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CBSE - Class 10 Mathematics Pair of linear equations in two variable Worksheet
if 2/x+3/y=10 and 3/x+2/y=5 ,then find 1/x + 1/y =........................
3
b.2
c.4
d.1/3
If a pair of linear equations is consistent, then the lines will be
always coincident
b.parallel
c.always intersecting
d.intersecting or coincident
If X+1⁄X=3 FIND THE VALUE OF X³+1/X³
15
b.16
c.17
d.18
Find the value of m, when (m+1)x=3ky+15=0 and 5x+ky+5=0 are coincident
m=16
b.m=-17
c.m=-15
d.m=-16
If the sum of first 7 terms of an A.P. is 49 and that of first 17 terms is 289, find the sum of n terms.
n^2
b.n^3
c.n/2
d.2n
The nth term of an AP is 3n + 5. what is the common difference
5
b.6
c.3
d.9
If the lines given by 2x + ky = 1 and 3x – 5y = 7 are parallel, then the value of k is
-10/3
b.10/3
c.-13
d.-7
The graph of the equation 2x + 3y = 5 is a
vertical line
b.straight line
c.horizontal line
d.none of these
Which term of the A.P.: 21, 18, 15, .... is zero
7
b.6
c.8
d.9
Your trading plan is something you should check
Every month
b.Every week
c.Every day
d.Every day before starting to trade
If a1x+b1y+c1=0 , a2x+b2y+c2=0 is a pair of linear eqns in two variables x and y such that if a1/a2=b1/b2=c1/c2 then pair of linear eqns is
consistent with infinitely many solution
b.inconsistent
c.consistent with unique solution
d.no solution
Worksheet Answers
Solution:
add eqution 1 and equestion 2
so 2/x+3/y+3/x+2/y=10+5
5/x+5/y=15
5(1/x+1/y)=15
1/x+1/y = 15/5 =3
Solution:
(m+1)x=3ky+15=0 this equation can be written as (m+1)x-3ky-15=0 and other equation is 5x+ky+5=0
the condition for coincident lines is the ratio of the coefficents of x, y and constants has to be equal.
=> (m+1)/5=-3k/k=-15/5
=> m+1=-15
=> m=-16
Hope it helps
thank you
Solution:
Before the start of the trade, remind yourself the max. capital you will deply on each trade, max loss you are wiling to take, max. trades you will take and the conditions for stopping trades.
Preferably write it down and put it right in front of you.
