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CBSE - Class 10 Mathematics Coordinate geometry Worksheet
The area of the triangle formed by the points A(-1.5, 3), B(6, -2) and C(-3, 4) is
0
b.1
c.2
d.3/2
Find the length of cirve X
.
.
.
.
If the distance between the points (2, –2) and (–1, x) is 5, one of the values of x is
-2
b.2
c.-1
d.1
Prove that the points P(0,-1), Q(-2,3) R(6,7) and S(8,3) are the vertices of a rectangle PQRS.
What is the length of the line segment whose end points are A (1,-4) and B (5, -7).
√157 units
b.5 units
c.√45 units
d.√137 units
If the coordinates of points A and B are (-2,-2) and (2,-4) find the coordinates of P such that AP = 3/7 AB, where P lies on the line segment AB.
If the points P(1, 2), B(0, 0) and C(a, b) are collinear, then
2a=b
b.a=-b
c.a=2b
d.a=b
We can find whether any given points are collinear or not using the distance formula.
The vertices of triangle PQR are P(6,-2), Q(0,-6) and R(4,8). Find the coordinates of mid point of PQ, QR and PR.
Prove that the points (7,10) (-2,5) and (3, -4) are the vertices of an isosceles right triangle.
Find the point on the x-axis which is equidistant from the points (5,4) and (-2,3). Also find the area of triangle formed by points.
The points P(2,-1) ,Q(3,4) , R(-2,3) ,S (-3,-2) for
a square
b.a rhombus
c.are collinear
d.none
दो वृत एक दूसरे को p पर आंतरिक रूप से स्पर्श करते है और बड़ी त्रिज्या वाले वृत की जीवा AB दूसरे वृत को C और D पर प्रतिछेद करते है । तो
∠CPA=∠DPB
b.∠CPA=∠CDP
c.∠CDP=∠DPB
d.∠APC=∠AACP
The point (5,a) lies on X axis when
a=0
b.a=5
c.a<0
d.a<5
If the point C(-1, 2) divides internally the line segment joining the points A(2,5) and B(x,4) in the ratio 3:4. Find the value of
2 cubes each of volume 64 cm3 are joined end to end. The surface area of the resulting cuboid is 160 cm2.
Worksheet Answers
P, Q, R and S are the vertices of a rectangle PQRS
Solution:
Use distance formula. D =
P = (-2/7, -20/7)
Mid points PQ, QR and PR are D(3,-4), E(2,1) and F(5.3)
ABC are the vertices of isosceles triangle
12.5 sq. units
(x,y) = (-5) (-2); 29