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Q6.13:
The equilibrium constant expression for a gas reaction is, $K_c = \frac{[NH_3]^4 [O_2]^5}{[NO]^4 [H_2O]^6}$ Write the balanced chemical equation corresponding to this expression.

Solution :

Step 1: Analyzing the Equilibrium Constant Expression

The law of mass action states that for a reversible reaction $aA + bB \rightleftharpoons cC + dD$, the equilibrium constant $K_c$ is expressed as:

$K_c = \frac{[C]^c [D]^d}{[A]^a [B]^b}$

Comparing this with the given expression: $K_c = \frac{[NH_3]^4 [O_2]^5}{[NO]^4 [H_2O]^6}$

We identify the species in the numerator as the products and the species in the denominator as the reactants. The stoichiometric coefficients correspond to the exponents of the concentration terms [Per the Law of Mass Action].

Step 2: Identifying Stoichiometric Coefficients

From the given expression, the stoichiometric coefficients for each species are determined as follows:

  • Products: $NH_3$ (coefficient = 4) and $O_2$ (coefficient = 5)
  • Reactants: $NO$ (coefficient = 4) and $H_2O$ (coefficient = 6)

Step 3: Constructing the Chemical Equation

By mapping the reactants to the left-hand side and products to the right-hand side, we derive the following unbalanced skeleton equation:

$4NO + 6H_2O \rightleftharpoons 4NH_3 + 5O_2$

Step 4: Verification of Atom Balance

To ensure this represents a physically valid reaction, we perform an atomic balance check [Law of Conservation of Mass]:

Element Reactant Side Product Side
Nitrogen (N) 4 4
Oxygen (O) 4 + 6 = 10 5 × 2 = 10
Hydrogen (H) 6 × 2 = 12 4 × 3 = 12

Since the number of atoms for each element is balanced on both sides, the chemical equation is stoichiometric.

Visual Representation of the Equilibrium

4NO(g) + 6H₂O(g) 4NH₃(g) + 5O₂(g)

Final Solution: 4NO(g) + 6H₂O(g) $\rightleftharpoons$ 4NH₃(g) + 5O₂(g)


More Questions from Class 11 Chemistry Equilibrium EXERCISES


CBSE Solutions for Class 11 Chemistry Equilibrium


Chapters in CBSE - Class 11 Chemistry


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