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Badrinath P Class 11 Tuition trainer in Hyderabad

Badrinath P

I have 18 Years Experience in teaching ( Chemistry NEET,IIT Mains, IIT Foundation)

Saroornagar, Hyderabad, India - 500060.

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Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

Provides tuition upto 12 Standard.

Languages Spoken

English

Telugu

Education

K U 2001

Master of Science (M.Sc.)

OSMANIA UNIVERSITY 2008

Bachelor of Education (B.Ed.)

Address

Saroornagar, Hyderabad, India - 500060

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Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

16

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

Taught in School or College

Yes

State Syllabus Subjects taught

Chemistry

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

16

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

Taught in School or College

Yes

State Syllabus Subjects taught

Chemistry

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

CBSE, ISC/ICSE, State

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach Class 11 Tuition and Class 12 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 16 years.

Contact

Answers by Badrinath P (3)

Answered on 23/10/2018 Learn CBSE/Class 11/Science/Chemistry +1 CBSE/Class 11/Science/Chemistry/Unit 11-Some p -Block Elements

The linear shape of C02 is due to ______ .(a) sp3 hybridisation of carbon(b) sp hybridisation of carbon(c)... ...more
The linear shape of C02 is due to  ______ .
(a) sp3 hybridisation of carbon
(b) sp hybridisation of carbon
(c) pπ-pπ bonding between carbon and oxygen
(d) sp2 hybridisation of carbon

Answer is b i,e SP hybridisation of carbon.
Answers 25 Comments
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Answered on 20/10/2018 Learn CBSE/Class 11/Science/Chemistry/Hydrogen +1 CBSE/Class 11/Science/Chemistry

Which of the following statements are correct? (a) Elements of group 15 form electron deficient hydrides.... ...more
Which of the following statements are correct?
(a) Elements of group 15 form electron deficient hydrides.
(b) All elements of group 14 form electron precise hydrides.
(c) Electron precise hydrides have tetrahedral geometries.
(d) Electron rich hydrides can act as Lewis acids.

Answer is b and c i,e All elements of group 14 form electron precise hydrides. Electron precise hydrides have tetrahedral geometries. Eg: CH4 has tetrahedral geometry.
Answers 3 Comments
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Answered on 19/10/2018 Learn CBSE/Class 11/Science/Chemistry/Hydrogen +1 CBSE/Class 11/Science/Chemistry

Consider the reactions (A) H202 + 2HI → I2 + 2H20 (B) HOCl + H2O2 → H30+ + Clâ?? + 02 Which... ...more
Consider the reactions
(A) H202 + 2HI → I2 + 2H20
(B) HOCl + H2O2 → H30+ + Clâ?? + 02
Which of the following statements is correct about H202 with reference to these reactions? Hydrogen peroxide is   _______      
(a) an oxidizing agent in both (A) and (B)
(b) an oxidizing agent in (A) and reducing agent in (B)
(c) a reducing agent in (A) and oxidizing agent in (B)
(d) a reducing agent in both (A) and (B)#new_quesion#The oxide that gives H202 on treatment with dilute H2S04 is
(a) Pb02
(b) Ba02 -8H20
(c) Mn02
(d) Ti02

1) Answer is b i,e is an oxidising agent in(A) and reducing agent in (B).Sinse in A Iodide is oxidised as Iodine(Oxidation number is increases i,e is -1 to 0),in B Chlorine is reduced to Chloride Ion(Oxidation number is decreases i,e +1 to -1) 2) answer is b i,e is BaO2 8H2o. Because BaO2 contains peroxide... ...more

1) Answer is b i,e is an oxidising agent in(A) and reducing agent in (B).Sinse in A Iodide is oxidised as Iodine(Oxidation number is increases i,e is -1 to 0),in B Chlorine is reduced to Chloride Ion(Oxidation number is decreases i,e +1 to -1)

2) answer is b i,e is BaO2 8H2o. Because BaO2 contains peroxide linkage.

Answers 2 Comments
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Contact

Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

16

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

Taught in School or College

Yes

State Syllabus Subjects taught

Chemistry

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

16

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

Taught in School or College

Yes

State Syllabus Subjects taught

Chemistry

No Reviews yet!

Answers by Badrinath P (3)

Answered on 23/10/2018 Learn CBSE/Class 11/Science/Chemistry +1 CBSE/Class 11/Science/Chemistry/Unit 11-Some p -Block Elements

The linear shape of C02 is due to ______ .(a) sp3 hybridisation of carbon(b) sp hybridisation of carbon(c)... ...more
The linear shape of C02 is due to  ______ .
(a) sp3 hybridisation of carbon
(b) sp hybridisation of carbon
(c) pπ-pπ bonding between carbon and oxygen
(d) sp2 hybridisation of carbon

Answer is b i,e SP hybridisation of carbon.
Answers 25 Comments
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Answered on 20/10/2018 Learn CBSE/Class 11/Science/Chemistry/Hydrogen +1 CBSE/Class 11/Science/Chemistry

Which of the following statements are correct? (a) Elements of group 15 form electron deficient hydrides.... ...more
Which of the following statements are correct?
(a) Elements of group 15 form electron deficient hydrides.
(b) All elements of group 14 form electron precise hydrides.
(c) Electron precise hydrides have tetrahedral geometries.
(d) Electron rich hydrides can act as Lewis acids.

Answer is b and c i,e All elements of group 14 form electron precise hydrides. Electron precise hydrides have tetrahedral geometries. Eg: CH4 has tetrahedral geometry.
Answers 3 Comments
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Answered on 19/10/2018 Learn CBSE/Class 11/Science/Chemistry/Hydrogen +1 CBSE/Class 11/Science/Chemistry

Consider the reactions (A) H202 + 2HI → I2 + 2H20 (B) HOCl + H2O2 → H30+ + Clâ?? + 02 Which... ...more
Consider the reactions
(A) H202 + 2HI → I2 + 2H20
(B) HOCl + H2O2 → H30+ + Clâ?? + 02
Which of the following statements is correct about H202 with reference to these reactions? Hydrogen peroxide is   _______      
(a) an oxidizing agent in both (A) and (B)
(b) an oxidizing agent in (A) and reducing agent in (B)
(c) a reducing agent in (A) and oxidizing agent in (B)
(d) a reducing agent in both (A) and (B)#new_quesion#The oxide that gives H202 on treatment with dilute H2S04 is
(a) Pb02
(b) Ba02 -8H20
(c) Mn02
(d) Ti02

1) Answer is b i,e is an oxidising agent in(A) and reducing agent in (B).Sinse in A Iodide is oxidised as Iodine(Oxidation number is increases i,e is -1 to 0),in B Chlorine is reduced to Chloride Ion(Oxidation number is decreases i,e +1 to -1) 2) answer is b i,e is BaO2 8H2o. Because BaO2 contains peroxide... ...more

1) Answer is b i,e is an oxidising agent in(A) and reducing agent in (B).Sinse in A Iodide is oxidised as Iodine(Oxidation number is increases i,e is -1 to 0),in B Chlorine is reduced to Chloride Ion(Oxidation number is decreases i,e +1 to -1)

2) answer is b i,e is BaO2 8H2o. Because BaO2 contains peroxide linkage.

Answers 2 Comments
Dislike Bookmark

Contact

Badrinath P describes himself as I have 18 Years Experience in teaching ( Chemistry NEET,IIT Mains, IIT Foundation). He conducts classes in Class 11 Tuition and Class 12 Tuition. Badrinath is located in Saroornagar, Hyderabad. Badrinath takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 16 years of teaching experience . Badrinath has completed Master of Science (M.Sc.) from K U in 2001 and Bachelor of Education (B.Ed.) from OSMANIA UNIVERSITY in 2008. He is well versed in English and Telugu.

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