As a tutor you can connect with more than a million students and grow your network.

Ask a Question

Feed

All

Answered on 02 Mar CBSE/Class 9/Mathematics

Salman Ahmad Siddiqui

Maths Tutor

It is not a big job to score 100 out of 100 in mathematics. A Good dedicated teacher and a real dedication can help you score 100%.

Like 1

Answers 21 Comments Answered on 23 Feb CBSE/Class 9/Mathematics

Salman Ahmad Siddiqui

Maths Tutor

Yes, of course 0 is a rational number. All natural numbers whole numbers and integers are also rational numbers. 0 can be written as 0/1 , 0/2 etc Hence it is natural number

Like 4

Answers 17 Comments Lesson Posted on 22 Feb CBSE/Class 9/Mathematics

Sujoy D.

1. Strong concept building classes. 2. Weekly tests in weak areas for students to improve their confidence. 3....

QUESTION In a college, where every student follows at least one of the three activities- dance, music, or sports- 65% follow dance, 86% follow music, and 57% follow sports. What can be the maximum and minimum percentage of students who follow A) All three activities B) Exactly two activities ... read more

**QUESTION**

In a college, where every student follows at least one of the three activities- dance, music, or sports- 65% follow dance, 86% follow music, and 57% follow sports. What can be the maximum and minimum percentage of students who follow

A) All three activities

B) Exactly two activities

**ANSWER**

Here the sum of the three percentage figures is 208%, however since every students is involve in at least one of the three activities, the surplus count is 108%, accounted for by the people engaged in 2 or 3 activities.

A) Exactly 3 activities

Max -> 108% extra is accounted for by 54% ppl, taking 2 extra activities(Total of 3 activities)

Min -> I allocate a 2nd activity to each of the 100%, but I am still left with 8%, which must be born by 8% people having 3 activities

For B)

Max -> 92%, since in worst case scenario 8% ppl must be into all 3 activities

Min -> 0%, In case of 54% ppl being into all 3 activities, as shown in A (Part 1), we end up with 0% ppl being into exactly 2 activities

Max exactly 2 sets cannot be 100%, as total is 208%, we must have a minimum of 8% students who like all three activities, hence only a max of 92% remaining folks can like exactly 2 activities

If you assign all 100% people 2 activities, your total will be 200 and not 208%... Also dint we just conclude that 8% ppl minimum are into 3 activities, So at least these 8% ppl need to be excluded right?

Like 0

Comments Looking for Class IX-X Tuition

Find best Class IX-X Tuition in your locality on UrbanPro.

Answered on 23 Feb CBSE/Class 9/Mathematics Tuition/Class IX-X Tuition

Salman Ahmad Siddiqui

Maths Tutor

2x + 3y=7 Put 2 in place of x and 1 in place of y. 2*2+ 3*1=4+3=7

Like 4

Answers 15 Comments Answered on 23 Feb CBSE/Class 9/Mathematics Tuition/Class IX-X Tuition

Salman Ahmad Siddiqui

Maths Tutor

N¹ *N² = LCM * HCF 161 *345 =23 * N² N² =2415

Like 4

Answers 13 Comments Answered on 23 Feb CBSE/Class 9/Mathematics Tuition/Class IX-X Tuition

Salman Ahmad Siddiqui

Maths Tutor

2x 3y=8 X=1 and y=8/6 X=8/6 and y=1 X=-1 and y=(-8)/6 X=(-8)/6 and y=-1

Like 4

Answers 6 Comments Looking for Class IX-X Tuition

Find best Class IX-X Tuition in your locality on UrbanPro.

Answered on 22 Feb CBSE/Class 9/Mathematics

Salman Ahmad Siddiqui

Maths Tutor

Sin(360)= sin(0)=0 Cos(360)=cos(0)=1 Formula: Sin((360*x)+y)=sin(y) Cos((360*x)+y)=cos(y) Where x is any integer and y is any real number. Sin(360) +cos (360) =1

Like 4

Answers 22 Comments Answered on 22 Feb CBSE/Class 9/Mathematics

Salman Ahmad Siddiqui

Maths Tutor

Volume of hemisphere of radius r=(2πr³)/3 =Half of the volume of full sphere ((4πr³)/3) = 2π/3 times of volume of cube of side r.

Like 4

Answers 16 Comments Answered on 24 Feb CBSE/Class 9/Mathematics Tuition/Class IX-X Tuition

In a trapezium ABCD where AB is parallel to CD, E is the mid-point of BC, prove that ?AED = 1/2 trapezium ABCD.

D Mukherjee

Teacher

Draw a line EF joining E, the mid-point of BC and F, the mid-point of AD. Now EF is parallel to AB Area of Triangle AEF = 1/2 (Area of Trapezium ABEF) Area of Triangle DEF = 1/2 (Area of Trapezuim DCEF) Adding we get Area of Triangle AED = 1/2 (Artea of Trapezium ABCD)

Like 1

Answers 1 Comments Looking for Class IX-X Tuition

Find best Class IX-X Tuition in your locality on UrbanPro.

Answered on 27 Feb CBSE/Class 9/Mathematics Tuition/Class IX-X Tuition

Samar Singh

Mathematics Professor

Let?ABC be required triangle AB=AC=5cm BC=8 cm Let AD be the altitude We know that perpendicular drawn from vertex bisect the base. Therefore BD=4 cm Using Pythagoras theorem we get AD= 3 cm Area of ?ABC=1/2 × base×height =1/2×8×3=12 cm2 read more

Let?ABC be required triangle

AB=AC=5cm

BC=8 cm

Let AD be the altitude

We know that perpendicular drawn from vertex bisect the base.

Therefore BD=4 cm

Using Pythagoras theorem we get AD= 3 cm

Area of ?ABC=1/2 × base×height

=1/2×8×3=12 cm2

read less Like 0

Answers 5 Comments UrbanPro.com helps you to connect with the best Class IX-X Tuition in India. Post Your Requirement today and get connected.

x

Ask a Question