positive LHS cannot add to equal RHS that is 0. hence all the terms of LHS are 0.∴ x-y = 0 , y-z =0, z-x=0 => x=y=z ∴ x:y:z= 1:1:1. 

Answers 353 Comments
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Answered on 25/05/2020 Learn Tuition/Engineering Diploma Tuition/Computer Engineering Diploma +1 Tuition/BTech Tuition

Numbers are stored and transmitted inside a computer in: a. binary form b. ASCII code form c. decimal... ...more

Numbers are stored and transmitted inside a computer in:
a. binary form
b. ASCII code form
c. decimal form
d. alphanumeric form

The ASCII code because the computer only deals with numbers (in binary representation specifically). ASCII is the standard representation to communicate between devices.
Answers 293 Comments
Dislike Bookmark

Contact

Teaches

BTech Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

1

BTech Computer Science subjects

Big Data Analytics, Data Structures and Algorithms, Database Management Systems, Java Programming, Linux Programming, Machine Learning, Design and Analysis of Algorithms

BTech Branch

BTech Computer Science Engineering

Type of class

Crash Course

Class strength catered to

One on one/ Private Tutions

Taught in School or College

Yes

No Reviews yet!

Answers by Akash Timmapuram (2)

Answered on 25/05/2020 Learn Tuition

5(X^2+Y^2+Z^2)=4(XY+YZ+ZX) then find X:Y:Z

5x^2 + 5y^2 + 5z^2 = 4xy+4yx+4zx 2(x^2+y^2 -2xy) + 2(y^2+z^2 - 2yz) +2(z^2+x^2 -2zx) + x^2+y^2 +z^2 = 0 => 2(x-y)^2 + 2(y-z)^2 + 2(z-x)^2 + x^2 + y^2 + z^2 = 0 Since LHS terms are squares (i.e) positive LHS cannot add to equal RHS that is 0. hence all the terms of LHS are 0.∴ x-y = 0 , y-z... ...more

5x^2 + 5y^2 + 5z^2 = 4xy+4yx+4zx

2(x^2+y^2 -2xy) + 2(y^2+z^2 - 2yz)  +2(z^2+x^2 -2zx) + x^2+y^2 +z^2 = 0 => 2(x-y)^2 + 2(y-z)^2 + 2(z-x)^2 + x^2 + y^2 + z^2 = 0

Since LHS terms are squares (i.e) positive LHS cannot add to equal RHS that is 0. hence all the terms of LHS are 0.∴ x-y = 0 , y-z =0, z-x=0 => x=y=z ∴ x:y:z= 1:1:1. 

Answers 353 Comments
Dislike Bookmark

Answered on 25/05/2020 Learn Tuition/Engineering Diploma Tuition/Computer Engineering Diploma +1 Tuition/BTech Tuition

Numbers are stored and transmitted inside a computer in: a. binary form b. ASCII code form c. decimal... ...more

Numbers are stored and transmitted inside a computer in:
a. binary form
b. ASCII code form
c. decimal form
d. alphanumeric form

The ASCII code because the computer only deals with numbers (in binary representation specifically). ASCII is the standard representation to communicate between devices.
Answers 293 Comments
Dislike Bookmark

Contact

Akash Timmapuram describes himself as IT professional Trainer with 1 year of experience in IT industry. He conducts classes in BTech Tuition. Akash is located in Bheemgal, Nizamabad. Akash takes Online Classes- via online medium. He has 1 years of teaching experience . Akash has completed Bachelor of Technology (B.Tech.) from indian institute of information technology in 2019. He is well versed in English, Hindi and Telugu.

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