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Lesson Posted on 08 Jan CBSE/Class 11/Science/Chemistry/Unit 1-Basic Concepts of Chemistry

Basic Organic Chemistry

Shijo Francis

I have qualified central govt. Exams for fellowship to pursue ph.D in cusat. So I have good idea in...

Organic chemistry means how particular reagents will react. Example if we considering acid it will make a proton donor or an electron acceptor. That is when was an acid is added it would acidify the medium by donating the proton. Similarly base will add hydroxyl up. But it some exceptional cases are... read more

Organic chemistry means how particular reagents will react. Example if we considering acid it will make a proton donor or an electron acceptor. That is when was an acid is added it would acidify the medium by donating the proton. Similarly base will add hydroxyl up. But it some exceptional cases are there where it would not react. That is it will act as the medium for the reaction to take place — nitration reaction sulphuric acid act as the medium.

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Answered on 27/11/2018 CBSE/Class 11/Science/Chemistry/Unit 1-Basic Concepts of Chemistry

How is empirical formula of a compound related to its molecular formula?

Anany

Molecular formula = empirical formula * n-factor ( where n-factor = molecular mass / empirical mass )
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Answered on 28/10/2018 CBSE/Class 11/Science/Chemistry CBSE/Class 11/Science/Chemistry/Unit 1-Basic Concepts of Chemistry

Papiya Abedin

Chemistry Expert

The S I unit of mass is kg.
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Answered on 15 Jan CBSE/Class 11/Science/Chemistry CBSE/Class 11/Science/Chemistry/Unit 1-Basic Concepts of Chemistry

Sufiyan Chauhan

Chemistry Tutor in Bathinda

"0.50 mol Na2CO3" means 0.50 x 106(molar mass) =53g of solid Na2CO3 ,whereas "0.50 M Na2CO3" means that 0.50 mol of Na2CO3 (53g) is present in 1 litre of solution.
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Answered on 05/11/2018 CBSE/Class 11/Science/Chemistry CBSE/Class 11/Science/Chemistry/Unit 1-Basic Concepts of Chemistry

What is the concentration of sugar (C12H22O11) in mol L -1 if its 20 g are dissolved in enough water... read more
What is the concentration of sugar (C12H22O11) in mol L -1 if its 20 g are dissolved in enough water to make a final volume up to 2 L? read less

Mr R Kiran

Chemistry Lecturer

Molarity= n/V n= w/MW. = 20/342 = 0.058 moles, V = 2 lit, Molarity = 0.058/2 = 0.029M
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Answered on 12/11/2018 CBSE/Class 11/Science/Chemistry CBSE/Class 11/Science/Chemistry/Unit 1-Basic Concepts of Chemistry

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ncert-solutions-for-class-11-chemistry-chapter-1-some-basic-concepts-of-chemistry-27 read less

Ajay Sharma

Teacher

12/NA
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Answered on 08/11/2018 CBSE/Class 11/Science/Chemistry CBSE/Class 11/Science/Chemistry/Unit 1-Basic Concepts of Chemistry

Use the data given in the following table to calculate the molar mass of naturally occurring argon. read more
Use the data given in the following table to calculate the molar mass of naturally occurring argon.
ncert-solutions-for-class-11-chemistry-chapter-1-some-basic-concepts-of-chemistry-30 read less

Sagardeep Singh

It's a simple solution. Just take molar mass of isotopes, mulitply by the percentage and you get your answer. {35.96755 × (0.337/100)} + {37.96272 × (0.063/100)} + {39.9624 × (99.600/100)} = 0.1212106435 + 0.0239165136 +39.8025504 = 39.947677557 read more

It's a simple solution. Just take molar mass of isotopes, mulitply by the percentage and you get your answer.

{35.96755 × (0.337/100)} + {37.96272 × (0.063/100)} + {39.9624 × (99.600/100)} =

0.1212106435 + 0.0239165136 +39.8025504 =

39.947677557

 

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Answered on 15/12/2018 CBSE/Class 11/Science/Chemistry CBSE/Class 11/Science/Chemistry/Unit 1-Basic Concepts of Chemistry

How much copper can be obtained from 100 g of copper sulphate (CuSO4 )? (Atomic mass of Cu= 63.5 amu) read more
How much copper can be obtained from 100 g of copper sulphate (CuSO4 )? (Atomic mass of Cu= 63.5 amu) read less

Santosh Shinde

39.7869674
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Answered on 17/11/2018 CBSE/Class 11/Science/Chemistry CBSE/Class 11/Science/Chemistry/Unit 1-Basic Concepts of Chemistry

Convert the following into basic units: (i) 28.7 pm (ii) 15.15 µs (iii) 25365 mg read more
Convert the following into basic units:
(i) 28.7 pm (ii) 15.15 µs (iii) 25365 mg read less

Naveen Kumar Budde

Home Tutor

(i) 1 pm = 10-12 m28.7 pm = 28.7×10-12 m = 2.87×10-11 m(ii) 1 pm = 10-12 m∴15.15 pm = 15.15×10-12 m = 1.515 ×10-11 m(iii) 1 mg = 10-3 g25365 mg = 2.5365×104×10-3 gNow,1 g = 10-3 kg2.5365×10 g = 2.5365×10×10-3 kg∴25365 mg = 2.5365×10-2... read more

(i) 1 pm = 10-12 m
28.7 pm = 28.7×10-12 m = 2.87×10-11 m
(ii) 1 pm = 10-12 m
∴15.15 pm = 15.15×10-12 m = 1.515 ×10-11 m
(iii) 1 mg = 10-3 g
25365 mg = 2.5365×104×10-3 g
Now,
1 g = 10-3 kg
2.5365×10 g = 2.5365×10×10-3 kg
∴25365 mg = 2.5365×10-2 kg

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Answered on 13/12/2018 CBSE/Class 11/Science/Chemistry CBSE/Class 11/Science/Chemistry/Unit 1-Basic Concepts of Chemistry

Calculate the molarity of a solution of ethanol in water in which the mole fraction of ethanol is 0.040. read more
Calculate the molarity of a solution of ethanol in water in which the mole fraction of ethanol is 0.040. read less

Purnima

Chemistry Expert

a /m.mass*1000/v = M.mass of ethanol - 46 Molarity =0.008
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