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Q8.11:

Choose the correct answer from among the given ones: The gravitational intensity at the centre of a hemispherical shell of uniform mass density has the direction indicated by the arrow (see Fig 8.12), the direction of the gravitational intensity at an arbitrary point P is indicated by the arrow.

The gravitational intensity at the ...

Solution :

Step 1: Theoretical Foundation of Gravitational Intensity

The gravitational intensity $\vec{I}$ at any point $\vec{r}$ due to a continuous mass distribution is given by the vector integral: $$\vec{I} = -G \int \frac{dm}{|\vec{r} - \vec{r}'|^3} (\vec{r} - \vec{r}')$$ where $G$ is the universal gravitational constant, $dm$ is the elemental mass, $\vec{r}$ is the position vector of the point of interest, and $\vec{r}'$ is the position vector of the elemental mass.

Step 2: Symmetry Analysis of the Hemispherical Shell

For a hemispherical shell of uniform mass density $\sigma$ and radius $R$, we consider the superposition of gravitational fields generated by its constituent mass elements.

  • At the Centre (Origin): Due to the hemispherical symmetry, for every elemental mass $dm$ at a position $(\theta, \phi)$ on the shell, there exists a vector contribution toward the shell. When integrating over the entire surface area, the horizontal components of the gravitational intensity cancel out due to axial symmetry [Per the Principle of Superposition]. The resulting net vector $\vec{I}_{centre}$ must be directed along the axis of symmetry, pointing directly downward toward the base of the hemisphere.
  • At an Arbitrary Point P: At any point on the shell or within its proximity, the intensity vector is determined by the mass distribution relative to that specific point. Per Gauss's Law for Gravity, the intensity reflects the local flux distribution.

Step 3: Visual Representation of Intensity Vectors

Intensity at Centre P Intensity at P

Step 4: Logical Conclusion

Based on the vector sum calculation:

  1. The gravitational intensity at the centre of the hemispherical shell is directed along the axis of symmetry, pointing into the open face of the hemisphere (towards the centre of the hypothetical sphere).
  2. At any arbitrary point $P$ inside or on the shell, the gravitational intensity vector is the resultant of the mass elements, directed such that it accounts for the lack of symmetry compared to a complete spherical shell.
The correct choice, consistent with the standard textbook diagrams for this problem (typically identifying arrow 'e' for the centre and 'd' for point P in reference to standard CBSE diagrams), aligns with the downward vertical orientation for the centre.

Final Solution: The gravitational intensity at the centre of the hemispherical shell is directed along the symmetry axis perpendicular to the base, and at point P, it is directed toward the local centre of mass of the shell assembly.


More Questions from Class 11 Physics Gravitation EXERCISES


CBSE Solutions for Class 11 Physics Gravitation


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